For loop leaves blank td in a table - php

Question

I am calling a for loop to get data from database with this code which is working fine but only with one problem
<table class="table" style="color:#000 !important;">
<tbody>
<tr>
<th>Question</th>
<th>User Answer</th>
</tr>
<tr>
</<?php
for ($x = 0; $x <= 30; $x++) {
?> <td><?= $info['ans_' . $x]; ?></td>
</tr>
<tr>
<?php
$sales_quiz = mysqli_query($conn_quiz, "SELECT * FROM `sales_quiz` where `que_no` = '$x'");
$sales_que = mysqli_fetch_array($sales_quiz); ?>
<td><?= $sales_que['que']; ?></td>
<?php }; ?>
</tr>
</tbody>
</table>
The result is first td of 2nd data which is que is blank and for loop start counting it from 2nd row
I do create a separate for loop for question and answer but then the table becomes broken.

Answer 1

If you need new rows in a table for every loop then you need to add the tr within the loop.
Also all tds that need to be on the same row has to be within one tr.
So remove the extra <tr> and bring them inside the loop.
<table class="table"
style="color:#000 !important;">
<tbody>
<tr>
<th>Question</th>
<th>User Answer</th>
</tr>
<?php
for ($x = 0; $x <= 30; $x++) {
?>
<tr>
<td><?= $info['ans_' . $x]; ?></td>
<!-- </tr> Remove these-->
<!-- <tr>-->
<?php
$sales_quiz = mysqli_query($conn_quiz, "SELECT * FROM `sales_quiz` where `que_no` = '$x'");
$sales_que = mysqli_fetch_array($sales_quiz);
?>
<td><?= $sales_que['que']; ?></td>
</tr>
<?php
} # the semi-colon (;) at the end is unnecessary
?>
</tbody>
</table>

Answer 2

You need to move your </tr><tr> to after the last td, and probably swap your $info['ans_'.$x]; and $sales_que['que']; since it seems like it should go question then answer, and the variable names make me think you are doing answer then question.
<table class="table" style="color:#000 !important;">
<tbody>
<tr>
<th>Question</th>
<th>User Answer</th>
</tr>
<tr>
<?php
for ($x = 0; $x <= 30; $x++) {
?> <td><?= $sales_que['que']; ?></td>
<?php
$sales_quiz = mysqli_query($conn_quiz, "SELECT * FROM `sales_quiz` where `que_no` = '$x'");
$sales_que = mysqli_fetch_array($sales_quiz); ?>
<td><?= $info['ans_'.$x]; ?></td>
</tr>
<tr>
<?php }; ?>
</tr>
</tbody>
</table>

Answer 3

I think it might be the "</" in the 10th line of your code, before the first <?php . There is any reason for that "</" to be there? From my perspective that creates a empty <tr></tr> on the resultant html file, and thats why you have that empty cell on your table. I might be wrong, just check it out and tell me if it works.