Laravel Pagination - Call to undefined method Illuminate\Database\Eloquent\Builder::links() - php

Question

I am using Laravel Framework 8.62.0 and PHP 7.4.20.
I get the following error:
Call to undefined method Illuminate\Database\Eloquent\Builder::links() (View: /home//Code/test_project/resources/views/index.blade.php)
I have a view that has uses 3 simple filters. To display the view via get I use the following:
public function getSearchView()
{
try {
$con = 'mysql_prod';
// search results
$items = Item::on($con)->select(['items.name AS item_name', 'items.slug', 'items.id AS item_id', 'item_details.sticker_number', 'item_details.section', 'item_details.type', 'collections.name AS collections_name', 'collections.sport_type', 'collections.league', 'collections.year as collections_year', 'images.file_name'])
->leftJoin('item_details', 'items.id', '=', 'item_details.items_id')
->leftJoin('collections', 'items.collections_id', '=', 'collections.id')
->leftJoin('images', 'images.items_id', '=', 'items.id')
->limit(500)
->paginate(10);
// filter field
$condition = Condition::on($con)->select(['id', 'name AS condition_name'])
->distinct()
->get();
$collection = Collection::on($con)->select(['id', 'name AS collection_name'])
->distinct()
->orderBy('collection_name', 'ASC')
->get();
return view('index', compact('items'));
} catch (\Exception $e) {
Log::error($e);
report($e);
}
}
To filter the view I use:
public function postFilter(Request $request)
{
try {
$con = 'mysql_prod';
//##################################
// QUERY - SEARCH RESULTS
//##################################
$items = Item::on($con)->select(['items.name AS item_name', 'items.slug', 'items.id AS item_id', 'item_details.sticker_number', 'item_details.section', 'item_details.type', 'collections.name AS collections_name', 'collections.sport_type', 'collections.league', 'collections.year as collections_year', 'images.file_name'])
->leftJoin('item_details', 'items.id', '=', 'item_details.items_id')
->leftJoin('collections', 'items.collections_id', '=', 'collections.id')
->leftJoin('images', 'images.items_id', '=', 'items.id');
// collection
if(!is_null($request->select_collection_field)) $items->where('collections.id', '=', intval($request->select_collection_field));
// FILTER field
if(!is_null($request->select_filter_field)) {
if($request->select_filter_field === "select_all") $items->orderBy('item_name', 'desc');
if($request->select_filter_field === "publishing_year") $items->orderBy('collections_year', 'desc');
}
// query database
$items->limit(500)->paginate(10);
//##################################
// FILTERS
//##################################
$condition = Condition::on($con)->select(['id', 'name AS condition_name'])
->distinct()
->get();
$collection = Collection::on($con)->select(['id', 'name AS collection_name'])
->distinct()
->orderBy('collection_name', 'ASC')
->get();
return view('index', compact('items', 'condition', 'collection'));
} catch (\Exception $e) {
Log::error($e);
report($e);
}
}
In my web.php I have the two endpoints:
Route::get('/', [SearchController::class, 'getSearchView'])->name('/');
Route::post('postFilter', [SearchController::class, 'postFilter']);
In my view I use the pagination of laravel:
{!! $items->links('vendor.pagination.default') !!}
Any suggestions why I get the above error and how to fix it?
I appreciate your replies!

Answer 1

$items is currently a Query Builder instance. This object wont change, it will continue to be a Query Builder instance. When you execute a query from a Query Builder you get a returned result, and that is what you need to be passing to your view. You could reassign $items to this result easily:
$items = $items->limit(500)->paginate(10);
Now $items is the Paginator instance because you reassigned that variable to the result of the paginate call.

Answer 2

public function boot()
{
Paginator::defaultView('view-name');
Paginator::defaultSimpleView('view-name');
}
add this code to AppServiceProvider. I hope it will work.