I'm trying to get data from the database using ajax to insert it in other element but the post data not passing to get-data.php
so what the reason can be and the solution
addBuilding.php
<?php
require_once("./dbConfig.php");
$selectIL = "SELECT * FROM iller ";
$selectIL = $db->prepare($selectIL);
$selectIL->execute();
$res = $selectIL->get_result();
?>
<form action="" method="post">
<select name="pp" id="cites">
<option value="">-select state-</option>
<?php
while ($row = $res->fetch_assoc()) {
?>
<option value="<?= $row['id'] ?>"><?= $row['il_adi'] ?></option>
<?php
}
?>
</select>
<select name="district" id="district">
<option value="">-select district-</option>
</select>
</form>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<script src="getdata.js"></script>
getdata.js
$(document).ready(function() {
$("#cites").change(function() {
if ( $("#cites").val()!="") {
$("#district").prop("disabled",false);
}else {
$("#district").prop("disabled",true);
}
var city = $("#cites").val();
$.ajax({
type: "POST",
url:"get-data.php",
data:$(city).serialize(),
success: function(result) {
$("#district").append(result);
}
});
});
});
get-data.php
I can see the form data in network inspection put no data passing to get-data.php
<?php
require_once("./dbConfig.php");
if (isset($_POST['pp'])) {
$cites = $_POST['cites'];
$selectIlce = "SELECT * FROM ilceler where il_id=? ";
$selectIlce = $db->prepare($selectIlce);
$selectIlce->bind_param("i", $cites);
$selectIlce->execute();
$res = $selectIlce->get_result();
?>
<?php
while ($row = $res->fetch_assoc()) {
?>
<option value="<?= $row['id'] ?>"><?= $row['ilce_adi'] ?></option>
<?php
}
}
?>
You need to echo the results in get-data.php
<?php
while ($row = $res->fetch_assoc()) {
?>
echo "<option value='". $row["id"]."'>".$row['ilce_adi']."</option>";
<?php
}
}
?>
1- Get data by serialize from form:
$("form").serialize()
2- Add dataType: "json" to ajax option:
$.ajax({
type: "POST",
url:"get-data.php",
data:$(city).serialize(),
dataType: "json",
success: function(result) {
$("#district").append(result);
}
});
Related
I have this select , i wanna save each value after change , save it and use in other select
This is my code :
<?
$sql = "SELECT * FROM championnat ";
$result = $conn->query(sprintf($sql));
if($result){
if ($result->num_rows != 0)
{
$rows=array();
?>
<select name="nom_championnat" id="nom_championnat" >
<option value=""></option>
<?php
while($r=mysqli_fetch_assoc($result))
{
?>
<option value=" <?php echo $r['idChampionnat']?>" name="nom_championnat" selected >
<?php echo $r['nomChampionnat'] ?></option>
<?php
}
}
}
?>
</select>
</div>
I need the variable $r['idChampionnat'] to save it in each select and use it in this requete , how can it asve and put it in that requete sql ????
<?php
$sql = "SELECT * FROM equipe where idChampionnat=???? ";
$result = $conn->query(sprintf($sql));
if($result){
if ($result->num_rows != 0)
{
$rows=array();
?>
<select name="equipe1" >
<option value=""></option>
<?php
while($r=mysqli_fetch_assoc($result))
{
?>
<option required value=" <?php echo $r['nomEquipe']?>" name="equipe1" selected ><?php echo $r['nomEquipe'] ?>
</option>
<?php
}
}
}
?>
</select>
just to clear it ,
You need to use jQuery to fire an AJAX call when the first box is selected.
