I want to get the value from $data->username but it returns NULL because input is not json. What am I doing wrong here?
Here is my current code.
JS:
$(function() {
$("#login-form").submit(function(e) {
e.preventDefault();
$.ajax({
url: 'http://penguin.linux.test/api/login.php',
type: 'post',
dataType: 'application/json',
data: $("#login-form").serialize(),
success: function(data) {
console.log(data);
},
error: function(data) {
console.log(data);
}
});
});
PHP:
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
$data = json_decode(file_get_contents("php://input", true));
}
Related
im trying to post to php using jquery but the success function is returning an empty string.
jquery:
function post() {
value = posts[index].id;
console.log(value)
$.ajax({
url: 'post.php',
type: 'POST',
data: {value: 'value'},
success: function(result) {
console.log(result)
}
})
}
php:
if(isset($_POST)) {
var_dump($_POST);
}
I want to get the return result of a php function in an Ajax request in order to make some verification in onSucces. How can I get the JSON result from the php function into the ajax request?
public function verifyEmailAction()
{
$is_valid = true;
$is_duplicate = false;
$email_reset = false;
$register = $this->getRegisterHelper();
$register->addEmailCheck();
$register->setData($this->getAllParams());
$validationErr = $register->getValidationResult();
if (!empty($validationErr['badWords']['email']) || $validationErr['banned']['email'] == true
|| empty($validationErr['isEmailValid'])
) {
$is_valid = false;
} elseif (!empty($validationErr['duplicates']['email'])) {
$is_duplicate = true;
$email_reset = $this->sendResetEmail();
}
$result = [
'duplicate' => $is_duplicate,
'valid' => $is_valid,
'reset' => $email_reset
];
$this->getResponse()->setBody(json_encode($result));
}
jQuery.validator.addMethod("checkDuplicate", function (value, element) {
jQuery.ajax({
type: 'GET',
url: '/user/register/verify-email.ajax',
data: {
'email': value
}
});
});
jQuery.ajax({
type: 'GET',
url: '/user/register/verify-email.ajax',
data: {
'email': value
},
dataType:'json',
success:function(response){
console.log(response);
var duplicate=response.duplicate;
var valid=response.valid;
var reset=response.reset;
},
error:function(err){
console.log('Error '+err);
}
});
You need to use the success and error functions like below,
jQuery.validator.addMethod("checkDuplicate", function (value, element) {
jQuery.ajax({
type: 'GET',
url: '/user/register/verify-email.ajax',
data: {
'email': value
},
success : function(data, status, xhr) {
console.log(JSON.stringify(data));
},
error: function(jqXhr, textStatus, errorMessage){
console.log("ERROR " + errorMessage);
}
});
});
$.ajax({
type: 'GET',
url: url,
data: {
'email': value
},
dataType:'json',
}).success(function(response){
//YOUR Json KEY
if(response.success){
}
});
I hope this article will help you.
http://api.jquery.com/jquery.ajax/
Specially you can use this
jQuery.ajax({
url: "YOURURL",
type: "YOURTYPE",
dataType:"json",
}).done(function(data) {
console.log(data) // to see the reqested data
// manipulate data here
});
Add dataType:'json':
jQuery.validator.addMethod("checkDuplicate", function (value, element) {
jQuery.ajax({
type: 'GET',
url: '/user/register/verify-email.ajax',
data: {
'email': value
},
dataType:'json'
});
});
You can use this to convert JSON string to a JavaScript object:
var txtReturned = JSON.parse(data);
Reference:
jQuery AJAX Call to PHP Script with JSON Return
I have a simple code but is not working. I want to create a more complex function but I just need the basic structure.
HTML
<span class="cleanreport">Delete Record</span>
Javascript:
$( ".cleanreport" ).click(function() {
var token = "test";
$.ajax({
data: {"data": token},
type: "post",
url: "clean.php",
success: function (data) {
console.log(data);
$('.test').html(data);
}
});
});
PHP clean.php
$data = $_POST['data'];
echo $data;
What I am doing wrong?
This should work for you:
var token = "test";
$.ajax({
type: 'POST',
url: "clean.php",
data: {id: token},
dataType: "json",
success: function(response) {
// some debug could be here
},
error: function(a,b,c) {
// some debug could be here
}
});
If not, please debug success and error parameters using console.log().
Based on jquery documentation setting type is an alias for method so this could not be a problem in you case for sure.
