pass array to sql insert query php - php

Question

i have a sql query to insert data without col names :
$sql = "INSERT INTO test_table VALUES (null,1,2,3) ";
if (mysqli_query($conn, $sql)) {echo 'success!';}else {echo 'failed!';}
I want to insert 1,2,3 as array , something like this:
$data = [1,2,3];
$sql = "INSERT INTO test_table VALUES (null,$data) ";
if (mysqli_query($conn, $sql)) {echo 'success!';}else {echo 'failed!';}
I tried php implode function too, but it didn't worked. Any help will be appreciated. Thank you!

Answer 1

You didn't provide the table structure that it is going into, but if all you are wanting to solve for is having the $data array split into constituent parts you could do it several ways:
a) implode(), although you already mentioned trying it, should work just fine:
$data = [1,2,3];
$sql = "INSERT INTO test_table VALUES (null,".implode(',',$data).")";
b) reference each array index:
$data = [1,2,3];
$sql = "INSERT INTO test_table VALUES (null,{$data[0]},{$data[1]},{$data[2]})";
That only works if you have a set amount of values in the array however.
c) loop over the array:
$data = [1,2,3];
$sql = "INSERT INTO test_table VALUES (null"
foreach($data as $value){ $sql .= ",$value"; }
$sql .= ")";
Hope that helps, if not please provide more details about the structure of both the data going in and the database table so we can better understand the issue.