Its been a while since I've done this but this should give you some idea. I took some code from here and here as example
Say your html looks like this
<select id="nom_championnat">
<option value="value1">value1</option>
<option value="value2">value2</option>
</select>
<select id="equipe1"></select>
then you need to tell jquery what to do when nom_championnat changes selection
$('#nom_championnat').change(function() {
var data = "";
$.ajax({
type:"POST",
url : "queryfile.php",
data : "value="+$(this).val(),
async: false,
success : function(response) {
data = response;
return response;
},
error: function() {
alert('Error occured');
}
});
var string = data.message.split(",");
var array = string.filter(function(e){return e;});
var select = $('equipe1');
select.empty();
$.each(array, function(index, value) {
select.append(
$('<option></option>').val(value).html(value)
);
});
});
and then you need a queryfile.php to handle the ajax requests, something like
<?php
print_r($_POST);
$value = $_POST["value"];
$sql = "select where {$value} ..."
$result = execute($sql);
echo $result;
?>
My table is not displayed when i select any project name. I guess the onchange function is not working properly but i couldn't figure out the problem.
Code is as follows:
<div class="span6">
<?php $sql = "SELECT * from login_projects WHERE login_id='".$record['login_id']."'";
$res_sql = mysql_query($sql); ?>
<label>Project Name <span class="f_req">*</span></label>
<!--<input type="text" name="city" class="span8" />-->
<select name="project_name" onchange="get_list_onnet()" id="project_name" class="span8">
<option value="">--</option>
<?php while($rec_sql = mysql_fetch_array($res_sql)){ ?>
<option value="<?php echo $rec_sql['project_id']; ?>">
<?php echo $rec_sql['project_name']; ?></option>
<?php } ?>
</select>
</div>
Function:
<script>
function get_list_onnet(){
var project_name=$("#project_name").val();
$.ajax
({
type: "POST",
url: "ajax.php",
data: {action: 'get_list_onnet',list_onnet:project_name},
success: function()
{
document.getElementById("dt_a").style="block";
$("#dt_a").html(html);
}
});
};
</script>
<script>
$(document).ready(function() {
//* show all elements & remove preloader
setTimeout('$("html").removeClass("js")',1000);
});
</script>
Ajax.Php Page:
function get_list_onnet(){
$list_onnet=$_POST['list_onnet'];
$sql_list_onnet=mysql_query("SELECT * from projects,project_wise_on_net_codes
where projects.project_id = project_wise_on_net_codes.project_id AND
project_wise_on_net_codes.project_id='$list_onnet'");
$row1 = mysql_num_rows($sql_list_onnet);
if($row1>0)
{
echo "<tr><th>id</th><th>Project Name</th><th>Country Code</th><th>On-net prefix</th>
<th>Action</th></tr>";
$k = 1; while($row_list_onnet=mysql_fetch_array($sql_list_onnet))
{
$project3 = $row_list_onnet['project_name'];
$countrycode1 = $row_list_onnet['country_code'];
$prefix1 = $row_list_onnet['on_net_prefix'];
$id_proj = $row_list_onnet['project_id'];
$on_prefix = $row_list_onnet['on_net_prefix'];
echo "<tr><td>".$k."</td><td>".$project3."</td><td>".$countrycode1."</td>
<td>".$prefix1."</td><td><a href='process/update_process_onnet.php?ID=".$id_proj."&Onnet=".$on_prefix."'>Delete</a></td>
</tr>";
$k++;
}
}
else
{
echo "<script>alert('No Record Found')</script>";
}
}
The problem is that it is always going in the else condition and nothing is displayed in the table.
Here is the code snippet :
<select name="isbn" onchange=" ">
<?php
//Displaying all ISBN in drop down
$result = mysqli_query($con,"SELECT * FROM book");
while($row = mysqli_fetch_array($result)) {
?>
<option> <?php echo $row['ISBN']; ?></option>
<?php } ?>
</select>
</label></td>
</tr>
<tr>
<td>Copy Number </td>
<td><select name="copy_number">
<?php
//Now based on selected book I want to fetch number of copies from database
$result = mysqli_query($con,"SELECT number_of_copies FROM book where isbn = [ SELECTE VALUE FROM ABOVE]");
?>
How can I do that?
