Find Logic from String using Regex - php

Question

i want to get logic from string that what from input string. For example:
Input:
pageType == "static" OR pageType == "item" AND pageRef == "index"
How to i get logic like:
0 => pageType == "static"
1 => pageType == "item"
2 => pageRef == "index"
The logic clause must be complete based on what is entered.
I place like this:
$input = 'pageType == "static" OR pageType == "item" AND pageRef == "index"';
preg_match_all('/(.+)(?!AND|OR)(.+)/s', $input, $loX);
var_dump($loX);
but the array just show:
0 => pageType == "static" OR pageType == "item" AND pageRef == "index"
1 => pageType == "static" OR pageType == "item" AND pageRef == "index
2 => "
Please help me, thanks ^_^

Answer 1

One option is to make use of the \G anchor and a capture group:
\G(\w+\h*==\h*"[^"]*")(?:\h+(?:OR|AND)\h+|$)
The pattern matches:
\G Get continuous matches asserting the position at the end of the previous match from the start of the string
(\w+\h*==\h*"[^"]*") Match 1+ word characters == and the value between double quotes
(?: Non capture group for the alternatives
\h+(?:OR|AND)\h+ Match either OR or AND between spaces
| Or
$ Assert the end of the string
) Close the group
Regex demo | Php demo
$re = '/\G(\w+\h*==\h*"[^"]*")(?:\h+(?:OR|AND)\h+|$)/';
$str = 'pageType == "static" OR pageType == "item" AND pageRef == "index"';
preg_match_all($re, $str, $matches);
print_r($matches[1]);
Output
Array
(
[0] => pageType == "static"
[1] => pageType == "item"
[2] => pageRef == "index"
)
Another option to get the results is to split on the AND or OR surrounded by spaces:
$result = preg_split('/\h+(?:OR|AND)\h+/', $str);