How do I get the content header from my POST? - php

Question

I'm trying to get the content header query string returned. I'm getting a response but it does not include the query string I am trying to pass. I'm running on an Apache server.
$postdata = http_build_query(
array(
'feed_them_social' => 'yes',
'refresh_token' => get_option( 'custom_refresh_token' ),
'time' => esc_html( get_option( 'custom_token_exp_time' ) ),
)
);
$opts = array('http' =>
array(
'method' => 'POST',
'header' => 'Content-type: application/x-www-form-urlencoded',
'content' => $postdata
)
);
$context = stream_context_create($opts);
$command = 'curl --data "' . $context . '" https://my-url.com';
exec($command, $token);
$output = implode('', $token);
print_r( $output );
Below is the response I'm getting.
Content-Length: 15
Content-Type: application/x-www-form-urlencoded
Accept: */*
Host: youtube-token-refresh.myurl.com
User-Agent: curl/7.77.0
I added this to php file on the server I am trying to get a response from. I just want to print out the header content with my query string for now but not having any luck. What am I missing?
$headers = apache_request_headers();
foreach ($headers as $header => $value) {
echo "$header: $value <br />\n";
}

Answer 1

Using exec is not secure and also it's a hard way to use curl.
In this case, I suggest file_get_contents function that works fine with stream_context_create. More Information: https://www.php.net/manual/en/function.file-get-contents.php
Just replace the last 4 lines with the following code.
$output = file_get_contents('https://my-url.com', false, $context);
print_r($output);