Define article id - php

I have a page of a separate article to which we go by slug
php.blade
#extends('layouts.app')
#section('content')
<div class="article-wrapper">
<div class="container">
<h1>{{ $article->title }}</h1>
<h3>{{ $article->subtitle }}</h3>
<img src="{{ $article->main_image }}" alt="">
<h3>{{ date('d F Y', strtotime($article->published_at)) }}</h3>
<h3>{{ $article->views }} Views</h3>
#foreach($article_blocks as $article_block)
<div class="text-image">
<h2>{{ $article_block->title_1 }}</h2>
<h3>{{ $article_block->text_1 }}</h3>
<img src="{{ $article_block->main_image }}" alt="">
</div>
#endforeach
#endsection
controller
public function index(Request $request, $slug)
{
$article = Article::where('slug', $slug)->first();
$article_blocks = ArticleBlock::where('article_id', 1)->get();
return view('article', compact('article', 'article_blocks'));
}
Next, I have another model for blocks, each article has its own blocks, as you can see in my controller, I manually write the article ID to get the blocks specific for it.
How to make it itself determine which article we are on, and display blocks only for it?

Try :
public function index(Request $request, $slug)
{
$article = Article::firstWhere('slug', $slug);
$article_blocks = ArticleBlock::where('article_id', $article->id)->get();
return view('article', compact('article', 'article_blocks'));
}
If you have created relationships between your models, you can use it as follows:
public function index(Request $request, $slug)
{
$article = Article::with('articleBlock')->where('slug', $slug)->get();
return view('article', compact('article'));
}

Related

laravel view doesn't show data after adding new route

It works really good, but when I've created new page something goes wrong and now my blog view doesn't show data, but blogs view still correctly show data . I am trying to show detailed data of each blog when user click on button "Details"
MainController:
public function blog(Blogs $blog)
{
return view('blog', compact('blog'));
}
public function blogs()
{
return view('blogs',['blogs' => Blogs::all(),]);
}
blogs.blade.php:
#extends('layouts.master')
#section('title', __('main.blogs'))
#section('content')
<div class="row">
#foreach($blogs as $blog)
#include('layouts.cardBlog', compact('blog'))
#endforeach
</div>
#endsection
and cardBlog.blade.php:
<div class="col-sm-6 col-md-4">
<div class="thumbnail">
<img src="{{($blog->image) }}">
<div class="caption">
<h3>{{ $blog->title }}</h3>
<p>{{ $blog->body }}</p>
<p>
<a href="{{route('blog', $blog->id) }}"
class="btn btn-default"
role="button">#lang('main.more')</a>
#csrf
</p>
</div>
</div>
</div>
blog.blade.php
#extends('layouts.master')
#section('title', __('main.blogs'))
#section('content')
<h1>{{ $blog->title}}</h1>
<img src="{{$blog->image }}">
<p>{{ $blog->body }}</p>
#endsection
web.php:
Route::get('/', 'MainController#index')->name('index');
Route::get('/categories', 'MainController#categories')->name('categories');
Route::get('/about', 'MainController#aboutus')->name('about');
Route::get('/contact-us', 'ContactUSController#contactUS')->name('contact-us');
Route::post('contactus', ['as'=>'contactus.store','uses'=>'ContactUSController#contactSaveData']);
Route::get('/contacts', 'MainController#contacts')->name('contacts');
Route::get('/blogs', 'MainController#blogs')->name('blogs');
Route::get('/blog/{id}', 'MainController#blog')->name('blog');
Route::get('/intership', 'MainController#intership')->name('intership');
Route::get('/{category}', 'MainController#category')->name('category');
Route::get('/{category}/{product}/{skus}', 'MainController#sku')->name('sku');
Route::post('subscription/{skus}', 'MainController#subscribe')->name('subscription');
What's is the error that it shown?
I suggest use "compact" in this line code
return view('blogs',['blogs' => Blogs::all(),]);
Something like this
public function blogs()
{
$blogs = Blogs::all();
return view('blogs',compact('blogs'));
}
Try this
public function blog($id)
{
$blog = Blogs::findOrFail($id)
return view('blog', compact('blog'));
}

