How to create recursive array from the loop PHP? [closed] - php

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I have an array like below and its dynamic array.
$array = [10,20,30,40,50];
I want to create an another array recursively using the above array values. Looks like below
Array
(
[10] => Array
(
[20] => Array
(
[30] => Array
(
[40] => Array
(
[50] => Array
(
[label] => LABEL
)
)
)
)
)
)
Can anyone help / assist for the above query?
Your help very much appreciated.
Thanks in advance.

It's just a loop, not recursive. If it was recursive you'd need 2 functions or call the same function from within itself. This looks a bit like that, but it's just a loop.
Iterate through each number and create a new array using the number as the key and the accumulating array as the value. Doing it this way means that the first item in the original array will be the deepest item in the finished array, so array_reverse is needed to get it the way you described.
$array = [10,20,30,40,50];
$newarray=[];
foreach (array_reverse($array) as $number) $newarray = [$number => $newarray];
print_r($newarray);
https://www.tehplayground.com/bya12n5tV0jjcAvA

<?php
$array = [10, 20, 30, 40, 50];
$matrix = []; // Final result.
$pointer = &$matrix; // Reference of deepest array.
foreach ($array as $item) {
$pointer[$item] = []; // Create a deeper array.
$pointer = &$pointer[$item]; // Move the reference to the deeper array.
}
$pointer['label'] = "LABEL";
// Print result.
print(json_encode($matrix, JSON_PRETTY_PRINT));
Output
{
"10": {
"20": {
"30": {
"40": {
"50": {
"label": "LABEL"
}
}
}
}
}
}

Related

Add one more element to array in loop with PHP [closed]

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I have array like below:
$arr=[["id"=>"001","name"=>"Hello","pict"=>"hello.jpg"],["id"=>"002","name"=>"Abc","pict"=>"abc.jpg"]];
i want to add one more element to array $arr by "link"=>"uploads/hello.jpg"
My expected result:
$arr=[["id"=>"001","name"=>"Hello","pict"=>"hello.jpg","link"=>"uploads/hello.jpg"],["id"=>"002","name"=>"Abc","pict"=>"abc.jpg","link"=>"uploads/abc.jpg"]];
Any solution for this thank.
You can iterate over the array using foreach, passing a reference into the loop to allow the values to be modified directly:
$arr=[["id"=>"001","name"=>"Hello","pict"=>"hello.jpg"],["id"=>"002","name"=>"Abc","pict"=>"abc.jpg"]];
foreach ($arr as &$a) {
$a['link'] = 'uploads/' . $a['pict'];
}
print_r($arr);
Output:
Array
(
[0] => Array
(
[id] => 001
[name] => Hello
[pict] => hello.jpg
[link] => uploads/hello.jpg
)
[1] => Array
(
[id] => 002
[name] => Abc
[pict] => abc.jpg
[link] => uploads/abc.jpg
)
)
Demo on 3v4l.org
You can iterate over each element in the array and set it that way.
for ($i = 0; $i < count($arr); i++) {
$arr[$i]['link'] = 'uploads/'.$arr[$i]['pict'];
}
foreach($arr as $key => $value){
$arr[$key]['link'] = "uploads/".$value['pict'];
}
Use the foreach loop to modify the original array. The $key value is used to refer to each index in the array.

foreach value with key outside foreach [closed]

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I have a few foreaches which show a total of some numbers.
One of them is this one:
foreach ($lijst['palen'] as $key => $valuepalen)
{
echo $valuepalen ."x Bekaclip palen (48mm / lengte " . $??? . " cm" . "\n";
}
And then there is this one which contains the values I need:
foreach ($optellen as $key => $hoogtevalue)
{
}
The values I need is $hoogtevalue which contains 100 and 110.
But if I insert $hoogtevalue in $??? it only shows the last submitted number 110.
I want to show it like this:
......... lengte is 100
......... lengte is 110
It seems to me that you are trying to map the values from one array to the other, by the position that they sit in the array, rather than by their existing key.
You could use array_map with null as the first parameter to create a new array that consists of pairs from each. (I've added a print_r of the mapped array below to demonstrate the data structure.)
You can then just loop through the pairs.
<?php
$one = [ 63 => 2, 123 => 2];
$two = [ 1 => 100, 3 => 110];
$pairs = array_map(null, $one, $two);
print_r($pairs);
foreach($pairs as $pair)
printf("%d = %d\n", $pair[0], $pair[1]);
Output:
Array
(
[0] => Array
(
[0] => 2
[1] => 100
)
[1] => Array
(
[0] => 2
[1] => 110
)
)
2 = 100
2 = 110
Alternatively you could use the array_values function on both arrays to re-index them and then use keys for association.
This will handle it:
foreach ($lijst['palen'] as $valuepalen) {
foreach ($optellen as $hoogtevalue) {
echo $valuepalen."x Bekaclip palen (48mm / lengte ".$hoogtevalue".cm \n";
}
}

