Php Dropdown menu - Connect to another DB and show them - php

Question

i work with vuejs3 and laravel 9 on one project.
i have two DB_table. Employee and company.
Company has only id and company name.
Employee contains: id, first name, last name, email, and company_id as forign key, which was joined to id in company_table.
If you want to create a new employee, you have to enter above mentioned infos and select a company name from selectbox (which is shown in previously entered companies) and save it in the table. How can I do then?
#extends('mitarbeiter.layout')
#section('content')
<div class="card">
<div class="card-header">Mitarbeiter Page</div>
<div class="card-body">
<form action="{{ url('mitarbeiter') }}" method="post">
{!! csrf_field() !!}
<label>Vorname</label></br>
<input type="text" name="vorname" id="vorname" class="form-control"></br>
<label>Nachname</label></br>
<input type="text" name="nachname" id="nachname" v-model="mitarbeiter.nachname" class="form-control"></br>
<label>Email</label></br>
<input type="text" name="email" id="email" class="form-control"></br>
<label>Company</label></br>
<select>
<option value="">------Select Company-------</option>
<option name="companyname">
{{option.companyname}}
</option>
</select></br>
</br>
<input type="submit" value="Save" class="btn btn-success"></br>
</form>
</div>
</div>
#stop

Answer 1

You can use foreach like this :
<select name="company" class="form-control">
#foreach ($companies as $company)
<option value="{{ $company->id }}">{{$company->name}}</option>
#endforeach
</select>
and in the controller :
$company = Companies::find($id);
$employee = new Employee();
$employee->user_id = $request->company; //name of select
$employee->company_id = $id;
$employee->save();
hope this would help