What to make checkbox for each row - php

In our website, we have textbox to ask input values from user. If user input the data Q54497899, rest of the results must be shown from database. Rightnow, I want to add checkbox on each result. I tried to add with foreach but it still doesn't work for me. I will provide codes below which were written in the correlationwafer_result.php. Want to add checkbox beside each Q54497899
<?php
// ini_set("memory_limit","512M");
include("_dbconn.php");
include("//sgewsnant21.amk.st.com/ewsweb/wwwroot/library/common7/db_config.inc");
include("//sgewsnant21.amk.st.com/ewsweb/wwwroot/library/common7/standard_defines.inc");
session_start();
$productlotid = isset ($_GET['productlotid'])? $_GET['productlotid']:'';
$sql = "SELECT * FROM productdb.tbl_correlationwafer WHERE `lotid` = '$productlotid'";
$result1 = mysqli_query($conn,$sql);
$cnt = 0;
echo "<table id='corwafer'>";
while ($row = mysqli_fetch_assoc($result1)) {
echo "<tr>";
echo "<th colspan='2'>Lot ID:</th>";
echo "<th colspan='2'>Product:</th>";
echo "<th colspan='4'>EWSFLOW </th>";
echo "<th>Zone</th>";
echo "</tr>";
$field1name = $row["lotid"];
$field2name = $row["product"];
$field3name = $row["ewsflow"];
$field4name = $row["zone"];
echo '<tr>
<td colspan="2">'.$field1name.'</td>
<td colspan="2">'.$field2name.'</td>
<td colspan="4">'.$field3name.'</td>
<td >'.$field4name.'</td>
</tr>';
foreach($productlotid as $k => $v){
if($k == $row["lotid"]){
echo "<input type=\"checkbox\" id=\"chkproductlotid" . $cnt . "\" name=\"chkproductlotid\" value=\"$v\"><font face=\"arial\" size=\"2\" color=\"#3C5F84\">". $k . "</font>";
}
}
$cnt++;
}
echo "</table>";
flush();
mysqli_close($conn);
?>

Try :
$('chkproductlotid').val();

$productlotid = isset ($_GET['productlotid'])? $_GET['productlotid']:'';
Your $productlotid is more like a string not an array, does it?

You should put your checkbox inside td, and I think your checkbox value should be able to take from the first While Loop, no need that Foreach..

Related

showing results obtained after $_POST in a new page

I have been trying to work this out for a while.
I have created a form with a dropdown box that gets results from a database. from this i then $_POST that from to another page. From that second page i wish to get the ID number and then get the records and display them on screen.
I will then put them in a table to organise the results better.
can anyone help me in achieving this.
Here is the code for the form (which works and sends the $PlantID)
$sql = "SELECT DISTINCT * FROM PLANTS";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
//********************* Botannical name drop down box
echo "<form name='selection' id='selection' action='profile.php' method='post'>";
echo "<select name='flower'>";
while($row = mysqli_fetch_array($result)) {
$plantid = $row['FlowerID'];
$plantname = $row['Botannical_Name'];
$plantcommon = $row['Common_Name'];
/* $plantheight = $row['Height'];
$plantav = $row['AV'];
$plantcolours = $row['Colours'];
$plantflowering = $row['Flower_Time'];
$plantspecial = $row['Special_Conditions'];
$plantfrost = $row['Frost_Hardy'];
$plantaspect = $row['Aspect'];
$plantspeed = $row['Growth_Speed'];*/
echo "<option value=".$plantid.">".$plantname." -> AKA -> ".$plantcommon."</option>";
}
echo "</select>";
echo "<br />";
//********************* End of form
echo "<input type='submit' name='submit' value='Submit'/>";
echo "</form>";
I have created this page to get the ID and display that ID on screen. AS you can tell i have probably doubled up on ways to try work this out.
$sql = "SELECT * FROM PLANTS";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
if(isset($_POST['submit'])){
$selected_val = $_POST['Botannical_Name']; // Storing Selected Value In Variable
echo "You have selected :" .$selected_val; // Displaying Selected Value
}
echo "<br />";
echo "well:".$_POST["Botannical_Name"]."<br/>";
echo "now:".$plantquery."<br />";
echo $_POST;
echo "<table>";
foreach ($_POST as $key => $value) {
echo "<tr>";
echo "<td>";
echo $key;
echo "</td>";
echo "<td>";
echo $value;
echo "</td>";
echo "</tr>";
}
echo "</table>";
Any help would be greatly appreciated.
you should use following to get the selected value,
$selected_val = $_POST['flower'];
if(isset($_POST['submit'])){
$selected_val = $_POST['flower']; // Storing Selected Value In Variable
echo "You have selected :" .$selected_val; // Displaying Selected Value
$sql = "SELECT * FROM PLANTS WHERE FlowerID='.$selected_val.'";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
while ($row=mysqli_fetch_assoc($result))
{
echo $row['Botannical_Name'];
}
}
echo "<br />";
print_r($_POST);
if(!empty(_POST)) {
echo "<table>";
foreach ($_POST as $key => $value) {
echo "<tr>";
echo "<td>";
echo $key;
echo "</td>";
echo "<td>";
echo $value;
echo "</td>";
echo "</tr>";
}
echo "</table>";
}

