So I've created a function to allow letters single letters to be changed in to a 2 digit number.
This is the code:
<?php
function Letter2number($abc) {
//A = 00
str_replace('a','00',$abc);
str_replace('A','00',$abc);
//B = 01
str_replace('b','01',$abc);
str_replace('B','01',$abc);
//C = 02
str_replace('c','02',$abc);
str_replace('C','02',$abc);
//D = 03
str_replace('d','03',$abc);
str_replace('D','03',$abc);
//E = 04
str_replace('e','04',$abc);
str_replace('E','04',$abc);
//F = 05
str_replace('f','05',$abc);
str_replace('F','05',$abc);
}
?>
When the variable from a form input is processed though this function it was meant to output a 2 digit number.
But the output is blank.
Any idea what I'm doing wrong?
First attempt at programming? I hope you have a bit of fun. There are two major problems with your code, both have to do with return values.
Something like str_replace('F','05',$abc); returns a string, which you have to do something with. For instance: $abc = str_replace('F','05',$abc);.
Your function doesn't return anything. At the bottom of the function use return $abc;.
Also consider your choice of variable name: $abc implies that it contains the alfabet, not one letter. A better name would be $letter.
TIP: I used $abc in the above points to not confuse you any further, but the code itself is far from optimal. Can you make it better?
Related
In PHP I am using stristr search but I also want to return and display the surrounding characters each side of the found string, like concordancer. About 9 or 10 characters should be enough, for example:
'below' is the string I have found, but then I want to display context for my users, like this:
'if I sat below the deck'
My current code is
if (stristr($order, $en[$i])) {
$lit= "".$en[$i]."";
$order = str_replace($en[$i], $lit, $order, $count);
$total = $total + $count;
$sub[$loc[$i]] = $sub[$loc[$i]] + $count;
$carreau[$loc[$i]] = $carreau[$loc[$i]]."".$lit." ";
}
Thank you so much for any help.
You want something like $context = substr($order,from,length)
How to calculate from and length?
Use stripos (and arithmetic) to calculate from. Beware it isn't less than 0. Review substr doc for the why).
Use strlen (of the "needle") and arithmetic to determine the length.
Hi i need to save a 010 number in $number and if i do like this php will remove the starting 0
$number = 010
And echo of this will return 10 how can i make it not to remove the initial 0
BR
Martin
Use it as a String:
$number = '010';
Use str_pad() function.
echo str_pad('10',3,'0',STR_PAD_LEFT)
http://php.net/manual/en/function.str-pad.php
Do remember that numbers starting with 0 can also be treated as octal number notation by the PHP compiler, hence if you want to work with decimal numbers, simply use:
$num = '010';
This way the number is saved, can be stored in the database and manipulated like any other number. (Thx to the fact that PHP is very loosely typed language.)
Another method to use would be:
Save number as $num = 10;
Later while printing the value you can use sprintf, like:
sprintf("%03d", $i);
This will print your number in 3 digit format, hence 0 will be added automatically.
Another method:
<?php
$num = 10;
$zerofill = 3;
echo str_pad($num, $zerofill, "0", STR_PAD_LEFT);
/* Returns the wanted result of '010' */
?>
You can have a look at the various options available to you and make a decision. Each of the method given above will give you a correct output.
What I am doing is taking a vehicle VIN number and taking the last 6 digits of it and storing it as a stock number. The issue I have is I have a function that goes and checks the database to make sure that stock number exists. If it does (can have the same vehicle in inventory again from buy back, etc) I want to concat at the end of the sting A through Z.
if(strlen($vin) > 9) {
$stocknum = substr($vin,-6);
while(verfiyUnique($mysqli, $stocknum) != true) {
if(strlen($stocknum < 7)) {
$stocknum = substr($vin,-6) . "A";
}else{
?
}
}
return $stocknum;
How do I increment lets say A to B or B to C if it does match?
Thanks in advance for your help!
You could increment the ascii number and use the chr() function to convert it to the relevant character. E.g.: chr(65) would output A
See http://php.net/manual/en/function.chr.php for more info as well as a link to an ASCII table.
You could also use $letters = range('A','Z') to create an array of uppercase letters and then increment an index variable to access the array. E.g.: $letters[$i] would output A
There is a problem in Interview Street challange. Maybe the most easiest of all challenges. "Unfriendly Numbers", is the name and question goes like this.
There is one friendly number and N unfriendly numbers. We want to find how many numbers are there which exactly divide the friendly number, but does not divide any of the unfriendly numbers.
Input Format:
The first line of input contains two numbers N and K seperated by spaces. N is the number of unfriendly numbers, K is the friendly number.
The second line of input contains N space separated unfriendly numbers.
Output Format:
Output the answer in a single line.
