I have a small part of the code. I have to get the data using ajax but I am getting only one field.
There is no issue with the value and I am getting the correct one. I have to send the result to ajax but I am getting only one field.
I believe there is some issue with my array.
$result=[];
if ($haschange['fb']==1) {
$result[]="<input type='text' value='".$social_links['fb']."'>";
}
if ($haschange['twitter']==1) {
$result[]="<input type='text' value='".$social_links['twitter']."'>";
}
if ($haschange['linkedin']==1) {
$result[]="<input type='text' value='".$social_links['linkedin']."'>";
}
if ($haschange['instagram']==1) {
$result[]="<input type='text' value='".$social_links['instagram']."'>";
}
echo json_encode($result);
exit();
script
<script type="text/javascript">
$(document).on('click', '.pendingContent', function(){
var id=$(this).data("id");
//alert(id);
$.ajax({
url: 'process.php',
method:'post',
dataType: "json",
data:{action:"pendingContent",id:id},
success: function(data){
$('#shaedcontent').html(data);
$("#pendingContent").modal('show');
}
});
});
</script>
Your and other comments basically already described it. If we assume that $haschange has different values, your array should be okay. If you are not sure, just check the return of that function inside your browser within the developer tools.
As we should have an array posted to the ajax function, you should have an array. Your access on the array is not correct as you just add the array (json string) to the html element.
The best approach is to use a foreach loop to go through each object within the json response. If you are not sure what you have received in the ajax method, just use console.log(data). With this you should see a proper json object.
Related
Trying to send a post request from ajax to php.
I did many trial and errors based from the answers including making sure that the "type" is set to post, specifying "dataType", correct "url". I think I miss something important but I can't figure out what it is.
main.php
<script>
$(document).ready(function(){
$(".editContact").on("click", function(){
let dataID = $(this).attr("data-id");
console.log(dataID);
$.ajax({
type: 'POST',
url: 'functions/phonebook.php',
dataType: "text",
data:{data:dataID}
});
});
});
</script>
functions/phonebook.php
if(isset($_POST["data"])){
$res = array($data=>var_dump($_POST["data"]));
}
else{
$res ='null';
}
Then print the $res variable containing the dataID from ajax to my html element in main.php
<label class="m-label-floating">Contact name <?php echo $res; ?> </label>
The console.log in my main.php prints the data what I want to send in ajax but when I try to send the dataID to my phonebook.php, I get a null value.
Your problem is here:
$res = array($data=>var_dump($_POST["data"]));
You are using var_dump the wrong way.
From the docs:
This function displays structured information about one or more expressions that includes its type and value. Arrays and objects are explored recursively with values indented to show structure.
This function does not return any value, so, in your case, $data=>var_dump($_POST["data"]) will always be null.
What you need to is:
$res = array($data => $_POST["data"]);
If you are sending data to a different page altogether and need to use jquery / JS to do it, it might be simpler to send via window replace:
window.location.replace(...)
If you need to stay on the same page, you might want to include a success function in your ajax query, as this will return to the page you are calling from:
$.ajax({
type: 'POST',
url: 'functions/phonebook.php',
data:{data:dataID},
success: function (html) {
// do your HTML replace / add stuff here
},
});
I have a form with several identical fields:
<input type="text" id="qte" value="" name="qte[]">
How transmetre the array in my file processing?
I noticed that the array sent ajax became a string.
$("#form_commande").submit(function(event){
var qte = $("#qte").val();
if(qte== '')
{
$('#qte_message').html("KO QTE");
}
else
{
$.ajax({
type : "POST",
url: $(this).attr('action'),
data: $(this).serialize(),
success : function(){
$('#form_commande').html('<p>OK</p>');
},
error: function(){
$('#form_commande').html("<p>KO</p>");
}
});
}
return false;
}
Get value in jquery like:
$("#form_commande").submit(function(event){
var qte_array = new Array();
$('input[name="qte[]"]').each(function(){
qte_array.push($(this).val());
});
if(qte_array.length== 0)
{
$('#qte_message').html("KO QTE");
}
else
{
$.ajax({
type : "POST",
url: $(this).attr('action'),
data: {qte:qte_array},
success : function(){
$('#form_commande').html('<p>OK</p>');
},
error: function(){
$('#form_commande').html("<p>KO</p>");
}
});
}
});
and get it in php like:
$qte = $_POST["qte"];
here qte an array
This returns the input textbox object:
$("#qte");
This returns the value of the input textbox object:
$("#qte").val();
Remember you asked for DOM object by id, and this by definition returns only one.
Please read this topic:
JQuery - Reading an array of form values and displaying it?
In short you should iterate with tag name="qte[]" instead of using ids. In DOM you cannot have two different objects with different ids.
var qte_array = new Array();
$('input[name="qte[]"]').each(function(){
qte_array.push($(this).val());
});
After this you have all the values of qte[] array in one object - qte_array. You can later serialize this array to JSON and then pass it as a string.
ALTHOUGH - you shouldn't need to do all those things. You can send ajax request directly with your form, all those data in these inputs will be transferred anyway. You just need to handle them correctly server-side.
id is unique, you can't have more fields with the same ID.
By the way you should convert values to JSON and pass them to Ajax
I want to manipulate a PHParray in javascript. This is the code i'm using.
