Hello so right now I have this data that i retrieved from the database table and the format is ["2021-08-17 23:13:15"] and i wish to change it into something like this 1629243333 (another data) because i want to get the difference in days between both time. I tried using the gettimeStamp() but it doesnt work.
$updateRaw = \DB::table('tickets')
->where('id', $ticket)
->pluck('updated_at');
the $updateRaw is the data with the date format. Any help would be appreciated thanks
With Carbon do like this, if update_at column is not carbon instance;
use Carbon\Carbon;
Carbon::parse($updateRaw[0])->timestamp;
if it is then simply do
$updateRaw[0]->timestamp;
for more : https://carbon.nesbot.com/
A simpler solution would be to use native strtotime() to convert datetime to unix timestamp
$updateRaw = \DB::table('tickets')
->where('id', $ticket)
->value('updated_at'); //use value to get first value directly
$timestamp = strtotime($updateRaw);
Related
I am getting dates from an API call. The date is formatted in this way
2017-10-19T15:30:00
I want to store this date in my MYSQL database using Laravel Database Migration, currently I am using
$table->dateTime('datetime');
When I store it using a dateTime field as above, all I get is
0000-00-00 00:00:00
When I use a timestamp format, I don't get accurate dates, I just get the current time and date.
How can I solve this? Any help would be appreciated, and please let me know if you want further information.
Luckily, Laravel uses the Carbon class, which makes things a lot easier to modify dates. In your case, you want to do this:
Carbon::createFromFormat('Y-m-d\TH:i:s', $date);
There are two ways you can implement it: you can modify it before you save it to your database, or you can add a mutator on your model.
public function setDatetimeAttribute($value)
{
$this->attributes['datetime'] = Carbon::createFromFormat('Y-m-d\TH:i:s', $value);
}
You may want to build in some validation to see which format the date/time is in before you try to convert it.
in the model you should put:
protected $dates = ['datetime'];
Use Carbon
$dt = Carbon::parse('1975-05-21 22:23:00.123456');
to save:
$model = new Model;
$model->date = $dt; // you can use the carbon object directly
$model->save();
This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 12 months ago.
I want to change the date format which is fetched from database.
now I got 2016-10-01{{$user->from_date}} .I want to change the format 'd-m-y' in laravel 5.3
{{ $user->from_date->format('d/m/Y')}}
Try this:
date('d-m-Y', strtotime($user->from_date));
It will convert date into d-m-Y or whatever format you have given.
Note: This solution is a general solution that works for php and any of its frameworks. For a Laravel specific method, try the solution provided by Hamelraj.
In Laravel use Carbon its good
{{ \Carbon\Carbon::parse($user->from_date)->format('d/m/Y')}}
In your Model set:
protected $dates = ['name_field'];
after in your view :
{{ $user->from_date->format('d/m/Y') }}
works
You can check Date Mutators: https://laravel.com/docs/5.3/eloquent-mutators#date-mutators
You need set in your User model column from_date in $dates array and then you can change format in $dateFormat
The another option is also put this method to your User model:
public function getFromDateAttribute($value) {
return \Carbon\Carbon::parse($value)->format('d-m-Y');
}
and then in view if you run {{ $user->from_date }} you will be see format that you want.
There are 3 ways that you can do:
1) Using Laravel Model
$user = \App\User::find(1);
$newDateFormat = $user->created_at->format('d/m/Y');
dd($newDateFormat);
2) Using PHP strtotime
$user = \App\User::find(1);
$newDateFormat2 = date('d/m/Y', strtotime($user->created_at));
dd($newDateFormat2);
3) Using Carbon
$user = \App\User::find(1);
$newDateFormat3 = \Carbon\Carbon::parse($user->created_at)->format('d/m/Y');
dd($newDateFormat3);
Method One:
Using the strtotime() to time is the best format to change the date to the given format.
strtotime() - Parse about any English textual datetime description into a Unix timestamp
The function expects to be given a string containing an English date format and will try to parse that format into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 UTC), relative to the timestamp given in now, or the current time if now is not supplied.
