How to use array_map with reset callback in php 8 [duplicate] - php

This question already has answers here:
Change the array KEY to a value from sub array
(7 answers)
How can i get sub array value to main array key? [Php] [duplicate]
(2 answers)
Multidimensional indexed array to associative array depending on column value
(2 answers)
Closed 10 months ago.
I have a function that work good in php 7 but in php 8.0.11 has warning
$orders->result = array_map('reset', $orders->result);
E_WARNING: reset(): Argument #1 ($array) must be passed by reference, value given in
Of course, I can use this code instead that but maybe slower than array_map
foreach ($orders->result as $item)
$result[$item[0]['order_id']] = $item[0];
Edit:
before foreach or array_map the output like this
Array
(
[0] => Array
(
[order_id] => 41111909
[shop_id] => 34277
[user_id] => 42363
[status_id] => 4
)
)
after use foreach output like this
Array
(
[41111909] => Array
(
[order_id] => 41111909
[shop_id] => 34277
[user_id] => 42363
[status_id] => 4
)
)
How to solve it ?

The simplest replacement is to make an arrow function (single-expression closure) to get the element for you.
If the arrays are plain lists, so that you're always getting element 0, that's as simple as:
$orders->result = array_map(fn($item) => $item[0], $orders->result);
Another alternative in this case is array_column:
$orders->result = array_colum($orders->result, 0);
If you have other keys, you could use either reset or array_key_first in the callback instead:
$orders->result = array_map(fn($item) => $item[array_key_first($item)], $orders->result);
(I suspect array_key_first will be slightly more efficient, since it doesn't need to manipulate the internal array pointer.)

It's not entirely clear what you're trying to do, but it seems like you are trying to get the first value from nested arrays. You should be able to use a function:
$orders->result = array_map(function($v) { return reset($v); }, $orders->result);
You may also try using current if it does what you need as it doesn't take a reference and the array pointer should already be reset by array_map:
$orders->result = array_map('current', $orders->result);
After the edit the code in question is not re-indexing the array as you show in the before and after. To do that is simple:
$orders->result = array_column($orders->result, null, 'order_id');

Related

PHP array sort with forced the first row [duplicate]

This question already has answers here:
Move array item with certain key to the first position in an array, PHP
(9 answers)
move array element to the first position but remain order
(4 answers)
Move an array element to a new index in PHP
(9 answers)
Move Value in PHP Array to the Beginning of the Array
(12 answers)
Move array element with a particular value to top of array
(2 answers)
Closed 2 months ago.
How to sort an array at PHP to force selected row as a first ?
My array is
array[]=array(id=>'a', content=>'lemon');
array[]=array(id=>'b', content=>'apple');
array[]=array(id=>'c', content=>'banana');
array[]=array(id=>'d', content=>'cherry');
How to sort the array to force
array[]=array(id=>'b', content=>'apple');
as a first row and doesn't matter the rest (apple is the key).
And in other example turn sort to get
array[]=array(id=>'d', content=>'cherry');
as a first row and doesn't matter the rest (cherry is the key).
Another way to do this is to effectively rotate the array using array_slice, bringing the element you want to the start:
$first = 'apple';
$k = array_search($first, array_column($array, 'content'));
$array = array_merge(array_slice($array, $k), array_slice($array, 0, $k));
print_r($array);
Output:
Array (
[0] => Array ( [id] => b [content] => apple )
[1] => Array ( [id] => c [content] => banana )
[2] => Array ( [id] => d [content] => cherry )
[3] => Array ( [id] => a [content] => lemon )
)
Demo on 3v4l.org
There are 2 ways I can think of doing this. The first is as Ultimater in the comments suggest to extract the matching row, then sort and then add the row back in...
$first = 'apple';
$array = [];
$array[]=array('id'=>'a', 'content'=>'lemon');
$array[]=array('id'=>'b', 'content'=>'apple');
$array[]=array('id'=>'c', 'content'=>'banana');
$array[]=array('id'=>'d', 'content'=>'chery');
$firstElement = array_search($first, array_column($array, "content"));
$row = $array[$firstElement];
unset($array[$firstElement]);
sort($array);
array_unshift($array, $row);
print_r($array);
The second is to use usort and add specific clauses in that if the key matches the row you want first, then it will always force it to the first row...
$first = 'apple';
usort($array, function ($a, $b) use ($first){
if ( $a['content'] == $first) {
return -1;
}
if ( $b['content'] == $first) {
return 1;
}
return $a <=> $b;
});
print_r($array);
(I've used <=> in this which is PHP 7+, there are alternatives if you need to use PHP 5).
If as your comment suggests that there is no need to sort the rest of the data, then the first set of code minus the sort() should do.
One other option - if id:content is one to one, we can index the array by content and merge with an array with a single empty "apple" key (or whichever content value you're looking for).
$array = array_merge(['apple' => []], array_column($array, null, 'content'));
If the resulting string keys are undesirable the array can be reindexed with array_values.
If the array only contains id and content and id:content is in fact one to one, a "dictionary" of key-value pairs will be handier to deal with than a list of rows like this and it would probably be better to set the array up that way to begin with if possible.
If id:content is not one to one, then... never mind. ;-)

Collect all values from nested array row of specific key [duplicate]

