How to display two or more array on same table - php

Question

Hey guys I have one mysql table tick where i have some info like user id now to display that data I need to retrieve from user table name of the user based on that id
?php
$mysql5 = mysqli_query($dbc, "SELECT * FROM tick where status='1' ORDER BY dt DESC LIMIT 6 ");
if($indtbl = mysqli_fetch_array($mysql5))
{
$title = $indtbl['tickettitle'];
$company = $indtbl['companyname'];
$companyid =$indtbl['compid'];
$trackid = $indtbl['trackid'];
$assignto = $indtbl['assignto'];
$priority = $indtbl['priority'];
}
?>
and user table query is based on first one
<?php
$findresults2323 = mysqli_query($dbc, "SELECT * FROM users WHERE id= '$assignto'");
if($rest = mysqli_fetch_array($findresults2323))
{
$userimg = $rest['img'];
$fname1 = $rest['fname'];
$lname1 = $rest['lname'];
}
?>
now the problem is when i am fetching the array
<thead>
<tr>
<th class="text-left">Title</th>
<th>Company</th>
<th>Ticket ID</th>
<th>Assign To</th>
<th>Priority</th>
</tr>
</thead>
<?php
while($rowten = mysqli_fetch_array($mysql5)) {
$retrive11 = mysqli_fetch_array($findresults23);
?>
<tr>
<td><a href="readit.php?id=<?php echo $rowten["id"];?>"><?php echo $rowten["tickettitle"]; ?></td>
<td><a href="readit.php?id=<?php echo $rowten["id"];?>"><?php echo $rowten["companyname"];?> <?php echo $rowten["compid"];?></td>
<td><a href="readit.php?id=<?php echo $rowten["id"];?>"><?php echo $rowten["trackid"]; ?></td>
<td><a href="readit.php?id=<?php echo $rowten["id"];?>"><?php echo $retrive11['fname'];?></td>
<td><a href="readit.php?id=<?php echo $rowten["id"];?>"><?php echo $rowten["priority"]; ?></td>
</tr>
<?php
}
?>
i am getting the error
Notice: Trying to access array offset on value of type null on line 459
line 459 is
<td><a href="readit.php?id=<?php echo $rowten["id"];?>"><?php echo $retrive11['fname'];?></td>
what I am doing wrong

Answer 1

In order to use 2 queries, you need to run the second query inside of the loop so it retrieves the specific user record for the given result from the tick query.
while($rowten = mysqli_fetch_array($mysql5)) {
$assignto = $rowten['assignto'];
$findresults2323 = mysqli_query($dbc, "SELECT * FROM users WHERE id= '$assignto'");
$retrive11 = mysqli_fetch_array($findresults23);
However, this is very inefficient as it requires a query on the user table for every result in the tick query. The proper way of doing this is to use a single query with a join.
SELECT tick.*, users.fname FROM tick LEFT JOIN users ON (tick.assignto=users.id) where tick.status='1' ORDER BY tick.dt DESC LIMIT 6
The result of this query will have all the data from both your queries in one result.