Example:
<?php
$timestamp = strtotime( "February 26, 2007" );
print date('Y-m-d', $timestamp );
?>
Output:
2007-02-26
Method Two:
date_format() - Return a new DateTime object, and then format the date:
<?php
$date=date_create("2013-03-15");
echo date_format($date,"Y/m/d H:i:s");
?>
Output:
2013/03/15 00:00:00
You can use Carbon::createFromTimestamp
BLADE
{{ \Carbon\Carbon::createFromTimestamp(strtotime($user->from_date))->format('d-m-Y')}}
I had a similar problem, I wanted to change the format, but I also wanted the flexibility of being able to change the format in the blade template engine too.
I, therefore, set my model up as the following:
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
\Carbon\Carbon::setToStringFormat('d-m-Y');
class User extends Model
{
protected $dates = [
'from_date',
];
}
The setToStringFormat will set all the dates to use this format for this model.
The advantage of this for me is that I could have the format that I wanted without the mutator, because with the mutator, the attribute is returned as a string meaning that in the blade template I would have to write something like this if I wanted to change the format in the template:
{{ date('Y', strtotime($user->from_date)) }}
Which isn't very clean.
Instead, the attribute is still returned as a Carbon instance, however it is first returned in the desired format.
That means that in the template I could write the following, cleaner, code:
{{ $user->from_date->format('Y') }}
In addition to being able to reformat the Carbon instance, I can also call various Carbon methods on the attribute in the template.
There is probably an oversight to this approach; I'm going to wager it is not a good idea to specify the string format at the top of the model in case it affects other scripts. From what I have seen so far, that has not happened. It has only changed the default Carbon for that model only.
In this instance, it might be a good set the Carbon format back to what it was originally at the bottom of the model script. This is a bodged idea, but it would work for each model to have its own format.
Contrary, if you are having the same format for each model then in your AppServiceProvider instead. That would just keep the code neater and easier to maintain.
I suggest using isoFormat for better appearance on the web pages.
{{ \Carbon\Carbon::parse($blog->created_at)->isoFormat('MMM Do YYYY')}}
The result is
Jan 21st 2021
Carbon Extension
In Laravel 8 you can use the Date Casting: https://laravel.com/docs/8.x/eloquent-mutators#date-casting
In your Model just set:
protected $casts = [
'my_custom_datetime_field' => 'datetime'
];
And then in your blade template you can use the format() method:
{{ $my_custom_datetime_field->format('d. m. Y') }}
In Laravel you can add a function inside app/Helper/helper.php like
function formatDate($date = '', $format = 'Y-m-d'){
if($date == '' || $date == null)
return;
return date($format,strtotime($date));
}
And call this function on any controller like this
$start_date = formatDate($start_date,'Y-m-d');
Hope it helps!
For a more natural date format used everywhere outside of the US, with time that includes hours, minutes and seconds:
07/03/2022 19:00:00
{{ \Carbon\Carbon::parse($transaction->created_at)->format('d/m/Y H:i:s')}}
Or if you'd prefer to use a more natural 12-hour-clock-based time format like this:
07/03/2022 7:00:00 PM
{{ \Carbon\Carbon::parse($transaction->created_at)->format('d/m/Y g:i:s A')}}
Here's the full list of variables available for use in the PHP/Carbon date-time format.
Sometimes changing the date format doesn't work properly, especially in Laravel. So in that case, it's better to use:
$date1 = strtr($_REQUEST['date'], '/', '-');
echo date('Y-m-d', strtotime($date1));
Then you can avoid error like "1970-01-01"!
I have stored the date as a string in my DB in this format (dd-mm-yyyy).
Here I want to check the difference in days between the current date and the date in DB.
Here is my controller code:
public function index()
{
$domain_count = domain_details::get()->count();
//var_dump($domain_data);
$domain_alert = domain_details::
where('domain_ex_date','>',date('j-m-y'))
->get();
return view('home1')->with('domain_count' , $domain_count)
->with('domain_alert' , $domain_alert);
How do I achieve this? Is my approach right?
The above code shows 2016 is greater than 2017. I can see my logic is wrong but how do I change this?
