I got a date with format 'Y-m-d', and want to get the day from it. Like if I have 2021.01.01, I want for example Friday, or Thursday depending on what day it actually is. I already got the date stored as $date and I want the day stored as $day.
I've already tried this, without any error, and without anything happening:
$day = Carbon::createFromFormat('Y-m-d', $date)->format('1');
var_dump($day);
I've found another solution for you :
$timestamp = strtotime('2009-10-22');
$day = date('l', $timestamp);
echo $days;
output:
Thursday
You can try this ,
$d=unixtojd(mktime(0,0,0,6,20,2007));
var_dump(cal_from_jd($d,CAL_GREGORIAN));
output :
array (size=9)
'date' => string '6/20/2007' (length=9)
'month' => int 6
'day' => int 20
'year' => int 2007
'dow' => int 3
'abbrevdayname' => string 'Wed' (length=3)
'dayname' => string 'Wednesday' (length=9)
'abbrevmonth' => string 'Jun' (length=3)
'monthname' => string 'June' (length=4)
And for your code , you just need to add your date like this
$d=unixtojd(mktime(0,0,0,month,days,year));
$calendar = cal_from_jd($d,CAL_GREGORIAN);
var_dump($calendar['dayname']);
It seems like you used a 1 (one) instead of an l (lowercase L). If you change that, it works fine.
$day = Carbon::createFromFormat('Y-m-d', $date)->format('l');
var_dump($day);
This works, you seem to be using 1 instead of l
$today = Carbon::now();
$dayName = $today->format('l');
When using Carbon, ->dayName is the obvious and more explicit way:
Carbon::createFromFormat('Y-m-d', $date)->dayName
It also allow you to have it in any language:
Carbon::createFromFormat('Y-m-d', $date)->locale('fr_FR')->dayName
Related
I want to display the start date and end date of the week. I have One date and a string like 1W4 and,in 1W4 consider 4 weeks and 1 visit so, my string like this 2W4,1W2,3W3,1W1,2W4.
I want to make start date and end date of week array according to string and week start from Sunday to Saturday.
Please post me if anyone has solution.Please ignoring if mistake in asking Question.
Thank you.
Try my php code:
From php.net datetime.format:
W: ISO-8601 week number of year, weeks starting on Monday.
The first calendar week of a year is that one which includes the first Thursday of that year.
So I have to rest one day to the start week date.
I assumed that the weeks correspond to the current year.
Input string:
$weeksString = "2W4,1W2,3W3,1W1,2W4";
Code:
<?php
$weeksArray = explode(",", $weeksString);
$result = array();
foreach($weeksArray as $visitsWeek) {
list($visits, $week) = explode("W", $visitsWeek);
$startDate = date("Y-m-d", strtotime(date("Y") . "W" . str_pad($week, 2, "0", STR_PAD_LEFT) . " -1 days"));
$endDate = date("Y-m-d", strtotime($startDate . " +6 days"));
$result[] = array("week" => $week, "startDate" => $startDate, "endDate" => $endDate);
}
?>
Output array $result:
array ( 0 => array ( 'week' => '4', 'startDate' => '2021-01-24', 'endDate' => '2021-01-30', ), 1 => array ( 'week' => '2', 'startDate' => '2021-01-10', 'endDate' => '2021-01-16', ), 2 => array ( 'week' => '3', 'startDate' => '2021-01-17', 'endDate' => '2021-01-23', ), 3 => array ( 'week' => '1', 'startDate' => '2021-01-03', 'endDate' => '2021-01-09', ), 4 => array ( 'week' => '4', 'startDate' => '2021-01-24', 'endDate' => '2021-01-30', ), )
This question already has answers here:
Convert day of the year to datetime in php
(2 answers)
Closed 2 years ago.
I'm trying to convert day of year into date.
So no problem i use DateTime::createFromFormat with z and Y.
DateTime::createFromFormat('z Y', '199 2020');
/*RESULT*/
object(DateTime)[3]
public 'date' => string '2020-07-19 12:45:24.000000' (length=26)
public 'timezone_type' => int 3
public 'timezone' => string 'Europe/Paris' (length=12)
But when i test the result i get the wrong day of year...
date('z Y', strtotime('2020-07-19'));
/*RESULT*/
'198 2020' (length=8)
So i trying this
DateTime::createFromFormat('z Y', date('z Y', strtotime('2020-07-19')));
/*RESULT*/
object(DateTime)[3]
public 'date' => string '2020-07-20 12:52:10.000000' (length=26)
public 'timezone_type' => int 3
public 'timezone' => string 'Europe/Paris' (length=12)
if i check day of year 199 of 2020 on this website: https://www.calendrier.best/numero-de-jour-2020.html
I get 2020-07-17
What i'm doing wrong ??
