I'm fetching my songs from MySQL database and I'll be adding more song in the futures so I can't hard coded the max number so I'll be really appreciated if I can get any help or suggestion how to do it.
you can use the following query to get the total records in DB
$query = 'SELECT count(*) as total FROM song';
for checking if the max is reached
<? if ($page*$recordsPerPage < $total) : ?>
Next
complete example for hiding the next
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "test2";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if (!isset($_GET['id'])) {
$id = 1;
} else {
$id = (int)$_GET['id'];
}
$recordsPerPage = 10 ;
// $query = 'SELECT * FROM song WHERE 1 LIMIT ' . (($id - 1) * $recordsPerPage) . ' ' . $recordsPerPage;
//Here need to handle the songs data retreive
$sql = "select count(*) as total FROM songs";
$result = $conn->query($sql);
$data = $result->fetch_assoc();
if ($id*$recordsPerPage < (int)$data["total"])
echo "<a href='page/details.php?id=". ($id+1) ."'>Next</a>";
$conn->close();
Related
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "job_database";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error)
{
die("Connection failed: " . $conn->connect_error);
}
if(isset($_POST['Get']))
{
$jtitle = $_POST['jobtitle'];
$location = $_POST['location'];
$category = $_POST['categories'];
//Query specified database for value
$sql = "SELECT * FROM addjob where jtitle ='$jtitle' ∧ location ='$location' ∧ category ='$category' " ;
$result = $conn->query($sql);
}
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "jtitle: " . $row["jtitle"]. "location:" . $row["location"]. "category" . $row["category"]."<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
Change your sql query as follows,
$sql = "SELECT * FROM addjob WHERE jtitle =".$jtitle." AND location =".$location." AND category =".$category." ;
since ∧ is wrong, what it does is, it ends the SQL query because there is ; in the end. So change ∧ into and and check.
And read more about form validation and SQL injection from these links.
Good luck! =)
I have a database and I'm trying to sum up a column up to a specific point with say, LIMIT, and then return the sum value, but it's not working. This is what I have:
<?php
$servername = "localhost";
$username = "xxxxx";
$password = "xxxxxx";
$dbname = "xxxxxx";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die ("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT sum(donation_count) FROM (SELECT donation_count FROM users LIMIT 9) AS value_sum";
$result = $conn->query ($sql);
if ($result-> num_rows> 0) {
while ($row = $result->fetch_assoc()) {
echo '<div>'".$row['value_sum']."'</div>';
}
}
?>
SELECT sum(donation_count) as value_sum FROM (SELECT donation_count FROM users LIMIT 9) AS temp
MySQL database Start = "2017-03-29 01:30:00"
The problem is:
I print the $SQL and search the record in MySQL database, it can search the record. However, I need to debug and test if there is no result, it will be expected to echo "No". But, it always to echo "Yes" no matter I can get the record in MySQL or not.
How can I fixed it.
Main purpose: Get the record if there are and Echo "No" if there don't have record
<?php
$serverName = "localhost";
$username = "root";
$password = "";
$dbName = "fyp";
$tbName = "events";
$String_start = '2017-03-29 01:28:00';
$String_end = '2017-03-29 01:32:00';
$conn = new mysqli($serverName, $username, $password, $dbName);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//$staffID = $_SESSION['userID'];
$staff_ID = '15207800';
$sql = "SELECT *
FROM `$tbName`
WHERE `start` BETWEEN ('$String_start') AND ('$String_end')";
echo $sql;
$result=mysqli_query($conn,$sql);
if($result)
{
echo "Yes";
}
else{
echo "no";
}
?>
Mysql query only return fails if there is an issue, for successful execution it returns TRUE even if there is no record. You can achieve with follwing way
<?php
$serverName = "localhost";
$username = "root";
$password = "";
$dbName = "fyp";
$tbName = "events";
$String_start = '2017-03-29 01:28:00';
$String_end = '2017-03-29 01:32:00';
$conn = new mysqli($serverName, $username, $password, $dbName);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//$staffID = $_SESSION['userID'];
$staff_ID = '15207800';
$sql = "SELECT *
FROM `$tbName`
WHERE `start` BETWEEN ('$String_start') AND ('$String_end')";
echo $sql;
$result=mysqli_query($conn,$sql);
$num_rows = mysqli_num_rows($result);
if($num_rows > 0)
{
echo "Yes";
}
else{
echo "no";
}
?>
Use mysqli_num_rows that will return total results returned by the query. If total > 0 then results found else no results.
To fetch rows from MySQL result set, use mysqli_fetch_assoc
$result = mysqli_query($conn,$sql);
// $result contains result set and will return `TRUE` if query was successfully executed
// and will return `FALSE` only in case of error
$total = mysqli_num_rows($result);
if($total > 0)
{
echo "Yes";
// Fetch rows from mysql result set
while($row=mysqli_fetch_assoc($result))
{
print_r($row);
}
}
else
{
echo "no";
}
I want to do a query to get the last id (int) in a table to create a new row with that last id + 1 but actually this just put all rows with the same id
my code:
<?php
$servername = "localhost";
$user = "root";
$pass = "dbpass";
$dbname = "site";
$mail = $_POST['mail'];
$password = $_POST['password'];
// Create connection
$conn = mysqli_connect($servername, $user, $pass, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sqlID = "SELECT MAX(id) FROM `login`;";
if ($result = mysqli_query($conn, $sqlID)) {
$id = mysqli_fetch_row($result);
}
settype($id, "int");
$id = $id + 1;
$sql = "INSERT INTO login (`id`,`mail`,`password`)
VALUES ('".$id."','".$mail."','".$password."');";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
?>
mysqli_fetch_row returns always an array, also if there is only 1 element. So the MAX(id) in in $row[0].
Fixing this, you also don't need to use settype.
If your id is autoincrement, change this:
$sql = "INSERT INTO login (`id`,`mail`,`password`)
VALUES ('".$id."','".$mail."','".$password."');";
to:
$sql = "INSERT INTO login (`mail`,`password`)
VALUES ('".$mail."','".$password."');";
Then get rid of all code from $sqlID to $id + 1; (for tidyness)
I'd like to draw data from a table in my mysql, and put the data into a customized table. I would like to have the info into the table as http://gyazo.com/c6a40fcd6e4edc66f7f11650f641dae2. However when I'm trying it turns out very bad. Heres my coding.
<?php
$servername = "#";
$username = "#";
$password = "#";
$dbname = "#";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT minecraft_user, service FROM votes";
$result = $conn->query($sql);
echo '<div class="grid-40 vote-leaderboard"> <h3><i class="fa fa-star"></i>Recent Votes</h3> <table class="top-voters"> <tbody>';
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo '<tr><td>' . $row[minecraft_user]. '</td><td>' . $row[service]. '</td></tr><br>';
}
} else {
echo "No recent votes!";
}
echo '</tbody>';
$conn->close();
?>
Can someone please help me with this? I've been testing for hours with no result.
If you want to get the last 10 table entries then you should change your sql query like this
$sql = "SELECT minecraft_user, service FROM votes order by `minecraft_user` DESC limit 0,10";
If you add id as auto_increment then
$sql = "SELECT id, minecraft_user, service FROM votes order by `id` DESC limit 0,10";