Laravel records not geting as dynamic

views/show.blade.php
#extends('layouts.app')
#section('content')
<h5>Showing Task {{ $task->title }}</h5>
<div class="jumbotron text-center">
<p>
<strong>Task Title:</strong> {{ $task->title }}<br>
<strong>Description:</strong> {{ $task->description }}
</p>
</div>
#endsection
Controllers/HomeController.php
public function show(Task $task)
{
return view('show', compact('task', $task));
}
routes/web.php
Route::get('show/{id}', 'HomeController#show')->name('show');
views/viewalltask.blade.php
<td>{{$data->title}}</td>
No error / No Record / instead of particulr record display blank page
You need to change the route configuration to:
Route::get('show/{task}', 'HomeController#show')->name('show');
This way Laravel's IOC container knows how to resolve/bind it.
Must match the variable name used in the method definition:
public function show(Task $task)

Laravel Collection get one of values by key

I'm new to Laravel and I'm trying to get one of the values in one collection by one ID retrieved from another collection.
My function returns 2 Collections:
public function index()
{
$category = BlogCategory::all(['id', 'name']);
$post = BlogPost::orderBy('id', 'desc')->take(14)->get();
return view('blog.index', ['posts' => $post], ['categories' => $category]);
}
In a foreach loop I'm getting values from collections:
#foreach($posts as $post)
#if($loop->iteration > 2)
<div class="col-sm-6 col-md-3 d-flex justify-content-center other-post">
<a href="#">
<img src="#" alt="">
<p class="post-category">{{ $categories->get($post->category_id) }}</p>
<h5 class="post-title">{{ $post->title }}</h5>
</a>
</div>
#endif
#endforeach
I'm partially getting the result as you can see in the image below, but I want to get only the name.
Here is the code that I'm trying to figure out
{{ $categories->get($post->category_id) }}
If there is a better or correct way to do it, let me know.
Blog Posts migration:
public function up()
{
Schema::create('blog_posts', function (Blueprint $table) {
$table->bigIncrements('id');
$table->string('title');
$table->longText('content');
$table->mediumText('slug');
$table->bigInteger('author_id')->unsigned();
$table->bigInteger('category_id')->unsigned();
$table->timestamps();
$table->foreign('author_id')->references('id')->on('blog_authors');
$table->foreign('category_id')->references('id')->on('blog_categories');
});
}
You should put in place the relationships between BlogPost and BlogCategory models, seen that you already have a category_id field in BlogPost model, i.e.:
in BlogPost Model:
public function category(){
return $this->belongsTo(\App\BlogCategory::class);
}
in BlogCategory Model:
public function posts(){
return $this->hasMany(\App\BlogPost::class);
}
Next you can eager load categories with the $posts in your controller with only two queries:
public function index()
{
$posts = BlogPost::with('category')->orderBy('id', 'desc')->take(14)->get();
return view('blog.index', compact('posts'));
}
Then in your view you can access each $post->category object directly because eager loaded in the controller:
#foreach($posts as $post)
#if($loop->iteration > 2)
<div class="col-sm-6 col-md-3 d-flex justify-content-center other-post">
<a href="#">
<img src="#" alt="">
<p class="post-category">{{ $post->category->name }}</p>
<h5 class="post-title">{{ $post->title }}</h5>
</a>
</div>
#endif
#endforeach
It could be optimized, first, you need to make relation one to many from categories to posts
first: make sure that you have in posts migrations category_id column
Second: Open Category Model and write this method this will allow you to fetch posts that belong to the category
public function posts(){
return $this->hasMany(\App\Post::class);
}
Third: open shop model and write this method this will allow you to fetch category that belongs to the post
public function catgeory(){
return $this->belongsTo(\App\Category::class);
}
Finally: you will edit your view like this one
#foreach($posts as $post)
<div class="col-sm-6 col-md-3 d-flex justify-content-center other-post">
<a href="#">
<img src="#" alt="">
<p class="post-category">{{ $post->category->title }}</p>
<h5 class="post-title">{{ $post->title }}</h5>
</a>
</div>
#endforeach
and of course, you wouldn't call categories in your controller anymore
public function index()
{
$post = BlogPost::orderBy('id', 'desc')->take(14)
->with('category')->get();
return view('blog.index', ['posts' => $post]);
}
Maybe it better use a relation to drive this situation. You can load in the controller the data in this way.
In the Model Post:
function categories(){
return $this->belongsToMany('App\BlogCategory')->select(array('id', 'name');
}
Maybe is hasOne -> the relationship if you don't have a table pivot...
In the Controller:
public function index()
{
$data['posts'] = BlogPost::orderBy('id', 'desc')->take(14)->with('categories')->get();
return view('blog.index', $data);
}
In the View:
#foreach($posts as $post)
#if($loop->iteration > 2)
<div class="col-sm-6 col-md-3 d-flex justify-content-center other-post">
<a href="#">
<img src="#" alt="">
<p class="post-category">{{ $post->categories->name }}</p>
<h5 class="post-title">{{ $post->title }}</h5>
</a>
</div>
#endif
#endforeach
this line $categories->get($post->category_id) return for you an array of category, so the solution for you here is just like bellow:
{{ $categories->get($post->category_id)['name'] }}

