How can I skip multiple strings from php array? - php

Question

I have the categories: 2D, 3D, Photo, Animation, which become buttons.
How can I skip the 3D and Animation from being displayed? on this particular page when running foreach. For example, the buttons that will appear have to be: All, 2D, Photo.
I tried to find a solution, but no luck.
What I managed to remove was only a string, but not multiple ones, with:
$key = array_search('3D',$terms);
unset($terms[$key]);
This is my code that I want to apply the changes to:
$terms = get_terms("portfolio_category",$cat_arguments);
if($terms):
?> <!-- category menu, this -->
<div class="row categories-p">
<ul class="col-sm-12">
<li><?php _e("All","um_lang"); ?></li>
<?php
sort($terms);
foreach($terms as $term):?>
<li>
<?php echo $term->name; ?></li>
<?php endforeach; ?>
</ul>
</div>
<?php endif; ?>

Answer 1

You can use php's in_array, here's a basic example:
Assuming you have the following:
$categories = ['2D', '3D', 'Photo', 'Animation'];
And your skip list looks like this:
$skipList = ['3D', 'Animation'];
Then your render function will look like this:
iterate over category list
if the item is not in the skip list, render
foreach ($categories as $category) {
if (!in_array($category, $skipList)) {
// Display the category button
// e.g. echo "<button>{$category}</button>";
}
}