How to echo an error message using $_GET in php - php

Question

[SOLVED]: This code is functional, i made a mistake by displaying an old version of my .php page into the browser, which didn't have the updated code below. I would like to echo an error 'error' produced from my php code which is meant to validate a sign in form, into the page of the sign in form, the error appears in the URL only , for example : signin.php?error= User name is incorrect. So i would like the same message to appear within the sign in form itself , i tried to use $_GET['error'] and echo'ed it within my form,
<form method="post" onsubmit=" return formSubmit() " action="signinphp.php">
<div class="userimage">
<img class="userlogo" src="image/userlogo.png" alt="Picture- User Profile picture">
</div><br>
<?php if (isset($_GET['error'])){?>
<p class="error"><?php echo $_GET['error'];?></p>
<?php } ?>
<div class="error" id= "errorMsg"></div> <br>
<div class="error" id= "errorMsg1"></div>
<div class="field">
<label class="stafflabel"> Staff Name </label>
<input class="area" placeholder="staffmember or admin" onclick=" return userValidation()" onchange=" return userValidation()" id="staff" name="staffname" type="text" >
</div> <br>
<div class="error" id= "errorMsg2"></div>
<div class="field">
<label class="passlabel"> Password </label>
<input class="area" placeholder="password" onclick=" return userValidation()" onchange=" return userValidation()" id="pass" name="password" type="password" >
</div><br>
<div class="checkbox">
<input type="checkbox" class="remember-me">
<label class="remember" for="remember-me">Remember me </label>
<a class="pass-link" href="#"> Forgot password?</a>
</div><br><br><br>
<div class="field">
<input class="btn" onclick="check(this.form)" type="submit" value="Sign in">
</div> <br>
<div class="account-link">
Didn't create an account yet? Create Account
</div>
</form>
PHP
<?php
if (isset($_POST['staffname'])&& isset($_POST['password'])){
function validate($data){
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
$staffname = validate($_POST['staffname']);
$pass= validate($_POST['password']);
if (empty($staffname)){
header("Location:signin2.php?error=Staff name and password are required!");
exit();
} else if (empty($pass)){
header ("Location:signin2.php?error=Staff name and password are required!");
exit();
} else {
if ($staffname == "staffmember" && $pass== "letmein!123"){
echo "Logged in!";
header("Location: log-it-reportsbeta.php");
exit();
}
else if ($staffname == "admin" && $pass== "heretohelp!456"){
echo "Logged in!";
header("Location: sql_select_updated.php");
exit();
}
}
}
else{
header("Location: signin2.php");
exit();
}
but it did not work , i provided my form code below and the php code for the form validation, please take a look , thank you.

Answer 1

You may wanna use an extra condition to get an error message instead of passing the whole error string in your URL.
In your php script :
if (empty($staffname)){
header("Location:signin2.php?error=1");
exit();
} else if (empty($pass)){
header ("Location:signin2.php?error=2");
exit();
}
In your form :
if (isset($_GET['error'])) {
if ($_GET['error'] == 1) {
$message = "Staff name and password are required!";
}
else if ($_GET['error'] == 2) {
$message = "Another error message";
}
echo '<p class="error">'.$message.'</p>';
}