If you know the year, you can use something like this. Outputs:
string(10) "2020-07-17"
Code:
<?php
$dayOfYearNumber = 199;
$year = 2020;
// Add day of year number to the first day of the year, substracting 1 because Jan 1st will be the first day.
$date = (new DateTime("$year-1-1"))->add(new DateInterval('P' . $dayOfYearNumber - 1 . 'D'));
var_dump($date->format('Y-m-d')); // string(10) "2020-07-17"
PHP only detects some standards like you can see here https://www.php.net/manual/de/datetime.formats.date.php
In Your first example you defined your format but strtotime() has no such parameter
If you have these values as variable you could use mktime() instead https://www.php.net/manual/de/function.mktime
But I recommend to always give PHP a month e.x. January
i am trying to figure out how to get total Months in between two overlapping date Ranges.
e-g
Date Range from Date-A to Date-B overlapping the Date range of Date-X and Date-Y.
_ Start|Jan - Feb - March - April ------ Nov - Dec|End (DateRange A)
Start|Jan - Feb ---- Dec - Jan - Feb|End _
In two date ranges the Jan and Feb Months are colliding. Means Total of 2 Months are there.
So i want these two months in my array so i can apply different functions on it.
e-g i have these two dates
$dateRange1Start = "2015-07-01";
$dateRange1End = "2014-06-30";
=-=-=-=====-=-==
$dateRange2Start = "2012-02-01";
$dateRange2End = "2014-12-31";
There are total 6 Months in colliding between these two date ranges. i want to get these 6 Months.
I tried to search for help in google, but mostly i get less than or greater than signs. but specifically like this. I tried to implement my own logic but its not getting me anywhere, sadly to only more problems :(
i am trying to get results like this
$collidingDates = array("2014-07","2014-08","2014-09","2014-10","2014-11","2014-12");
Any help would be appreciated. :)
=-=-=-=-=-=-=-==-=-=-=-=-=-=-=-=--=-=
UPDATE:
Here is what i have done so far, yes getting some code from here and there. and tweaking it a bit up to fulfill my requirements.
//Getting all Months from First Date Range
$start = (new DateTime('2014-06-01'))->modify('first day of this month');
$end = (new DateTime('2015-05-06'))->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$firstPeriod = new DatePeriod($start, $interval, $end);
//Getting all Months from Second Date Range.
$start = (new DateTime('2012-02-01'))->modify('first day of this month');
$end = (new DateTime('2014-12-31'))->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$secondPeriod = new DatePeriod($start, $interval, $end);
$collidingDates = array();
foreach ($firstPeriod as $f_dt) {
foreach($secondPeriod as $s_dt){
if($f_dt->format("Y-m") === $s_dt->format("Y-m")){
array_push($collidingDates,$f_dt->format("Y-m"));
}
}
}
echo "<pre>";
print_r($collidingDates);
i got this output.
Array
(
[0] => 2014-06
[1] => 2014-07
[2] => 2014-08
[3] => 2014-09
[4] => 2014-10
[5] => 2014-11
[6] => 2014-12
)
But i think i am getting 1 extra month
2014-06, not sure how O_o??
This is a two step process. First you need to establish the narrowest date range from the start and end dates. Then list the months between those dates.
// An array of start and end dates. There are just 2 in this example but you
// could have as many as you like in the same "start, then end" format.
$ranges = [
[new DateTime('2014-07-01'), new DateTime('2015-06-30')],
[new DateTime('2012-02-01'), new DateTime('2014-12-31')]
];
// Reduce the ranges to one set of two dates, the latest of the start dates
// and the earliest of the end dates.
$range = array_reduce($ranges, function($carry, $item){
return $carry
? [max($carry[0], $item[0]), min($carry[1], $item[1])]
: $item;
});
var_dump($range);
/*
array (size=2)
0 =>
object(DateTime)[1]
public 'date' => string '2014-07-01 00:00:00.000000' (length=26)
public 'timezone_type' => int 3
public 'timezone' => string 'Europe/London' (length=13)
1 =>
object(DateTime)[4]
public 'date' => string '2014-12-31 00:00:00.000000' (length=26)
public 'timezone_type' => int 3
public 'timezone' => string 'Europe/London' (length=13)
*/
// Shift both dates to the first of the month. Strictly speaking, we only
// need to do this with the start date.
