Show each name property of all the objects in PHP [duplicate] - php

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How to add elements to an empty array in PHP?
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I'm new at PHP and sessions. For a small project for school. How do i view only the name property of each object stored in a session variable?
I tried using foreach and then using $log->name to only get the name property, but it gives me a "Warning: Attempt to read property "name" on string in".
This is where i add new object to session variable:
<?php
class Log
{
public $name;
public $location;
public $activity;
}
if (isset($_POST['submit'])) {
session_start();
$new_log = new Log;
$new_log->name = $_POST['name'];
$new_log->location = $_POST['location'];
$new_log->activity = $_POST['activity'];
$_SESSION['logs'][] = serialize($new_log);
header('Location: data.php');
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<p class="lead">Mensen aanmelden</p>
<form action="index.php" method="POST">
<!-- Vul de form tag aan zodat deze informatie naar process.php zal gepost worden -->
<input type="text" name="name">
<hr>
<input type="radio" name="location" value="inside"> Binnen<br>
<input type="radio" name="location" value="outside"> Buiten
<hr>
<input type="radio" name="activity" value="drinks"> Drinken<br>
<input type="radio" name="activity" value="dance"> Dansen
<hr>
<input type="submit" name="submit" value="Voeg toe">
</form>
</body>
</html>
This is where i want to view each name of the object:
<?php
session_start();
foreach ($_SESSION['logs'] as $log) {
echo $log ->name. "<br>";
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
return
</body>
</html>


Try this:
$_SESSION['logs'][] = serialize($new_log);

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$json_data = "string";
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file_put_contents("user_data/data.txt",$json_data);
// really not sure if this is what you wanted to do, bit of a guess really
header('Location: https://se.yahoo.com?fname='.$_POST['fname']);
exit();
}
?>
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<html lang="en">
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</head>
<body>
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<input type="text" id="fname" name="fname"><br>
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</body>
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Although, if you were allowed to use JS, it would be a lot simpler. However, since you wanted it in just PHP, the code below should work. Feel free to modify it as per your needs
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?>
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NOTE
If you are using version below PHP 7, just use <?php echo isset($_POST['Usereingabe'])? $_POST['Usereingabe'] : ''; ?> in place of <?php echo $userSolution ?? ''; ?>

So you can keep them in a _SESSION variable and when they submit the answer you can check the _POST variable against the _SESSION one
<?php
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$zufallszahl1= rand(1,100);
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$_SESSION['zufallszahl1']=$zufallszahl1;
$_SESSION['zufallszahl']=$zufallszahl;
$_SESSION['sol']=$solution;
}
// do anything else u want
?>
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You could use two extra input tags in your form of type="hidden" that contain the random numbers in their value fields, and check if they are empty. If they are, generate new ones, otherwise keep the old ones.

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here is the php code
<?php
setcookie("pseudo", $_POST['pseudo'], time() + 365*24*3600);
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you are missing the cookie name parameter which is required to set a cookie.
please see the below implementation
setcookie("Cookie_Name", $_POST['pseudo'], time() + 365*24*3600);

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