i need to do this operation:
Count the total of each number of records with a different 'rrpp': 1,2,3,4 ∞
I always use this to sum the records of a RRPP:
$variable = Modelo::where('dia_id' , $request->id)->where('rrpp' , 1)->count('id');
but this way I only get the result of 1 in specific.
And what I need is to get the result like this
help, thanks
you only get result 1 because you use this where('dia_id' , $request->id) in your query,
if you want to count rrpp=1 use this query:
$variable = Modelo::where('rrpp' , 1)->count('id');
if you want to count all rrpp use this query:
$variable = Modelo::select('rrpp',
DB::raw('count(*) as total'))
->groupBy('rrpp')
->get()
Related
I was working with a project where I want to get the count of values in a column. I will explain with an example.
I have a table column named name. Where it's values are A,B,C,D,A,D,B,A,C.
Now I want the output as
Count: A-3,B-2,C-2,D-2.
I have tried using group by and distinct. but both don't give me what I want. It all getting the total count of that item. In the code given below is the query I tried. There I want the count of particulars_id and the $public_page_id will be common for all particulars_id I am fetching. There will be a number of public_page_id in the table, and each will have some particulars_id under them.
$output = '';
$this->db->select('COUNT(service_appointment_details.particulars_id)
as count,particulars.particulars_name');
$this->db->from('particulars');
$this->db->group_by('particulars.particulars_id');
$this->db->where('particulars.public_page_id',$public_page_id);
$this->db-
>join('service_appointment_details','particulars.public_page_id =
service_appointment_details.public_page_id','right');
$this->db->where($where_date);
$query = $this->db->get();
Expected Result
Expected Result is (based on the above example)
Count: A-3,B-2,C-2,D-2.
Actual Result
But what I'm getting now is
Count: A-9,B-9,C-9,D-9.
I need to fetch count of each particulars_id under the given public_page_id
You should use count(*)
$this->db->select('COUNT(*) as count,particulars.particulars_name');
........
As pointed out by #scaisEdge, you need to use count(*) instead of count(service_appointment_details.particulars_id). By using count(service_appointment_details.particulars_id), you basically count the number of rows from your select which is not what you want.
Final snippet would be:
$output = '';
$this->db->select('COUNT(*) as count, particulars.particulars_name');
$this->db->from('particulars');
$this->db->group_by('particulars.particulars_name');
$this->db->where('particulars.public_page_id',$public_page_id);
$this->db->join('service_appointment_details','particulars.public_page_id = service_appointment_details.public_page_id','right');
$this->db->where($where_date);
$query = $this->db->get();
Whenever you want to count occurrence of a column values, you'd do
SELECT column_to_count, count(*) FROM table GROUP BY column_to_count
I have an 2 tables Ratings and Attributes , i pass the month and get all record of both users and count this , i have already count this record , and divided into groups by user_id , But in my attribute table i have a user name , and join this table to get attribute name , My query is that
$months = \Request::get('month');
$records = DB::table("ratings")
->select(DB::raw("SUM(ratings.attribute_score) as score"))
->whereRaw('MONTH(ratings.created_at) = '.$months)
->join('users','ratings.user_id','=','users.id')
->groupBy('ratings.user_id')
->get();
dd($records);
And get json like that
But i want to get name of the specific user with score but here multiple selects not working in this query how to use multiple select to get attributes table records? if i am using this query. Thanks Developers in advance
->select(DB::raw("SUM(ratings.attribute_score) as score , ratings.user_id , attributes.attributes_name"))
Using this the select not working here it always return the score Jason like show in the Sceenshot. How can i do to selects multiples using groupBy??
USE THIS TO GET USERNAME WITH SCORE COUNTS. Try This
$months = \Request::get('month');
$records = DB::table("ratings")
->select(DB::raw('SUM(ratings.attribute_score) as score, users.name as
user_name'))
->whereRaw('MONTH(ratings.created_at) = '.$months)
->join('users','ratings.user_id','=','users.id')
->groupBy('users.name')
->get();
return view('attribute.show' , compact('records'));
I'm creating a query that gives me the top 5 countries with more visits, but my query isn't working.
My query I can limit, how would I count all record by country, to see the 5 countries more visited.
My query:
$top5 = DB::table('visits') ->select('ip','country', 'browser') ->groupBy('ip') ->get();
output example:
http://pastebin.com/wtu8CnL8
First you need to group your query by country, since that's what you're looking at. Then you need to count your results, order it by that number, and just take what you need.
$top5 = DB::table('visits')
->select('ip','country', 'browser', DB::raw("count(*) as total_visits"))
->groupBy('country')
->orderBy('total_visits','DESC')
->take(5);
I am currently querying the database to get a count:
$onorder = $db->selectRow("SELECT COUNT(*) as Count FROM store_orders");
The results will be like:
$onorder['Count'];
How do I update the query to find out if ANY of the results counted have a value of 1 for a column named Priority?
You can do:
$onorder = $db->selectRow(
"SELECT COUNT(*) as a, COUNT(IF(Priority=1,1,NULL)) as b FROM store_orders");
and have:
$onorder['a'];
$onorder['b'];
Inside the COUNT you put a condition so it won't count everything:
IF([condition], [result if true], [result if false])
This way it onlyCOUNT()s the ones with value 1 and not the NULLs.
I am building a Twitter-like application which has a feed in it. In this feed I need to display shares with this properties:
-Shares from user, who I am following
-Shares from user, which are sorted by the positive rating, but only the top10%
These two queries I need somehow to merge, so it will become an array in the end, which has all the shares which are applying to this criteria, without any duplicates and ordered by ID, desc
My tables are looking like this:
User, Shares, Follows
Shares:
-user_id
-positive
Follows:
-follower_id
-user_id
-level
What I already tried:
$follower_shares = Share::join('follows', 'shares.user_id', '=', 'follows.user_id')
->where('follows.follower_id', Auth::user()->id)
->where('follows.level', 1)
->get(array('shares.*'));
//count = 10% of total shares
$count = Share::count()/10;
$count = round($count);
$top10_shares = Share::orderBy('positive', 'DESC')
->take($count)
->get();
//sorts by id - descending
$top10_shares = $top10_shares->sortBy(function($top)
{
return -($top->id);
});
//merges shares
$shares = $top10_shares->merge($follower_shares);
The problem is now, that I was told that there is a better way to solve this.
Also, $shares is giving me the result which applies to the criteria, but the shares have duplicates (rows, which are applying to both criteria) and arent ordered by id desc in total.
I would be very happy, if you could tell me, how to do this the right way.
Thanks very much!
I found this to be a pretty clean solution:
// Instead of getting the count, we get the lowest rating we want to gather
$lowestRating = Share::orderBy('positive', 'DESC')
->skip(floor(Share::count() * 0.1))
->take(1)->lists('positive');
// Also get all followed ids
$desiredFollow = Auth::user()->follows()->lists('user_id');
// Select where followed or rating higher than minimal
// This lets the database take care of making them distinct
$shares = Share::whereIn('user_id', $desiredFollow)
->orWhere('positive', '>=', $lowestRating[0])
->get();