You can do that with jQuery ajax and simple php handler to get copies of selected book,
<select name="isbn">
.....
</select>
<div id="copies"></div>
<script>
$.ajax({
url: "getCopies.php?",
data: "isbn=" + $("select[name='isbn']").val(),
type: "POST",
dataType: "json",
success: function(response) {
$.each(response, function(i, item) {
$("#copies").append(item.name); // Sample json format {id: "213123", name:"Lord of the rings", isbn:"887799..."}
})
}
});
</script>
getCopies.php
<?php
$isbn = $_POST["isbn"];
// Some db connections
$result = mysqli_query($con,"SELECT number_of_copies FROM book where isbn = $isbn");
$resultArr = array();
while($row = mysqli_fetch_array($result)) {
$resultArr[] = $row;
}
echo json_encode($resultArr); // This will return rows in json format. You can iterate it in js side
I've a html form where the countries in the drop down are coming from a database. If user selects any country, then the city drop diwn will appear based on selected country.
If user wrongly input any field of the form (there are other field in this form) then country drop down will will remember which country the user initially selected, but clears the city, resetting it to --Select City--. I'm trying to selected the city name but I can't. Any idea ?
Ajax Code here:
<script type="text/javascript" src="http://ajax.googleapis.com/
ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
$(".country").change(function()
{
var id=$(this).val();
var dataString = 'id='+ id;
$.ajax
({
type: "POST",
url: "ajax_city.php",
data: dataString,
cache: false,
success: function(html)
{
$(".city").html(html);
}
});
});
});
</script>
ajax_city.php here
<?php
require_once("toplevel/content/database/databd.php");
if($_POST['id'])
{
$id=$_POST['id'];
$sql=mysql_query("select Name from cities WHERE CountryCode ='$id'");
while($row=mysql_fetch_array($sql))
{
$id=$row['Code'];
$data=$row['Name'];
if($_POST['city'] == $data)
{
$sel = 'selected = "selected"';
}
else
{
$sel = " ";
}
echo '<option value="'.$data.'" ' .$sel . ' >'.$data.'</option>';
}
}
?>
Html form here:
<tr>
<td>PAYS <span style="color: #FF0000;">*</span></td>
<td>
<select name="country" class="country">
<option value="">Select</option>
<?php
$sql=mysql_query("select * from country");
while($row=mysql_fetch_array($sql))
{
$id=$row['Code'];
$data=$row['Name'];
$data = mb_convert_encoding($data, 'UTF-8');
if($id == $_POST['country'])
{
$sel = 'selected="selected"';
}
else
{
$sel = "";
}
echo '<option value="'.$id.'"' . $sel . '>'.$data.'</option>';
}
?>
</select>
</td>
</tr>
<tr>
<td>City</td>
<td>
<select class="city" name="city">
<option selected="selected" value="">--Select City--</option>
</select>
</td>
</tr>
Not quite sure but issue is in datastring try changing this:
$(".country").change(function(){
var id=$(this).val();
var dataString = {'id': id};
$.ajax({
type: "POST",
url: "ajax_city.php",
data: dataString,
cache: false,
success: function(html){
$(".city").html(html);
}
});
});
You will need to rebuild your HTML on reload, but now with your City list (this is untested, but based on your code from the Country dropdown):
<tr>
<td>City</td>
<td>
<select class="city" name="city">
<option selected="selected" value="">--Select City--</option>
<?php
if (isset($_POST['city']) {
$sql=mysql_query("select * from city");
while($row=mysql_fetch_array($sql))
{
$id=$row['Code'];
$data=$row['Name'];
$data = mb_convert_encoding($data, 'UTF-8');
if($id == $_POST['city']) { $sel = 'selected="selected"'; }
else { $sel = ""; }
echo '<option value="'.$id.'"' . $sel . '>'.$data.'</option>';
}
}
?>
</select>
</td>
</tr>
WARNING: This is just same sample code. This should never ever go into production, because it has the potential for being extremely unsafe! As #PolishPrince has pointed out above, you should at least use PDO or MySQLi.
