How to fix HTTP 500 Error during Form Submission? [duplicate] - php

Question

This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
How do I get PHP errors to display?
(27 answers)
Closed 12 months ago.
I created a form with the following fields I am getting a HTTP ERROR 500 message when I hit SUBMIT button on my form. I have created the database as a MySQL database with 4 fields. My PHP code looks like below.
<?php
$yname = $_POST['yname'];
$pname = $_POST['pname'];
$details = $_POST['details'];
$links = $_POST['links'];
if (!empty($yname) || !empty($pname) || !empty($details) || !empty($links)) {
$host = "localhost";
$dbUsername = "u172756077_admin";
$dbPassword = "";
$dbname = "u172756077_Form";
$conn = new mysqli($host, $username, $dbPassword, $dbname);
if (mysqli_connect_error()) {
die('Connect Error('. mysqli_connect_errno().')'.mysqli_cnnect_error());
}
else {
$SELECT = "SELECT pname From form Where pname = ? Limit 1";
$INSERT = "INSERT Into form (yname, pname, details, links) values(?, ?, ?, ?)";
$stmt = $conn->prepare($SELECT);
$stmt->bind_param("s", $pname);
$stmt->execute();
$stmt->bind_result($pname);
$stmt->store_result();
$stmt->fetch();
$rnum = $stmt->num_rows;
if ($rnum == 0) {
$stmt->close();
$stmt = $conn->prepare($Insert);
$stmt->bind_param("ssss",$yname, $pname, $details, $links);
if ($stmt->execute()) {
echo "New record inserted sucessfully.";
}
else {
echo $stmt->error;
}
}
else {
echo "Someone already registers using this email.";
}
$stmt->close();
$conn->close();
}
}
else {
echo "All fields are required.";
die();
}
else {
echo "Submit button is not set.";
}
?>