Check if name ends by string in PHP - php

Question

In my folder cache, i have dozens of files whose name is filename-number.json, like
sifriugh-80.json
dlifjbhvzique-76.json
dfhgzeiuy-12.json
...
I have a simple script that cleans my cache dir every 2 hours, deleting files older than 2 hours:
$fileSystemIterator = new FilesystemIterator('cache');
$now = time();
foreach ($fileSystemIterator as $file) {
if ($now - $file->getCTime() >= 3 * 3600) // 2 hours
unlink('cache/' . $file->getFilename());
}
Now, i'm looking to only delete every 2 hours files whose number (before .json but not if number is present at the beginning of the file) does NOT end by -100.json, and those ending by -100.json, every 7 days only.
I know that i can use preg_match() to get names, but is there any effective way to perform it?

Answer 1

There is much simpler way than regex using PHP 8+ str_ends_with() : https://www.php.net/manual/en/function.str-ends-with.php
if (str_ends_with($file->getFilename(), '100.json)) {
// unlink at needed time
} else {
// unlink at needed time
}
For PHP 7, there are several ways to emulate it, check at the bottom of https://www.php.net/manual/en/function.str-ends-with.php

Answer 2

I do not see why you should not use preg_match. It is so good here.
Before using preg_match you should check the first symbol in file name and skip the next code if it is_numeric.
If it is not numeric you need to get only ending "-" can be presented zero or ones + number 1 or more digits + .json ending
(pattern can be something like this /-?\d+\.json$/)
After that you can parse it and know the real number before .json,
Your verification will be something like
If "-" symbol exists and number is 100 check the date for 7 days
If number is not 100 check the date for 2 hours