I have an HTML text input field - for example:
<input id="CustID" name="CustID" dir="rtl" value="<? echo $CustID;?>" size="35" required="true" maxlength="9" >
When I insert the number of the user, I need to open a select box to show all ticket for this user.
for example
<select name="ticket" id="ticket" >
<?
$query="SELECT * FROM ticket where CustID='$CustID' ";
$result=mysql_query($query) or die("error: " . mysql_error());
while($row=mysql_fetch_array($result))
{
?>
<option value="<?php echo $row['ticket'] ; ?>"><?php echo $row['ticket'] ; ?></option>
<? } ?>
</select>
How can i use this with AJAX?
This is what I have so far:
<script src="js/jquery.js"></script>
<script language="javascript">
function getData(id) {
$.ajax ({
url: "php_page.php",
type: "POST",
data: {custid:id},
success: function(data){
$("#return").html(data)
}
)} // i have error her why ??
}
</script>
<input type="text" value="<?php echo $CustID;?>" onkeyup="getData(this.value)"/>
<?
include("functions/connect.php");
$query = "select * from customers2 , tickets where customers2.CustID='".$CustID."' and tickets.CustNo=customers2.CustomersNo";
$result=mysql_query($query) or die("error: " . mysqli_error());
while($row=mysql_fetch_array($result))
{
?>
<option value="<?php echo $row['ticket'] ; ?>"><?php echo $row['ticket'] ; ?></option>
<? } ?>
</select>
Put your php on a separate page called php_page.php. Create your ajax call using the jquery library on your display page:
function getData(id) {
$.ajax ({
url: "php_page.php",
type: "POST",
data: {custid:id},
success: function(data){
$("#return").html(data)
}
)}
}
On your form page create a div with id "return" where you want your select options to show up and also call this function either with a button click or onkeyup:
<input type="text" value="<?php echo $CustID;?>" onkeyup="getData(this.value)"/>
Oh, and your mysql connect should use the mysqli library:
$con=mysqli_connect($host,$username,$password,$database);
$query = //same as before
$result=mysqli_query($query) or die("error: " . mysqli_error());
while($row=mysqli_fetch_array($result))
{
?>
<option value="<?php echo $row['ticket'] ; ?>"><?php echo $row['ticket'] ; ?></option>
<? } ?>
</select>
use AJAX to pass CustID to Select page.
i.e
index.php
<script>
function callAjax(str)
{
ajax
}
</script>
<input type = "text" name = "CustID" onblur="callAjax()"/>
<div id = "show">where to display the ajax results</div>
ajax.php
all that code with the select and options.
i will do but the result is get me all record on select and i wont only record of the user i enter ID
index.php
<script src="js/jquery.js"></script>
<script language="javascript">
function getData(id) {
$.ajax ({
url: "php_page.php",
type: "GET",
data: {custid:id},
success: function(data){
$("#return").html(data)
}
})
}
</script>
<input type="text" id="CustID" name="CustID" onkeyup="getData(this.value)"/>
<div id="return"></div>
php_page.php
<select>
<option value="">عرض الكل</option>
<?
include("functions/connect.php");
if(isset($_GET['CustID']))
{
$CustID = $_GET['CustID'];
$sql_check = mysql_query("select * from customers2 , omra , haj , tickets where customers2.CustID='".$CustID."' and tickets.CustNo=customers2.CustomersNo") or die(mysql_error());
if(mysql_num_rows($sql_check)){
while($rows = mysql_fetch_array($sql_check)){
?>
<option value="<?php echo $rows['TicketType'] ; ?>">تذكرة <?php echo $rows['TicketType'] ; ?> برقم <?php echo $rows['TicketRealNo'] ; ?></option>
<? } } ?>
</select>
<? } ?>