Connect to MySQL table using PHP (XAMPP) - php

Question

I am trying to make a CRUD in PHP. Apache and MySQL is still running.
class DB
{
static private $connection;
const DB_TYPE = "mysql";
const DB_HOST = "localhost";
const DB_NAME = "crud";
const USER_NAME = "root";
const USER_PASSWORD = "";
static public function getConnection()
{
if (static::$connection == null) {
try {
static::$connection = new PDO(self::DB_TYPE . "host" . self::DB_HOST . "dbname" . self::DB_NAME . self::USER_NAME . self::USER_PASSWORD);
} catch (Exception $exception) {
throw new Exception("connection failed");
}
}
return static::$connection;
}
}
I am running on localhost:3306
phpMyAdmin is up and running
The output is in the picture
output:

Answer 1

Your PDO invocation looks weird.
static::$connection = new PDO(self::DB_TYPE . "host" . self::DB_HOST . "dbname" . self::DB_NAME . self::USER_NAME . self::USER_PASSWORD);
The construct for this is new PDO($dsn, $user, $password);
The dsn has this format:
mysql:dbname=testdb;host=127.0.0.1;port=3333 then , user then , password
Your dsn section seems wrong, it should be more like this:
$dsn = 'mysql:dbname='. self::DB_NAME .';host=' . self::DB_HOST ;
$user = self::USER_NAME;
$password = self::USER_PASSWORD;
$dbh = new PDO($dsn, $user, $password);

Answer 2

I think you forgot spaces and signs in your connection arguments
That is your syntax :
new PDO(self::DB_TYPE . "host" . self::DB_HOST . "dbname" . self::DB_NAME . self::USER_NAME . self::USER_PASSWORD);
Which give :
"mysqlhostlocalhostdbnamecrudroot"
This is the syntax from the doc :
$dbh = new PDO('mysql:host=localhost;dbname=test', $user, $pass);