I am new to Codeigniter so I'm having some difficulties I want to retrieve data from the database and load it in the view but I couldn't figure out how.
Here is my model:
public function viewClientWaterwell(){
$userid = get_client()->userid;
$waterwells = $this->db->select('*')
->from($this->table)
->where('ww_client_id', $userid)
->get()->result_array();
return $waterwells;
}
Here is my clientController:
public function viewClient()
{
$data['waterwells'] = $this->waterwell_model->viewClientWaterwell();
$this->data($data);
$this->view('waterwells/clients/viewClient');
$this->layout();
}
I want to pass some data in a view to the client side but I can't figure out how. I think there is some problem with my model but I cannot figure out what. I'm new to this and will appreciate your feedback. Thanks!
You just need to use second argument to pass data to your template or view file
Here is example to start
Inside your controller function
public function viewClient()
{
$data = array( 'myvar' => 'I love stackoverflow' );
$this->load->view('waterwells/clients/viewClient', $data);
}
And inside your template or view file you can access them by their name.
<?php echo $myvar; ?>
Related
Hi everyone i have a many-to-many relationship between the turnos table and the dias table like this:
Currently, I'm doing the CRUD of the turnos table and for each turnos I have to assign many dias, I did it with the attach method.
Now the issue is in the edit method... how am I gonna get the assigned dias that is related to that turno so I can pass it to the view and the user can edit it?
If someone knows it please help me, I would appreciate it very much
//Dias Model
public function turnos()
{
return $this->belongsToMany(Turno::class);
}
//Turnos Model
public function dias()
{
return $this->belongsToMany(Dia::class);
}
// Controller
public function edit(Turno $turno)
{
// $dias = ??
return Inertia::render('Turnos/Editar', [
'turno' => $turno,
'dias' => ??
]);
}
The edit view Should looks like this:
You can load the relation with the load() method and just return the $turno variable that will contain the "turno" and the "dias".
public function edit(Turno $turno) {
$turno->load('dias');
return Inertia::render('Turnos/Editar', [
'turno' => $turno
]);
}
On the client side you can use v-model to fill your inputs.
This is my first time using this and im having issues. I have a HttpSocket->get which is working but i dont know how to display the results in my view
public function index() {
$HttpSocket = new HttpSocket();
// array query
$results = $HttpSocket->get('https://myurl.com', array('username' => 'myuser','password'=>'mypassword','cmd'=>'mycommands'));
//debug($results);
}
The response is there i can see it when i debug. please someone tell me how to show this in my view!!!
Thanks
Steve
CakePHP provide set() method to send variable value on view
$this->set("results", $results);
Controller method TestsController.php
public function index() {
$HttpSocket = new HttpSocket();
// array query
$results = $HttpSocket->get('https://myurl.com', array('username' => 'myuser','password'=>'mypassword','cmd'=>'mycommands'));
$this->set("results", $results);
//debug($results);
}
For instance your controller name TestsController then you will create file /view/Tests/index.ctp
view file index.ctp
print_r($results);
I wanted to know if there's a way to use variable layout for a single view in laravel.
I have a view of the login section. I want to show the login view in a lightbox by calling it via AJAX. I was thinking of using a different layout for the login view when it is called through ajax.
Something like this :
if($_GET["from"] == "ajaxLink") {
// use layout1
} else {
// use layout2
}
This obviously doesnt work. :)
Is there any way i can do this??
Thanks.
2 ways.
1. Blade layout
Controller:
$layout = Request::ajax() ? 'layout1' : 'layout2';
$data = array('layout' => $layout);
return View::make('index', $data);
View:
#layout($layout)
//rest of the code....
2. Controller layout
public function action_index()
{
$this->layout = Request::ajax() ? 'layout1' :'layout2';
$this->layout->nest('content', 'index');
}
Our Yii Framework application has the following defined as part of the UserProfileImages model:
public function getProfileImages($param, $user_id) {
if(isset($param['select']) && $param['select']=='all'){
$profile_images = UserProfileImages::model()->findAllByAttributes( array( 'user_id'=>$user_id) );
} else {
$profile_images = UserProfileImages::model()->findByAttributes( array( 'user_id'=>$user_id) );
}
return $profile_images;
}
How would I wire up the above snippet to a widget in my view to return all the images for a given user?
Bonus Question: Which image rotator do you suggest to render the above?
In your view file, add something like this, assuming that your controller specified $user_id:
$this->widget('UserProfileImagesWidget', array(
"userProfileImages" => UserProfileImages::getProfileImages(
array("select" => "all"),
$user_id
),
"user_id" => $user_id
));
Depending on your MVC philosophy, you could also retrieve the userProfileImages data in the controller and pass that data to your view.
Define a widget like this:
class UserProfileImagesWidget extends CWidget {
public $user_id;
public $userProfileImages = array();
public function run() {
$this->render("userProfileImage");
}
}
Finally, in the userProfileImages.php view file, you can do something like this:
if(!empty($this->userProfileImages)) {
// Your display magic
// You can access $this->user_id
}
As a side note: You might want to change the order of your parameters in getProfileImages. If $user_id is the first parameter, you can leave out $params completely in case you don't want to specify any.
Given an html/javascript 'widget' which needs to have certain fields customized before use. For example, the css class ids need to be unique as the widget may appear more than once on the same page.
Let's say I want to keep the markup (js/html) of the widget stored as a template so that I can fill in the values that need to be customized during resuse.
I know that Zend Framework's views give you at least part of this functionality, but each view is generally associated with a particular controller. Given that this widget could be created from any controller, yes still needs to be able to access some properties stored in a controller (or model). Where should I put the widget markup and how then do I fill in the custom values?
Can I create a custom view that can be reused within the same page (appear more than once) as well as on other pages? If so, how do I set that up?
Sounds like you need a ViewHelper http://framework.zend.com/manual/en/zend.view.helpers.html. Create a custom helper that will fetch the data from a model and just simply output it. This way it won't depend on any controller, can be called in either the layout or in any view script. Example:
// views/helpers/Widget.php
class Zend_View_Helper_Widget extends Zend_View_Helper_Abstract
{
protected $_model = null;
protected $_view = null;
public function widget()
{
$data = $this->_getDataFromModel();
return $this->_view->partial('widget.phtml', array('data' => $data));
}
public function setView(Zend_View_Interface $view)
{
if($this->_view === null) {
$this->_view = $view;
}
return $this->_view;
}
protected function _getDataFromModel()
{
$this->_model = $this->_getModel();
return $this->_model->getDataForWidget();
}
protected function _getModel()
{
if($this->_model === null) {
$this->_model = new Model_Widget(); // or whatever it's called
}
return $this->_model;
}
The partial script:
// views/scripts/widget.phtml
<div class="widget-class"><?php echo $this->data; ?></div>
And when you need it in your views just call it like <?php echo $this->widget(); ?>
Note that I'm rendering the widget in a separate partial view script, just to avoid having html/css in the helper itself.
Hope this helps to get you started :)
Zend_View_Helper_Partial
Example:
<?php echo $this->partial('partial.phtml', array(
'css_id' => 'foobar')); ?>
To run this from any other module:
<?php echo $this->partial('partial.phtml', 'partials_module', array(
'css_id' => 'foobar')); ?>
In your partial view script (partial.html) you would then have access to $this->css_id.