$range = array_map(function($date){
return $date->modify("first day of this month");
}, $range);
var_dump($range);
/*
array (size=2)
0 =>
object(DateTime)[1]
public 'date' => string '2014-07-01 00:00:00.000000' (length=26)
public 'timezone_type' => int 3
public 'timezone' => string 'Europe/London' (length=13)
1 =>
object(DateTime)[4]
public 'date' => string '2014-12-01 00:00:00.000000' (length=26)
public 'timezone_type' => int 3
public 'timezone' => string 'Europe/London' (length=13)
*/
$months = [];
$interval = new DateInterval("P1M");
for ($month = $range[0]; $month <= $range[1]; $month->add($interval)) {
$months[] = $month->format("Y-m");
}
var_dump($months);
/*
array (size=6)
0 => string '2014-07' (length=7)
1 => string '2014-08' (length=7)
2 => string '2014-09' (length=7)
3 => string '2014-10' (length=7)
4 => string '2014-11' (length=7)
5 => string '2014-12' (length=7)
*/
I think you are looking for this:
$start = (
new DateTime('2015-12-02'))
->modify('first day of this month');
$end = (new DateTime('2016-05-06'))->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
I looked at this answer already, and it's quite close to what I have.
Here is my PHP code:
$start = new DateTime('0:00 first day of previous month', new DateTimeZone('UTC'));
/*
if (isset($_GET['year']) && isset($_GET['month']) && checkdate($_GET['month'], 1, $_GET['year'])) {
$start = DateTime::createFromFormat('Y-m-d', $_GET['year'] . '-' . $_GET['month'] . '-1');
}*/
$middle = DateTime::createFromFormat('U', strtotime('first day of last month', $start->format('U')));
$middle->setTimezone(new DateTimeZone('UTC'));
$end = DateTime::createFromFormat('U', strtotime('first day of 2 months ago', $start->format('U')));
$end->setTimezone(new DateTimeZone('UTC'));
var_dump($start);
var_dump($middle);
var_dump($end);
Today is August 27th, so I would expect July 1, June 1, and May 1. Here's what the actual output is:
object(DateTime)[1]
public 'date' => string '2013-07-01 00:00:00' (length=19)
public 'timezone_type' => int 3
public 'timezone' => string 'UTC' (length=3)
object(DateTime)[2]
public 'date' => string '2013-05-02 00:00:00' (length=19)
public 'timezone_type' => int 3
public 'timezone' => string 'UTC' (length=3)
object(DateTime)[3]
public 'date' => string '2013-04-02 00:00:00' (length=19)
public 'timezone_type' => int 3
public 'timezone' => string 'UTC' (length=3)
Why is it returning the second day of the months for me?
I've also tried it without the new DateTimeZone('GMT') as the second parameter of the constructor for the initial DateTime but it still gives me the same result, just with different times.
this part irrelevant - question was edited
Because of the timezone difference. $start is calculated in the 'Rainy River timezone', while $middle and $end are in UTC time.
The 'Rainy River timezone has a -06:00 hour offset from UTC (exactly the difference in hours between the first with the second and third results).
update 1 - solution
It seems the problem lies somewhere around strtotime. For some reason it yields a result with an offset of one day (further explanation needed). A simple solution, is to subtract one second from that date and it will produce the correct result.
$timezone = new DateTimeZone('UTC');
$start = new DateTime('0:00 first day of previous month', $timezone );
$middle = DateTime::createFromFormat('U', strtotime('first day of last month',($start ->format('U'))-1),$timezone);
echo $middle->format('Y-m-d')."\n";
Result:
2013-05-01
update 2 - reason for problem
Eventually I find out that the problem originates from the instantiation of the fisrt date object. Here is an illustration.
