Put Mysql Query Result info multidimensional array - php

Question

#UPDATED
I have this table :product_img_detail Table
i want to put the result to make this array of json:
{
"selectedColor": "black",
"black": {
"thumb": {
"image1": "../img/e-commerce/product/dark-small-1.jpg",
"image2": "../img/e-commerce/product/dark-small-2.jpg",
"image3": "../img/e-commerce/product/dark-small-3.jpg"
},
"large": {
"image1": "../img/e-commerce/product/dark-large-1.jpg",
"image2": "../img/e-commerce/product/dark-large-2.jpg",
"image3": "../img/e-commerce/product/dark-large-3.jpg"
}
},
"selectedSlide": 0
}
and this is what i've tried so far with help of #IT goldman:
$sImg = "SELECT prod_thumb160x90, prod_img1280x720 FROM product_img_detail WHERE prod_id=".$data2['id'];
$qPrd = mysql_query($sImg);
$rPrd = mysql_fetch_array($qPrd);
$imgPath = "img/e-commerce/product/";
$count = 0;
$arrSm = [];
$arrLg = [];
foreach ($rPrd as $row) {
$count++;
$arrSm["image$count"] = $imgPath.$rPrd['prod_thumb160x90'];
$arrLg["image$count"] = $imgPath.$rPrd['prod_img1280x720'];
}
$arrImg = array("thumb"=>$arrSm, "large"=>$arrLg);
$res = array("selectedColor"=>"black", "black"=>$arrImg, "selectedSlide"=>0);
echo $json = json_encode($res);
the output of above code is:
{
"selectedColor": "black",
"black": {
"thumb": {
"image1": "img\/e-commerce\/product\/dark-small-1.jpg",
"image2": "img\/e-commerce\/product\/dark-small-1.jpg",
"image3": "img\/e-commerce\/product\/dark-small-1.jpg",
"image4": "img\/e-commerce\/product\/dark-small-1.jpg"
},
"large": {
"image1": "img\/e-commerce\/product\/dark-large-1.jpg",
"image2": "img\/e-commerce\/product\/dark-large-1.jpg",
"image3": "img\/e-commerce\/product\/dark-large-1.jpg",
"image4": "img\/e-commerce\/product\/dark-large-1.jpg"
}
},
"selectedSlide": 0
}
I'm curious, if i change the query to select * from the table, it looping until "image10", and if i change the query to select only 1 column from the table, it stop looping at "image2"!
Anyone can help me?
Please help i need to restructure with right & efficient code (and unescape the forwardslash), i've already stuck for 3 days...

Answer 1

After combining with #IT goldman code, i've found the answer:
$sImg = "SELECT * FROM product_img_detail WHERE prod_id=".$data2['id'];
$qPrd = mysql_query($sImg);
$imgPath = "img/e-commerce/product/";
$count = 0;
$arrSm = [];
$arrLg = [];
//foreach ($rPrd as $row) {
while($rPrd=mysql_fetch_array($qPrd)){
$count++;
$arrSm["image$count"] = $imgPath.$rPrd['prod_thumb160x90'];
$arrLg["image$count"] = $imgPath.$rPrd['prod_img1280x720'];
}
$arrImg = array("thumb"=>$arrSm, "large"=>$arrLg);
$res = array("selectedColor"=>"black", "black"=>$arrImg, "selectedSlide"=>0);
echo $json = json_encode($res);

Answer 2

You need to loop the records (rows) and aggregate to the arrays with the proper keys (according to $count)
You need to loop the records (rows) and aggregate to the arrays with the proper keys (according to $count)
EDIT: I fixed usage of the now deprecated mysql_fetch_array
<?php
$sql = "SELECT * FROM product_img_detail WHERE prod_id = " . $data2['id'];
$qPrd = mysql_query($sql);
$imgPath = "../img/e-commerce/product/";
$count = 0;
$arrSm = [];
$arrLg = [];
while ($row = mysql_fetch_array($qPrd, MYSQL_ASSOC)) {
$count++;
$arrSm["image$count"] = $imgPath . $row['prod_thumb160x90'];
$arrLg["image$count"] = $imgPath . $row['prod_img1280x720'];
}
mysql_free_result($qPrd);
$arrImg = array("thumb" => $arrSm, "large" => $arrLg);
$res = array("selectedColor" => "black", "black" => $arrImg, "selectedSlide" => 0);
echo $json = json_encode($res);