How to find if dates not found in table - php

Question

$gno = head::select('point','DATE')
->where('DATE', '>', Carbon::now()->subDays(7))
->orderBy('DATE','desc')
->get();
This code I have used to get past seven days of records from current date but if the date is not found in the table I want to return 0.
I don't know how to achieve this, any help?

Answer 1

You can change your query to use exists.
$gno = head::select('point','DATE')
->where('DATE', '>', Carbon::now()->subDays(7))
->orderByDesc('DATE')
->exists();
This way you get either true or false.
If you want to get the records and return them if found or return 0 if there are none, you have to do this:
$gno = head::select('point','DATE')
->where('DATE', '>', Carbon::now()->subDays(7))
->orderByDesc('DATE')
->get();
return $gno->isNotEmpty() ? $gno : 0;

Answer 2

You need to generate each date in PHP and then go through it and get all items for that date:
$gno = head::select('point','DATE')
->where('DATE', '>', Carbon::now()->subDays(7))
->orderBy('DATE','desc')
->get();
$dates = collect(range(0,7))->mapWithKeys(function ($i) use ($gno) {
$date = Carbon::now()->subDays($i);
return [ $date->toDateString() => $gno->filter(function ($head) use ($date) {
return $date->isSameDay($head->DATE);
}) ];
});
This should return a collection with dates as keys and a collection of rows as values with the collection being empty if there are no items for that date.