How to make url with slug in Laravel 5.4?

Right now I am trying to do a Laravel url with slug. I have my main page where I show all categories:
<div class="panel-body">
#foreach($categories as $category)
<p>{{ $category->name }}</p>
#endforeach
</div>
And now I want to go to a certain category page. I created routes:
Route::get('/test', 'FuelAccountingController#index')->name('fuel_accounting');
Route::get('/test/{slug}', 'FuelAccountingController#element');
And functions in controller:
public function index()
{
$categories = DB::table('fuel_accounting_categories')
->select('id', 'name', 'slug')
->get();
return view('pages.fuel_accounting')->with('categories', $categories);
}
public function element($slug)
{
$category = DB::table('fuel_accounting_categories')
->select('slug')
->where('slug', '=', $slug)
->first();
return view('pages.fuel_accounting_element')->with('category', $category);
}
And when I am trying to reach a page (for example: laravel.dev/test/current_category) it does not work. Can someone explain me how to do that?
Error: Sorry, the page you are looking for could not be found. (1/1) NotFoundHttpException
FIXED
<div class="panel-body">
#foreach($categories as $category)
<p>{{ $category->name }}</p>
#endforeach
</div>

Passing data from blade to route

I'm trying to list articles from database then show details of the article when the user clicks on it.
How can I pass the article id or name to the route/controller to display the details? I tried butting the id in the href but I don't know how to handle it from routes!
this is the articles list:
#foreach ($articles as $article)
<div class="panel-body">
{{$article->name}}
</div>
#endforeach
where do I go from here?
Your View file for listing all the articles:
#foreach ($articles as $article)
<div class="panel-body">
{{$article->name}}
</div>
#endforeach
routes.php
Route::get('/article/{id}', 'ArticlesController#show');
ArticlesController.php
/**
* Show the article of the given id.
*
* #param int $id The id of the article
* #return \Illuminate\View\View
*/
public function show($id)
{
$article = Article::findOrFail($id);
return view('articles.show', compact('article'));
}
show.blade.php
<h3>{{ $article->name }}</h3>
<p>{{ $article->body }}</p>
If you want to use route() you can pass parameters in second argument
#foreach ($articles as $article)
<div class="panel-body">
{{ $article->name }}
^^^ or whatever is the name of your route
</div>
#endforeach
Naturally this assumes you have your route defined in app\Http\routes.php. For example
Route::get('/articles/{id}', ['as' => 'article.show', 'uses' => 'ArticleController#show']);
Alternatively you can use url()
#foreach ($articles as $article)
<div class="panel-body">
{{ $article->name }}
</div>
#endforeach

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