How to integrate array_column() and array_filter() into dynamic table generation of sql results

I want to read out data from an sql-database an show them in a table. This works well. Now, I would like to show only those columns with at least one value in it and not the empty ones (containing NULL, 0, empty string). This works with the following example:
enter code here
<TABLE width="500" border="1" cellpadding="1" cellspacing="1">
<?php
$query = mysql_query("SELECT * FROM guestbook", $db);
$results = array();
while($line = mysql_fetch_assoc($query)){
$results[] = $line;
$Name = array_column($results, 'Name');
$Home = array_column($results, 'Home');
$Date = array_column($results, 'Date');
$Emptycolumn = array_column($results, 'Emptycolumn');
$Comment = array_column($results, 'Comment');
$City = array_column($results, 'City');
}
echo "<TR>";
if(array_filter($Name)) {echo "<TH>Name</TH>";}
if(array_filter($Home)){echo "<TH>Home</TH>";}
if(array_filter($Date)){echo "<TH>Date</TH>";}
if(array_filter($Emptycolumn)){echo "<TH>Emptycolumn</TH>";}
if(array_filter($Comment)){echo "<TH>Comment</TH>";}
if(array_filter($City)){echo "<TH>City</TH>";}
echo "</TR>";
$query = mysql_query("SELECT * FROM guestbook", $db);
while($line = mysql_fetch_assoc($query)){
echo "<TR>";
if(array_filter($Name)) {echo "<TD>".$line['Name']."</TD>";}
if(array_filter($Home)) {echo "<TD>".$line['Home']."</TD>";}
if(array_filter($Date)) {echo "<TD>".$line['Date']."</TD>";}
if(array_filter($Emptycolumn)) {echo "<TD>".$line['Emptycolumn']."</TD>";}
if(array_filter($Comment)) {echo "<TD>".$line['Comment']."</TD>";}
if(array_filter($City)) {echo "<TD>".$line['City']."</TD>";}
echo "</TR>";
}
?>
</TABLE>
Since the column-names of my table are highly variable (depending on the query), the table is generated by looping through the result-array, first the column-names, then the values in the rows:
enter code here
$sql = "SELECT DISTINCT $selection FROM $tabelle WHERE
$whereclause"; //will be changed to PDO
$result = mysqli_query($db, $sql) or die("<b>No result</b>"); //Running
the query and storing it in result
$numrows = mysqli_num_rows($result); // gets number of rows in result
table
$numcols = mysqli_num_fields($result); // gets number of columns in
result table
$field = mysqli_fetch_fields($result); // gets the column names from the
result table
if ($numrows > 0) {
echo "<table id='myTable' >";
echo "<thead>";
echo "<tr>";
echo "<th>" . 'Nr' . "</th>";
for($x=0;$x<$numcols;$x++){
$key = array_search($field[$x]->name, $custom_column_arr);
if($key !== false){
echo "<th>" . $key . "</th>";
}else{
echo "<th>" . $field[$x]->name . "</th>";
}
}
echo "</tr></thead>";
echo "<tbody>";
$nr = 1;
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $nr . "</td>";
for ($k=0; $k<$numcols; $k++) { // goes around until there are no
columns left
echo "<td>" . $row[$field[$k]->name] . "</td>"; //Prints the data
}
echo "</tr>";
$nr = $nr + 1;
} // End of while-loop
echo "</tbody></table>";
}
}
mysqli_close($db);
Now, I tried to integrate the array_column() and array_filter()-blocks of the example above into the loops, but unfortunately, it didn´t work. I´m sure, this is easy for a professional and I would be very grateful, if someone could help me with this problem!
Thank you very much in advance!!

