Sorting an array of numbers with for-loop - php

Question

I have a task of sorting an array of numbers in both ascending and descending order. The challenge is, I can't use the built-in sort function, but loop through the array with for-loops instead.
I am a total newbie when it comes to PHP and this task straight off baffles me. Here is the code I'm supposed to work with:
<?php
$arr = $_GET['arr'];
$table = explode(',', $arr);
$count = count($table);
// What I tried to work with, didn't get to work:
for ($i = 0; $i < $count; $i++) {
for ($j = $i + 1; $j < $count; $j++) {
if ($table[$i] > $table[$j]) {
$temp = $table[$i];
$table[$i] = $table[$j];
$table[$j] = $temp;
$asc = implode("," $temp);
}
}
}
echo "Ascending: $asc";
echo "Descending: $desc";
?>
Any clue why this doesn't run? At some point, I got the first (largest) number in the array with the echo, but don't really know what broke that either.

Answer 1

Move the line
$asc = implode(",", $table);
from its current location below the outer for loop and maybe add the line
$desc = implode(",", array_reverse($table));
to get the descending sort order.

Answer 2

Many ways to make it. One solution you will find in the code below. you will certainly notice that the sorting depends only on one operator. Therefore, you can build a function out of it by specifying the sorting as a parameter. function(array $array, string $sort) {}
DESC
$arr= array(112,21,130,140,2,42);
for($i=0; $i<count($arr)-1; $i++)
{
for($j=0; $j<count($arr)-1; $j++)
{
if($arr[$j] < $arr[$j+1]){
$temp= $arr[$j+1];
$arr[$j+1]= $arr[$j];
$arr[$j]= $temp;
}
}
}
print_r($arr);
Output:
Array
(
[0] => 140
[1] => 130
[2] => 112
[3] => 42
[4] => 21
[5] => 2
)
ASC
$arr= array(112,21,130,140,2,42);
for($i=0; $i<count($arr)-1; $i++)
{
for($j=0; $j<count($arr)-1; $j++)
{
if($arr[$j] > $arr[$j+1]){
$temp= $arr[$j+1];
$arr[$j+1]= $arr[$j];
$arr[$j]= $temp;
}
}
}
print_r($arr);
Output
Array
(
[0] => 2
[1] => 21
[2] => 42
[3] => 112
[4] => 130
[5] => 140
)