This question already has answers here:
How to get an array of specific "key" in multidimensional array without looping [duplicate]
(4 answers)
Closed 1 year ago.
Need to create a list that consists of all values stored in the array row of a specific key (product_id). Currently, doing a print_r of my $bestsellers variable produces the following array:
Array
(
[0] => stdClass Object
(
[product_id] => 178
[order_item_qty] => 9
)
[1] => stdClass Object
(
[product_id] => 233
[order_item_qty] => 4
)
[2] => stdClass Object
(
[product_id] => 179
[order_item_qty] => 1
)
)
Other SO answers led me to try:
$ids = array_column($bestsellers, 'product_id');
...but that produced an empty array, I guess because the row I’m trying to grab is nested in there? With that in mind I tried
foreach($bestsellers as $bestseller) {
$ids = array_column($bestsellers, 'product_id');
}
...which produced no result at all.
Hopefully someone can help clue me in as to where I’m going wrong. Thanks!
The nested values are objects, not arrays (can't you see stdClass Object in the output?). array_column is for 2-dimensional arrays. You need to access the properties using object syntax.
$ids = array_map(function($x) { return $x->product_id; }, $bestsellers);
For future reference, array_column will work for this in PHP 7, so you must be using PHP 5.
For PHP 7, your code
$ids = array_column($bestsellers, 'product_id');
will do what you want it to.
See the difference here on 3v4l.org.

Php reverse array is not working [duplicate]

This question already has answers here:
Reverse an associative array with preserving keys in PHP
(4 answers)
Closed 5 years ago.
I am developing a new website, and I have a quetion.
Input array:
Array ( [1319] => ####,[1316] => ###)
I have an array and I want to revese him, after the reverse the array would be like this:
Expected output:
Array ( [1316] => ###,[1319] => ####)
but when i'm using array_reverse function, it doesnt work for me, I got this array:
Array ( [0] => ###,[1] => ####)
Why it is happen?
For preserving keys you just pass second parameter to true in array_reverse.
Try this code snippet here
$array=Array ( 1319 => "####",1316 => "###");
print_r(array_reverse($array,true));
you can try this:
$a = []; //your array
$keys = array_keys($arr);
$values = array_values($arr);
$rv = array_reverse($values);
$newArray = array_combine($keys, $rv);

Take value from array which is in array [duplicate]

This question already has answers here:
PHP - Accessing Multidimensional Array Values
(4 answers)
Closed 8 years ago.
I've got this url:
http://web.com/script.php?identifiers%5Bmc%5D%5Bnick%5D=name1&identifiers%5Bcs%5D%5Bnick%5D=name2&identifiers%5Bcs%5D%5Bpassword%5D=mypass
so i will get array like this:
[identifiers] => Array
(
[mc] => Array
(
[nick] => name1
)
[cs] => Array
(
[nick] => name2
[password] => mypass
)
)
How do I take value name1 and put into variable $mc_name?
That's a simple array containing another array so you can simply specify multiple indexes for included array:
$mc_name = $_GET['identifiers']['mc']['nick'];
To better understand how it works think of it like assigning each array first to a variable like:
$identifiers = $_GET['identifiers'];
$mc_array = $identifiers['mc'];
$mc_name = $mc_array['nick'];
which will essentially do the same thing at once, without the need to specify multiple variables and arrays.
Start with:
identifiers = $_GET['identifiers']
If you know the key names, then simply:
$mc_name = $identifiers['mc']['nick']
If you know it's the first value or the first value, then you can:
$mc_name = array_shift($identifiers); // get the 'mc' array
$mc_name = array_shift($identifiers); // get the 'nick' value
Not that array_shift will actually remove the elements from the original array.

php reassign array contents [duplicate]

This question already has answers here:
Transposing multidimensional arrays in PHP
(12 answers)
Closed 1 year ago.
any particular function or code to put this kind of array data
ori [0] => 43.45,33,0,35 [1] => 74,10,0,22 [2] => 0,15,0,45 [3] => 0,0,0,340 [4] => 12,5,0,0 [5] => 0,0,0,0
to
new [0] => 43.45,74,0,0,12,0 [1] => 33,10,15,0,5,0 [2] => 0,0,0,0,0,0, [3] => 35,22,45,340,0,0
As you can see, the first value from each ori are inserted into the new(0), the second value from ori are inserted into new(1) and so on
If $ori is an array of arrays, this should work:
function transpose($array) {
array_unshift($array, null);
return call_user_func_array('array_map', $array);
}
$newArray = transpose($ori);
Note: from Transposing multidimensional arrays in PHP
If $ori is not an array of arrays, then you'll need to convert it first (or use the example by Peter Ajtai), like this:
// Note: PHP 5.3+ only
$ori = array_map(function($el) { return explode(",", $el); }, $ori);
If you are using an older version of PHP, you should probably just use the other method!
You essentially want to transpose - basically "turn" - an array. Your array elements are strings and not sub arrays, but those strings can be turned into sub arrays with explode() before transposing. Then after transposing, we can turn the sub arrays back into strings with implode() to preserve the formatting you want.
Basically we want to go through each of your five strings of comma separated numbers one by one. We take each string of numbers and turn it into an array. To transpose we have to take each of the numbers from a string one by one and add the number to a new array. So the heart of the code is the inner foreach(). Note how each number goes into a new sub array, since $i is increased by one between each number: $new[$i++][] =$op;
foreach($ori as $one) {
$parts=explode(',',$one);
$i = 0;
foreach($parts as $op) {
$new[$i++][] =$op;
}
}
$i = 0;
foreach($new as $one) {
$new[$i++] = implode(',',$one);
}
// print_r for $new is:
Array
(
[0] => 43.45,74,0,0,12,0
[1] => 33,10,15,0,5,0
[2] => 0,0,0,0,0,0
[3] => 35,22,45,340,0,0
)
Working example

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