Update array with post values - php

Question

im currently trying to update an array with values from another one.
Basically there is a form where you can update data for an object, the form sends a json array like so:
{
"name": "Test2",
"address": "Adresas 2",
"object_id": "44",
"job_id": [
"31",
"33"
],
"amount": [
"500",
"500"
]
}
My goal is to update another array that is being fetched from the database with values of job_idd and amount.
The array from database looks like so:
{
"jobs": [
{
"id": "31",
"amount": "500",
"have": 250
},
{
"id": "33",
"amount": "500",
"have": 0
}
]
}
I need to update the second array values "amount" with the posted values from the first array "amount", but so that the second array still has the original "have" values
I tried using nested foreach method:
$object_id = $_POST['object_id'];
$data = json_encode($_POST);
$json = json_decode($data, true);
$i = 0;
foreach($json['job_id'] as $item) {
$job_id = $item;
$query33 = "SELECT * FROM `objektai` WHERE id='$object_id'";
$result33 = mysqli_query($conn, $query33) or die(mysqli_error($conn));
while($row2 = mysqli_fetch_array($result33)){
$job_info = $row2['info'];
}
$json_22 = json_decode($job_info, true);
foreach ($json_22['jobs'] as $key2 => $entry2) {
$have = $json_22['jobs'][$key2]['have'];
}
$result["jobs"][] = array(
'id' => $job_id,
'kiekis' => $json['amount'][$i],
'turima' => $have,
);
$i++;
}
Usinng the example above the foreach prints the values 2 times and my updated json "have"
has a value of 0, the "amount" entries are updated correctly
Thanks in advance for you help!
UPDATE
adding var_export($_POST):
array ( 'name' => 'Test2',
'address' => 'Adresas 2',
'object_id' => '44',
'job_idd' => array (
0 => '31',
1 => '33',
),
'darbo_kiekis' => array (
0 => '500',
1 => '500',
),
)

Answer 1

When you're looping through the array from the database, you need to compare the id value with $obj_id.
I've also shown below how to use a prepared statement to prevent SQL injection.
I've removed lots of unnecessary code:
No need to convert $_POST to/from JSON.
Use $i => in the foreach loop to get the array index.
You don't need a while loop when processing the query results if it only returns one row.
You don't need $key2, you can just use $entry2.
$object_id = $_POST['object_id'];
$query33 = "SELECT * FROM `objektai` WHERE id = ?";
$stmt33 = $conn->prepare($query33);
$stmt33->bind_param('i', $job_id);
foreach($_POST['job_id'] as $i => $job_id) {
$stmt33->execute();
$result33 = $stmt33->get_result();
$row2 = $result33->fetch_assoc();
$job_info = $row2['info'];
$json_22 = json_decode($job_info, true);
foreach ($json_22['jobs'] as $entry2) {
if ($entry2['id'] == $job_id) {
$result["jobs"][] = array(
'id' => $job_id,
'kiekis' => $json['amount'][$i],
'turima' => $entry2['have']
);
}
}
}