Array.php
<?php
$sentido[1]="ver";
$sentido[2]="tocar";
$sentido[3]="oir";
$sentido[4]="gustar";
$sentido[5]="oler";
?>
fx_funciones.js
/*Pre-sentences*/
var js_array=new Array();
$.ajax({
type: "POST",
url: "array.php",
success: function(response) {
js_array=response
}
});
This is what I want to do but it's not working.
I think , the answer for above question is already addressed in below link. please check them out.
Get data from php array - AJAX - jQuery
I hope it will help you
Try this:
<?php
$sentido[1]="ver";
$sentido[2]="tocar";
$sentido[3]="oir";
$sentido[4]="gustar";
$sentido[5]="oler";
echo json_encode($sentido);
And:
$.getJSON('array.php', function(sentido) {
console.log(sentido);
});
You'll need to return the array from your PHP code as JSON, using the json_encode function. Then, in your jQuery code, specify a json dataType so that it's implicitly converted and passed to the callback function as an array:
var js_array=new Array();
$.ajax({
type: "POST",
url: "array.php",
success: function(response) {
js_array=response
},
dataType: 'json'
});
Use the standard JSON notation. It serializes objects and arrays. Then print it, fetch it on the client and parse it.
On the server:
echo json_encode($sentido);
For more on PHP's json_encode: http://php.net/manual/de/function.json-encode.php
On the client, this is specially easy if you use the jQuery function for ajax that expect JSON-encoded objects, and parses them for you:
$.getJSON('address/to/your/php/file.php', function(sentidos) {
alert(sentidos[0]); // It will alert "ver"
alert(sentidos[1]); // It will alert "tocar"
});
It uses GET but this most probably what you need.
For more on jQuery's $.getJSON: http://api.jquery.com/jQuery.getJSON/
I have a PHP page that uses a jQuery ajax call.
After I execute my AJAX and return a value on success, I need to use this value to pull an item from a PHP array, stored in session and update my SPAN with the new set.
Here's what I've got so far. I tested and I do return correct data value. I guess my syntax in jQuery is off, because my original span fades out, but nothing comes back.
JS:
$.ajax({
...
},
success: function(data){
var nextItem = <?php echo $_SESSION['items'][data]->desc; ?>
$('.x').fadeOut();
$('.x').attr(id, data);
$('.x').text(nextItem).fadeIn();
});
HTML:
<span id="'.$_SESSION['items'][0]->id.'" class="x">'.$_SESSION['items'][0]->desc.'</span>
You should return the session variable in the AJAX call. Execute the PHP code to get the session variable on the URL your AJAX call is hitting. The response of the AJAX call (in this case the 'data' variable in your success function) will be the result of:
<?php echo $_SESSION['items'][data]->desc; ?>
So no PHP code will be in your JS.
If you need to return multiple values, then you might consider using JSON. Your AJAX processing page might be like:
$result = array('id' => $id, 'session' => $_SESSION['items'][$id]->desc);
echo json_encode($result);
Your JS might look like this:
$("#getJSON").click(function() {
$.ajax({
...
success: function(data) {
$obj = $.parseJSON(data);
console.log($obj[0].id, $obj[0].session);
}
});
});
I am using jQuery, AJAX and PHP to update the contents of a drop down box on an event. My code currently triggers the event and uses AJAX to call a PHP function which goes to the database and gets the records associated with each member of the drop down.
I can currently return this 2-dimensional array (an array of records with an array of columns in each one) back to my jQuery function but I am at a loss as to how to convert the array into something which I can use.
jQuery code to call AJAX:
var element= $('select[name=elementName]');
var data = 'inData=' + element.val();
// Call AJAX to get the info we need to fill the drop downs by passing in the new ID
$.ajax(
{
type: "POST",
url: "ops.php",
data: "op=getInfo&" + data,
success:
function(outData)
{
// WHAT DO I DO HERE TO CONVERT 'outData' INTO A 2-DIMENSIONAL jQUERY ARRAY??
},
error:
function()
{
}
});
PHP code:
$sqlResults= mysql_query("SELECT data FROM table WHERE id='".$_POST['inData']."'");
$outData = array();
// Fill the data array with the results
while ($outData[]= mysql_fetch_array($sqlResults));
// echo the data to return it for use in the jQuery file
echo $outData;
The code posted is working fine - I just don't know how to read 'outData' in jQuery.
Thanks in advance for any help!!
Have you looked at json_encode?
echo json_encode($outData);
This will convert it into a json object that can be read by jQuery.
your looking for json
//php
echo json_encode($outData);
//javascript
$.ajax({
type: "POST",
url: "ops.php",
data: "op=getInfo&" + data,
dataType: "json",
success: function(outData) {
console.log(outData); //this will be an object just like
//your php associative array
},
error: function() {
}
});
JSON can do the trick, but why not look at it from another angle?
If you're pinging PHP to get updated info, just have PHP output the option values you want in your select box. Then use the HTML return of jQuery AJAX to .html() the result into your select element.
There's a couple of different ways to skin a cat, and I would submit that this much easier approach is going to gain you extra time to do more jQuery wizardry.
jQuery can not read the echo of a PHP array. Use json_encode before you output it:
echo json_encode($outData);
That's a format jQuery actually can parse as the response.