Make array depth from basic array [closed]

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I confused how to make depth from basic array.
$array = array('736', '827', '831');
With foreach loop, I want final result like this:
Array
(
[736] => Array
(
[827] => Array
(
[831] => Array
(
)
)
)
)
Just like you want them, do this:
array
(
736 => array
(
827 => array
(
831 => array
(
)
)
)
)
or did I misunderstand the question?
using a foreach backwards:
$arr=array(831,827,736);
$newref=array();
foreach($arr as $el)
{
$newref=array($el=>$newref);
}
for reversing an array: $arr=array_reverse($arr);
Possibly not the most efficient, but something like this should do it.
function nestedArray($array) {
$newArray = [];
$pointer = &$newArray;
foreach($array as $value) {
$pointer[$value] = [];
$pointer = &$pointer[$value];
}
return $newArray;
}
$arr = [736, 827, 831];
var_dump(nestedArray($arr));

Efficient way of traversing a complicated Array [closed]

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I have a database table that would return an array something like this
$roles['admin'] = 'app1,app2,app3';
$roles['moderator'] = 'app2,app3';
Now I want to traverse this array to show in my view, But instead of showing all apps inside each role, i would like to show all roles inside each app.
So ideally i would like the above array to become this
$apps['app1'] = 'admin';
$apps['app2'] = 'admin,moderator';
$apps['app3'] = 'admin,moderator';
I have been trying to solve this for 2 hours now, but for some reason I can't find an efficient way of doing this.
The following will traverse your array and load it into the appropriate array. It works by going through each part of the array and traversing it.
<?php
$apps = array();
foreach($roles as $key1 => $value1){
$parts = explode(',', $value1);
foreach($parts as $key2 => $value2){
$apps[$value2] .= (strlen($apps[$value2])>0)?",":"").$key1;
}
}
?>
You can map one array to the other by using array_reduce, array_keys and explode to turn your CSV values into arrays
$apps = array_reduce(array_keys($roles), function($apps, $key) use ($roles) {
foreach (explode(',', $roles[$key]) as $app) $apps[$app][] = $key;
return $apps;
}, []);
Note that the result is slightly different to what you wanted in that the values are themselves arrays instead of comma separated strings.
Array
(
[app1] => Array
(
[0] => admin
)
[app2] => Array
(
[0] => admin
[1] => moderator
)
[app3] => Array
(
[0] => admin
[1] => moderator
)
)
If you really need CSV values, add this
$apps = array_map(function($list) {
return implode(',', $list);
}, $apps);
which produces
Array
(
[app1] => admin
[app2] => admin,moderator
[app3] => admin,moderator
)

Combining two PHP arrays with some conditional addition thrown in [closed]

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I've got an unusual problem, but I'm fairly certain it's not impossible to solve.
Consider the two arrays below.
Array ( [0] => 1 [1] => 2 [2] => 2 )
Array ( [0] => 879 [1] => 482 [2] => 1616 )
I need to add the values in second array where the values in the first array are the same so that I would end up with...
Array ( [0] => 879 [1] => 2098 )
How might this be accomplished? Thanks in advance!
This isn't a full-proof way of completing this task, but it achieves the goal you desire. What's happening here is we're looping through your first array (the keys) and using the set values of these keys to add the values from the second array:
$new = array();
foreach($keys as $i => $key) {
if(!isset($new[$key])) { $new[$key] = 0; }
$new[$key] += $vals[$i];
}
Example/Demo
Notes
$keys being your first array: $keys = array(1, 2, 2);
$vals being your second array: array (879, 482, 1616);
As I stated, this isn't full-proof. You will need to modify it to ensure integrity, but it is a start that shows the flow of how you can go about doing what you require.

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