This will give a correct result:
$original = new DateTime('2013-05-01');
echo $original->format('Y-m-d')."\n";
$previous= DateTime::createFromFormat('U', strtotime('first day of last month',($original->format('U'))),new DateTimeZone('UTC'));
echo $previous->format('Y-m-d')."\n";
Result (OK):
2013-05-01
2013-04-01 <--- OK
However, this will not (only first line different, as in the original code):
$original = new DateTime('0:00 first day of previous month', new DateTimeZone('UTC'));
echo $original->format('Y-m-d')."\n";
$previous= DateTime::createFromFormat('U', strtotime('first day of last month',($original->format('U'))),new DateTimeZone('UTC'));
echo $previous->format('Y-m-d')."\n";
Result:
2013-07-01
2013-05-02 <--- BAD
After reading the answer here, I had a better idea:
$start = new DateTime('0:00 first day of previous month');
/*
if (isset($_GET['year']) && isset($_GET['month']) && checkdate($_GET['month'], 1, $_GET['year'])) {
$start = DateTime::createFromFormat('Y-m-d', $_GET['year'] . '-' . $_GET['month'] . '-1');
}*/
$middle = clone $start;
$middle->modify('first day of last month');
$end = clone $start;
$end->modify('first day of 2 months ago');
var_dump($start);
var_dump($middle);
var_dump($end);
Output:
object(DateTime)[1]
public 'date' => string '2013-07-01 00:00:00' (length=19)
public 'timezone_type' => int 3
public 'timezone' => string 'America/Rainy_River' (length=19)
object(DateTime)[2]
public 'date' => string '2013-06-01 00:00:00' (length=19)
public 'timezone_type' => int 3
public 'timezone' => string 'America/Rainy_River' (length=19)
object(DateTime)[3]
public 'date' => string '2013-05-01 00:00:00' (length=19)
public 'timezone_type' => int 3
public 'timezone' => string 'America/Rainy_River' (length=19)
Also, I realize that a DateTimeImmutable would be a better choice for the $start instance (so that I don't have to clone the other two), but I don't have access to PHP 5.5 yet.
>> $start_dt = new DateTime()
DateTime::__set_state(array(
'date' => '2012-04-11 08:34:01',
'timezone_type' => 3,
'timezone' => 'America/Los_Angeles',
))
>> $end_dt = new DateTime()
DateTime::__set_state(array(
'date' => '2012-04-11 08:34:06',
'timezone_type' => 3,
'timezone' => 'America/Los_Angeles',
))
>> $start_dt->setTimestamp(strtotime('31-Jan-2012'))
DateTime::__set_state(array(
'date' => '2012-01-31 00:00:00',
'timezone_type' => 3,
'timezone' => 'America/Los_Angeles',
))
>> $end_dt->setTimestamp(strtotime('1-Mar-2012'))
DateTime::__set_state(array(
'date' => '2012-03-01 00:00:00',
'timezone_type' => 3,
'timezone' => 'America/Los_Angeles',
))
>> $interval = $start_dt->diff($end_dt)
DateInterval::__set_state(array(
'y' => 0,
'm' => 0,
'd' => 30,
'h' => 0,
'i' => 0,
's' => 0,
'invert' => 0,
'days' => 30,
))
>> $interval->format('%mm %dd')
'0m 30d'
i.e., 31-Jan-2012 to 1-Mar-2012 yields less than a month! I'd expect the output to be 1 month, 1 day. It shouldn't matter the number of days in February; that's the point of using a time library -- it's supposed to handle these things. WolframAlpha agrees.
Should I file a bug to PHP? Is there a hack/fix/workaround to get months to work as expected?
Updated answer
This behavior of DateTime::diff is certainly unexpected, but it's not a bug. In a nutshell, diff returns years, months, days etc such that if you did
$end_ts = strtotime('+$y years +$m months +$d days' /* etc */, $start_ts);
you would get back the timestamp that corresponds to end original end date.
These additions are performed "blindly" and then date correction applies (e.g. Jan 31 + 1 month would be Feb 31, corrected to Mar 2 or Mar 3 depending on the year). In this specific example you cannot add even one month as salathe also explains.
Should I file a bug to PHP?
No.
The "month" part of the interval means that the month part of the start date can be incremented by that many months. The behaviour in PHP, taking your start date of 31-Jan-2012 and incrementing the month (literally, 31-Feb-2012) and then correcting for a valid date (PHP does this for you) would give 02-Mar-2012 which is later than the target date that you are working with.
To demonstrate this, take your start date and add n months for a few months to see the behaviour.
31-Jan-2012 (Interval)
02-Mar-2012 (P1M)
31-Mar-2012 (P2M)
01-May-2012 (P3M)
31-May-2012 (P4M)
01-Jul-2012 (P5M)
You can see that the month is being incremented, then adjusted to make a valid date.