I did a PHP programming like this:
<?php
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
$handle = fopen ("php://stdin","r");
$input = fgets($handle);
$num_unfriendly_number=substr($input,0,1);
$friendly_number=substr($input,2,1);
$input2=fgets($handle);
for($i=0;$i<=($num_unfriendly_number); $i=$i+2){
$unfriendly_numbers[$i]=substr($input2,$i,1);
}
//truncates additional input
//now getting divisiors of given friendly numbers
$check_num=1;
//one is always a divisor of any number
$divisior[0]=1;
$arrayindex=1;
for($check_num; $check_num<=$friendly_number; $check_num++){
$hold_var=$friendly_number%$check_num;
if($hold_var==0){
$divisor[$arrayindex]=$check_num;
$arrayindex++;
}
}
$index=0;
foreach($divisor as $test_div){
$output=true;
foreach($unfriendly_numbers as $test_unfrnd){
if($test_unfrnd%$test_div){
$output=false;
}
}
if ($output){
$outputarray[$index]=$test_div;
$index++; //edited afterwards after #Boris's suggestion but didn't work :(
}
}
$num_of_output=count($outputarray);
define('STDOUT',fopen("php://stout","r"));
fwrite(STDOUT,$num_of_output);
?>
The above programme worked fine for 2 testcases but did not applied for other tests. I did some research but did not found any errors. Any helps please. Thanks in advance.
Fist of all I would like to mention that I do not know php. However, I think this is simple enough I can try to help.
Several errors I see:
for($i=0;$i<=($num_unfriendly_number); $i=$i+2){
$unfriendly_numbers[$i]=substr($input2,$i,1);
}
Here you use substr($input2,$i,1);, this however assumes all your unfriendly numbers are digits, which might not always be the case. Better use the split function in php. Replace the whole while with the following:
$unfriendly_numbers = explode(" ", $input2);
After that:
$index=0;
foreach($divisor as $test_div){
$output=true;
foreach($unfriendly_numbers as $test_unfrnd){
if($test_unfrnd%$test_div){
$output=false;
}
}
if ($output){
$outputarray[$index]=$test_div;
}
}
Here you never increase the $index variable. Isn't this meaning that you will override the divisors one with other? USe the operator []=. It appends to an array in php:
if ($output){
$outputarray []= $test_div;
}
EDIT One more error I see is that you count on the friendly number to be a digit too. You can fix this too:
$friendly_number=substr($input,2,1);
->
$friendly_number=explode(" ", $input)[0];
I have the same problem I can't understand why this code can't finish in less than 16 seconds!
I would like to hear your tricks
a = raw_input()# this will read this line: 8 16
b = raw_input()# this will read this line: 2 5 7 4 3 8 3 18
al = a.split()
bl = b.split()
blint = []
fn = int(al[1])
fnlist = [fn]
half_fn = fn / 2 # only I go to half the number to save some time
k = 1
while k <= half_fn:
if fn % k == 0:
fnlist.append(k)
k += 1
plist = []
for j in bl:
blint.append(int(j)) # here I changed the bl list elements which are string to int
for i in fnlist:
for j in blint: #I have the int elements so I don't need every time bring the string and change it to int
if j % i == 0:
plist.append(i)
break
counter = len(fnlist) - len(plist)
print counter
I need help to change a character in php.
I got some code from the web:
char dest='a';
int conv=(int)dest;
Can I use this code to convert a character into numeric? Or do you have any ideas?
I just want to show the result as a decimal number:
if null == 0
if A == 1
Use ord() to return the ascii value. Subtract 96 to return a number where a=1, b=2....
Upper and lower case letters have different ASCII values, so if you want to handle them the same, you can use strtolower() to convert upper case to lower case.
To handle the NULL case, simply use if($dest). This will be true if $dest is something other than NULL or 0.
PHP is a loosely typed language, so there is no need to declare the types. So char dest='a'; is incorrect. Variables have $ prefix in PHP and no type declaration, so it should be $dest = 'a';.
Live Example
<?php
function toNumber($dest)
{
if ($dest)
return ord(strtolower($dest)) - 96;
else
return 0;
}
// Let's test the function...
echo toNumber(NULL) . " ";
echo toNumber('a') . " ";
echo toNumber('B') . " ";
echo toNumber('c');
// Output is:
// 0 1 2 3
?>
PS:
You can look at the ASCII values here.
It does indeed work as in the sample, except that you should be using php syntax (and as a sidenote: the language that code you found most probably was, it did not do the same thing).
So:
$in = "123";
$out = (int)$in;
Afterwards the following will be true:
$out === 123
This may help you:
http://www.php.net/manual/en/function.ord.php
So, if you need the ASCII code you will need to do:
$dest = 'a';
$conv = ord($dest);
If you want something like:
a == 1
b == 2
.
.
.
you should do:
$dest = 'a';
$conv = ord($dest)-96;
For more info on the ASCII codes: http://www.asciitable.com/
And for the function ord: http://www.php.net/manual/en/function.ord.php
It's very hard to answer because it's not a real question but just a little bit of it.
But if you ask.
It seems you need some translation table, that defines links between letters and numbers
A -> 2
B -> 3
C -> 4
S -> 1
or whatever.
You can achieve this by using an array, where keys would be these letters and values - desired numbers.
$defects_arr = array(
'A' -> 2,
'B' -> 3,
'C' -> 4'
'S' -> 1
};
Thus, you can convert these letters to numbers
$letter = 'A';
$number = $defects_arr($letter);
echo $number; // outputs 1
But it still seems is not what you want.
Do these defect types have any verbose equivalents? If so, why not to use them instead of letters?
Telling the whole story instead of little bit of it will help you to avoid mistakes and will save a ton of time, both yours and those who to answer.
Out of this question, if you are looking for convert RT0005 to 5
$max = 'RT0005';
return base_convert($max,10,10);
// return 5