What I need to do is to export as as .csv a list of a lot of different values inside different entities. I need each reference created at a certain date with related values.
What I did was first, find all the objects by date and put them in an array.
$parcelRepo = $this->getDoctrine()->getRepository(Parcel::class);
$dateToday = new \DateTime("now");
$parcels = $parcelRepo->findBy([
'date_add' => $dateToday
]);
Then, in a foreach loop, I find the values that relates to each parcel entity. This is where I have a problem, I don't understand how to access the values which are not located in the same table as my first parcel entity.
I need to not use SQL as well.
Here is the code where I get the "Only variables should be passed by reference" error.
$array = [];
foreach ($parcels as &$p) {
$array.array_push(
$p->getDeliveryOrder()->getProduct()->getAccount()->getCoclico(),
"1",
"",
$p->getDeliveryOrder()->getUser()->getLogin(),
$p->getDeliveryOrder()->getProduct()->getCode(),
$p->getInternalReference(),
$p->getDeliveryOrder()->getProduct()->getCode()+"0"+$p->getNumber(),
"121",
$p->getName(),
$p->getAddress4(),
$p->getAddress1(),
$p->getAddress2(),
$p->getAddress3(),
"téléphone", //TODO
$p->getPostalCode(),
$p->getCity(),
\DateTime::createFromFormat('Ymd',$dateToday),
"",
"",
"0"
);
}
I think I need to use QueryBuilder but was wondering if there was any other way to do what I need since QueryBuilder is close to SQL (from what I understand).
Also, as I need to export each foreach values in one line, I need a multidimensional array. However I did not look into this issue since I can't even get the values I need.
So the issue comes from
$array.array_push(
this code actually merges $array and array_push() returning value, array_push() first parameter should be the array ( which is sent through reference) you want to push in, and because you are actually sending a value and not a variable, this error appears.
Here is the documentation for array_push https://www.php.net/manual/ro/function.array-push.php
so it should actually be
array_push($array, ...);
But as Ricardo left you a comment, this code is not really necessary, you can get the formatted data like this from a query, chaining multiple relation calling like:
$p->getDeliveryOrder()->getProduct()->getAccount()->getCoclico()
is not really desirable, but if you think you can't do that then the fix is just to write array_push correctly.
Related
So i am using this PHP code to create the json output, and I am having an issue where it’s creating an array of array with the info. I would like to get rid of one array and just display the list of API’s thats been used and number that has been used.
Looks as though the difference is you have...
"apis":[{"item_search":"0\n"},{"item_recommended":"0\n"}]
and want
"apis":{"item_search":"0\n","item_recommended":"0\n"}
If this is the case, you need to change the way you build the data from just adding new objects each time to setting the key values directly in the array...
$zone_1 = [];
foreach($zone_1_apis as $api_name ) {
$zone_1[substr($api_name, 0,-5)] = file_get_contents('keys/'.$_GET['key'].'/zone_1/'.$api_name);
}
You also need to do the same for $zone_2 as well.
It may also be good to use trim() round some of the values as they also seem to contain \n characters, so perhaps...
trim(file_get_contents('keys/'.$_GET['key'].'/zone_1/'.$api_name))
Cutting out some of the code on the innermost foreach, I'm trying to change HERE to make it so that it alters the original value. I want to pass a pointer basically and alter it. I was able to kind of do this with the &$ keyword in the foreach but (as the docs state) it results in some buggy behavior and I'm trying to do it the way they, and others on SO suggest. The problem is all the examples I find are for a single foreach, not for nested.
The following code loops properly but when I get to the HERE it doesn't actually alter the original value. Also worth mentioning that $sources could be an array of arrays (by index) or an array of key values. This looping code seems to iterate over both fine though, just not overriding the original value of $sources
fwiw, on top of the &$ I also tried:
$sources[$sourceKey][$rowKey][$cellKey] = $date->format('m/d/Y');
Which $sources[$sourceKey][$rowKey][$cellKey] returns the right value if I print it but it still doesn't overwrite the original array.
function convertDates($sources) {
foreach($sources as $sourceKey => $sourceValue){
foreach ($sourceValue as $rowKey => $rowValue) {
foreach ($rowValue as $cellKey => $cellValue) {
HERE = $date->format('m/d/Y');
}
}
}
}
I never could get this to work correctly since there were two formats this loop could get (JSON encoded object and an array). Making it work for both was much harder than just doing it in JavaScript so instead of modifying on the server I format the data how I want client side and send it up. This formatting is purely presentational and for personal use so if someone were to put in a debugger and change the code to send a different format thats fine and there's no security issues.
So in the end, this code was rewritten in JS and since JS handles arrays and objects using the same pointers the above issue wasn't an issue any longer.
I am trying to merge a static data with json encode array data for output. Here is my php code:
$arr = array();
$rs = mysql_query("SELECT id, name, picture, mail, gender, birthday FROM users WHERE id='$logged_id' ");
while($obj = mysql_fetch_object($rs)) {
$arr[] = $obj;
}
echo '{"users":'.json_encode($arr).'}';
Now I want to merge other data with it:
$user_ip = array("user_ip" => $user_ip_address);
I have tried array_merge($arr, $user_ip). But it didn't work. I think this is not correct json array format if I merge with existing data array. Please let me know what to do how to output other data as well as current data coming from mysql with json encode.