$( ".cleanreport" ).click(function() {
var token = "test";
$.post('clean.php",
{
data: token
},
function (data,status) {
//console.log(data);
$('.test').html(data);
});
});
I want to send the data via ajax to other page. I have isolated the problem. This is the code.
Thank you all for your help..But no effect..
updated code
It worked...
<script>
$(document).ready(function(){
$(".edit").click(function(event) {
event.preventDefault(); //<--- to prevent the default behaviour
var box = 1233;
var size=123;
var itemname=123;
var potency=123;
var quantity=12333;
var dataString ={
'box' :box,
'size':size ,
'itemname':itemname,
'potency':potency,
'quantity':quantity
};
$.ajax({
url: "dd.php",
type: "post",
data: dataString,
success: function(data) {
alert(data);
},
error: function(data) {
alert(data);
}
});
});
});
</script>
So I click the link,it navigates, to dd.php which has
<?php
echo json_encode(array('itemcode'=>$_POST['itemname']));
echo $_POST['itemname'];
?>
I get Object Object as alert. What am doing wrong? Pls throw some light here..thanks you..
$(document).ready(function(){
$(".edit").click(function(event) {
event.preventDefault();
var data = {"box":1233,
"size":565,
"itemname":565,
"potency":876,
"quantity":234};
$.ajax({
url: "dd.php",
type: "post",
data: data,
dataType: "json",
success: function(data) {
if(console){
console.log(data);
}
},
error: function(data) {
if(console){
console.log(data);
}
}
});
});
});
few things to consider... you can post data as object..which is clean and easier to use
$(".edit").click(function(event) {
event.preventDefault(); //<--- to prevent the default behaviour
var box = 1233;
....
var dataString ={'box':box,'size':size,'itemname':itemname,'potency':potency,'quantity':quantity};
$.ajax({
url: "dd.php",
type: "post",
data: dataString,
dataType: "json", //<--- here this means the response is expected as JSON from the server
success: function(data) {
alert(data.itemcode); //<--here alert itemcode
},
error: function(data) {
alert(data);
}
});
so you need to send the response as json in PHP
<?php
echo json_encode(array('itemcode'=>$_POST['itemname']))
?>
Here you are using querystring as sent in GET request.
If you want to send the data in same form, you can use this with GET request type:
$.ajax({
url: "dd.php"+dataString,
type: "get",
dataType: "json",
success: function(data) {
console.log(data);
alert(data.itemcode);
},
error: function(data) {
alert(data);
}
});
Or for POST request,you will have to put data in json object form, So you can use :
var dataString ={
'box' :box,
'size':size ,
'itemname':itemname,
'potency':potency,
'quantity':quantity
};
$.ajax({
url: "dd.php",
type: "post",
data: dataString,
dataType: "json",
success: function(data) {
console.log(data);
alert(data.itemcode);
},
error: function(data) {
alert(data);
}
});
});
And put echo in your php code :
<?php
echo json_encode(array('itemcode'=>$_POST['itemname']))
?>
Javascript alert shows [Object object] for object. You can see response using console.log or can use that key with alert.
For more information, refer jQuery.ajax()
below is the code i am using
$(document).ready(function(){
$("form").submit(function(event) {
event.preventDefault();
var val = $("#captcha_text").val();
$.ajax({
url: 'checkAnswer.php',
type: 'POST',
dataType: 'text',
data: {
answer: val
},
complete: function(data)
{
console.log(data);
if($.trim(data) == "true")
$("form")[0].submit();
else
alert('Wrong Answer');
}
});
});
});
checkAnswer.php has this one line only which is
echo "true";
i do not know why the javascript if condition in the complete function is always going to else part and showing alert('Wrong Answer')
does any one know what could be the problem. ? In the firebug console i do see the response comming back from my ajax and response value is "true"
use:
if($.trim(data.responseText) == "true")
complete receives as 1st argument jqXHR(an extended XMLHTTP-Request-object) and not the data depending on dataType.
Or use success instead of complete
Well i think you have to do this:
$.ajax({
url: 'test.php',
type: 'POST',
dataType: 'text',
data: {
answer: val
},
complete: function(jqXHR, textStatus)
{ //it returns an jqXHR object
if($.trim(jqXHR.responseText) == "true")
$("form")[0].submit();
else
alert('Wrong Answer');
}
});
This is because jQuery returns a jqXHR object look here for reference.
EDIT You can also try this:
$.ajax({
url: 'test.php',
type: 'POST',
dataType: 'text',
data: {
answer: val
},
success: function(data)
{
if($.trim(data) == "true")
alert('ok');
else
alert('Wrong Answer');
}
});