It's better to have your dates in a DATE column in a proper format, otherwise MySQL won't know how to calculate it. Since you don't, you'll have to convert it with str_to_date, passing in the raw command:
where(DB::raw("str_to_date('domain_ex_date','%d-%m-%Y')"),'>',date('Y-m-d'))
I'm inserting date and time data in the database, my datatype is timestamp, I am inserting data using carbon but I always get this output from it '2014-11-25 00:53:48' I always get 00 on the hours, been stuck here for three hours... here is my code
$mydate=Carbon::now();
DB::table('attendances')
->where('user_id', Input::get('empid'))
->update(array('logon' =>$mydate));
try using $mydate->format("H:i")
Carbon defaults to outputting in DateTime format.
Also this looks like a simple use case: You could use DB::raw('NOW()') in place of $mydate if you are using MySQL
DB::table('attendances')
->where('user_id', Input::get('empid'))
->update(array('logon' =>DB::raw('NOW()')));
EDIT:
Also worth noting that Carbon extends php's DateTime. That means all DateTime functionality is still there. It also means your problem could be stemming from a problem with your PHP installation/configuration.
I want to input a timestamp in below format to the database.
yyyy-mm-dd hh:mm:ss
How can I get in above format?
When I use
$date = new Zend_Date();
it returns month dd, yyyy hh:mm:ss PM
I also use a JavaScript calender to insert a selected date and it returns in dd-mm-yyyy format
Now, I want to convert these both format into yyyy-mm-dd hh:mm:ss so can be inserted in database. Because date format not matching the database field format the date is not inserted and only filled with *00-00-00 00:00:00*
Thanks for answer
Not sure if this will help you, but try using:
// to show both date and time,
$date->get('YYYY-MM-dd HH:mm:ss');
// or, to show date only
$date->get('YYYY-MM-dd')
Technically, #stefgosselin gave the correct answer for Zend_Date, but Zend_Date is completely overkill for just getting the current time in a common format. Zend_Date is incredibly slow and cumbersome to use compared to PHP's native date related extensions. If you don't need translation or localisation in your Zend_Date output (and you apparently dont), stay away from it.
Use PHP's native date function for that, e.g.
echo date('Y-m-d H:i:s');
or DateTime procedural API
echo date_format(date_create(), 'Y-m-d H:i:s');
or DateTime Object API
$dateTime = new DateTime;
echo $dateTime->format('Y-m-d H:i:s');
Don't do the common mistake of using each and every component Zend Frameworks offers just because it offers it. There is absolutely no need to do that and in fact, if you can use a native PHP extension to achieve the same result with less or comparable effort, you are better off with the native solution.
Also, if you are going to save a date in your database, did you use any of the DateTime related columns in your database? Assuming you are using MySql, you could use a Timestamp column or an ISO8601 Date column.
This is how i did it:
abstract class App_Model_ModelAbstract extends Zend_Db_Table_Abstract
{
const DATE_FORMAT = 'yyyy-MM-dd';
public static function formatDate($date, $format = App_Model_ModelAbstract::DATE_FORMAT)
{
if (!$date instanceof Zend_Date && Zend_Date::isDate($date)) {
$date = new Zend_Date($date);
}
if ($date instanceof Zend_Date) {
return $date->get($format);
}
return $date;
}
}
this way you don't need to be concerned with whether or not its actually an instance of zend date, you can pass in a string or anything else that is a date.
a simple way to use Zend Date is to make specific function in its business objects that allows to parameter this function the date format. You can find a good example to this address http://www.pylejeune.fr/framework/utiliser-les-date-avec-zend_date/
this is i did it :
Zend_Date::now->toString('dd-MM-yyyy HH:mm:ss')
output from this format is "24-03-2012 13:02:01"
and you can modified your date format
I've always use $date->__toString('YYYY-MM-dd HH-mm-ss'); method in the past but today didn't work. I was getting the default output of 'Nov 1, 2013 12:19:23 PM'
So today I used $date->get('YYYY-MM-dd HH-mm-ss'); as mentioned above. Seems to have solved my problem.
You can find more information on this on output formats here: http://framework.zend.com/manual/1.12/en/zend.date.constants.html