I am getting such output with my existing code, which is correct:
{"users":[{"id":"14","name":"Sonu Roy","picture":"image012.jpg","mail":"myemail#gmail.com","gender":"Male","birthday":"1983-01-11"}]}
But now I want to add other variable e.g $user_ip_address as user's data joining with current output data like this:
{"users":[{"id":"14","name":"Sonu Roy","picture":"image012.jpg","mail":"myemail#gmail.com","gender":"Male","birthday":"1983-01-11",user_ip:"127.0.0.1"}]}.
I want to get it in this way. How to do it? Please let me know. Thanks in advance.
try this:
echo json_encode(array('users' => $arr, 'user_ip' => $user_ip_address));
on a side note:
you should use PHP PDO class to connect and query the database.
mysql_fetch_object returns an object, not an array. So, what are you doing by $arr[] = $obj; is just adding an object into an array. So, the actual structure of the $arr is something like
$arr => [
[0] => Object(....),
[1] => Object(....),
....
]
In your particular case, I assume you are fetching single row by primary key, so there are only one object.
THe simpliest way to fix this is to add a field to an object. I haven't worked with PHP since 5.3, so can't be sure, but it's as simple as adding
$obj->user_ip = $user_ip_address;
inside the loop.
Btw, a couple of questions for you:
Why do you use loop if it should result in a single row?
Why you are embedding the variable directly into SQL query. It's quite vulnerable, read about sql-injections and how to prevent it (one day I was really tired telling people here on SO to use PDO and prepared statements, so just go read about it),
Have you read the documentation about mysql_fetch_object and array_merge? Why not (because if you have read it you wouldn't be asking the question).
Tried debugging? E.g. attaching a debugger and watching for variables contents? Inserting logging or (God forgive me) debug print with echo?
"Didn't work" is a quite bad error description. This time you was lucky, because the error was obvious. Next time, please, be more specific.
someone wrote this code.
foreach ($node->taxonomy as $term) {
$tids[] = 't.tid = %d';
$args[] = $term->tid;
}
how he knows that in foreach "$node->taxonomy" is an array? and when i loop it,
foreach ($node->taxonomy as $term) {
}
the output that i get will be the $term's value. i don't know how it is change into the 't.tid = %d' and $term->tid. thank you.
In Drupal-related code, a $node is almost always an object produced by the node_load() function. Since every module has the opportunity to add its own properties to this object, it's very hard to find a central documentation of these properties.
By experience and by variable inspection, seasoned Drupal developers know that when set $node->taxonomy is always an array of term object (as returned by the taxonomy_get_term() function) indexed by their respective ids (named tids, for Term ID). This array is set by the taxonomy_nodeapi() function when $op == 'load' and is produced by the taxonomy_get_terms() function.
The question give little information but we can guess that the loop is meant to build two arrays used to generate a database query that filter on the tid column matching those of the $node object. Because the terms' data is already stored in the items of $node->taxonomy, let's hope that this query is not used to re-load the terms to display some of their name and/or description. Collecting 't.tid = %d' is probably a bad idea, the query would be better build with a single "tid in (". db_placeholder($args) .")" WHERE clause after collecting all the tids in $args.
The question is very unclear. All Items under the node object are arrays. You can check it yourself bu using:
print_r($node);
die;
Or using any PHP debugger.
for the foreach, It is very simple foreach... I don't understand what is the problem with that.
t.tid is simply an SQL query. %d is a placeholder for $args[], which consists of $term->tid. It's like this structure: PDO connections.
I'm trying to look through an array of records (staff members), in this loop, I call a function which returns another array of records (appointments for each staff member).
foreach($staffmembers as $staffmember)
{
$staffmember['appointments'] = get_staffmember_appointments_for_day($staffmember);
// print_r($staffmember['appointments'] works fine
}
This is working OK, however, later on in the script, I need to loop through the records again, this time making use of the appointment arrays, however they are unavailable.
foreach ($staffmembers as $staffmember)
{
//do some other stuff
//print_r($staffmember['appointments'] no longer does anything
}
Normally, I would perform the function from the first loop, within the second, however this loop is already nested within two others, which would cause the same sql query to be run 168 times.
Can anyone suggest a workaround?
Any advice would be greatly appreciated.
Thanks
foreach iterates over a copy of the array. If you want to change the value, you need to reference it:
foreach($staffmembers as &$staffmember) // <-- note the &
{
$staffmember['appointments'] = get_staffmember_appointments_for_day($staffmember);
// print_r($staffmember['appointments'] works fine
}
From the documentation:
Note: Unless the array is referenced, foreach operates on a copy of the specified array and not the array itself. foreach has some side effects on the array pointer. Don't rely on the array pointer during or after the foreach without resetting it.
and
As of PHP 5, you can easily modify array's elements by preceding $value with &. This will assign reference instead of copying the value.