PHP API request by GET details - php

Question

I'm trying to get the details from this example (i created the code right now).
But i'm very... confused... how can i get the details of the link, then separate and send to my MYSQL database..
<?php
$ch = curl_init();
$url = "https://reqres.in/api/users?page=2";
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$resp = curl_exec($ch);
if($e = curl_error($ch)) {
echo $e;
}
else {
$decoded = json_decode($resp, true);
//print_r($decoded);
foreach($decoded as $key => $item) {
$array = array(
'id' => ,
'email' => ,
'first_name' => ,
'last_name' => ,
);
print_r($array);
}
}
curl_close($ch);
?>

Answer 1

If you call the url in your browser then you will see that the result array is present in the data field.
You may check this by printing the whole result:
print_r($decoded);
So if you like to print_r the results it should be simply
print_r($decoded['data']);
If you like to store it in your database you may walk through the array and store each item
foreach($decoded['data'] as $item) {
storeItem($item);
}
To make this work you should implement the storeItem function which accepts the array $item and stores it into your database. There are various tutorials about doing that.