php - how to exclude a line of code in a loop

I have a code in HTML in a table. And I want the loop to just ignore them
<?php
$sel_admin = "query ";
$rs_admin = mysql_query($sel_admin);
while($row = mysql_fetch_array($rs_admin))
{
echo "<th>". $row['a']. "</th>";
</thead> // This two line of code
<tbody> // is the one I want to exclude in the while loop
$sel_admin2 = "query2 ";
$rs_admin2 = mysql_query($sel_admin2);
while($row2 = mysql_fetch_array($rs_admin2))
{
echo" <tr class='gradeX'> ";
echo "<td>" . $row2['sched3_time']. "</td>";
echo"</tr>";
}
}
?>
Is this even possible?
You need to end your first loop, spit out the html and then start the loop again, havent tested but i think the below should now work.
<?php
$sel_admin = "query ";
$rs_admin = mysql_query($sel_admin);
while ($row = mysql_fetch_array($rs_admin)) {
echo "<th>" . $row['a'] . "</th>";
}
?>
</thead>
<tbody>
<?php
$sel_admin2 = "query2 ";
$rs_admin2 = mysql_query($sel_admin2);
while ($row2 = mysql_fetch_array($rs_admin2)) {
echo " <tr class='gradeX'> ";
echo "<td>" . $row2['sched3_time'] . "</td>";
echo "</tr>";
}
?>
I'm guessing you want those lines printed once, not to be outside the loop, per se. You could use a variable to track it:
$linesNeeded = true;
while (...) {
...
if ($linesNeeded) {
echo $line1;
echo $line2;
$linesNeeded = false;
}
...
}
Please use mysqli instead of mysql. Take a look: MySQL vs MySQLi when using PHP
+
Your problem's answer too.
<?php
$sel_admin = "query ";
$rs_admin = mysqli_query($connection,$sel_admin);
while($row = mysqli_fetch_array($rs_admin))
{
echo "<th>". $row['a']. "</th>";
?>
</thead>
<tbody>
<?php
$sel_admin2 = "query2 ";
$rs_admin2 = mysqli_query($connection, $sel_admin2);
while($row2 = mysqli_fetch_array($rs_admin2))
{
echo" <tr class='gradeX'> ";
echo "<td>" . $row2['sched3_time']. "</td>";
echo"</tr>";
}
}
?>
This is honestly just a guess but based on the code you provided you actually need to add more code after remove the code you do not want:
<?php
$sel_admin = "query ";
$rs_admin = mysql_query($sel_admin);
while($row = mysql_fetch_array($rs_admin))
{
echo "<tr><th>". $row['a']. "</th></tr>"; // Notice the <tr></tr>
$sel_admin2 = "query2 ";
$rs_admin2 = mysql_query($sel_admin2);
while($row2 = mysql_fetch_array($rs_admin2))
{
echo" <tr class='gradeX'> ";
echo "<td>" . $row2['sched3_time']. "</td>";
echo"</tr>";
}
}
?>

Writing the attributes of a database in PHP

I am writing an application in which user can enter a database name and I should write all of its contents in table with using PHP.I can do it when I know the name of database with the following code.
$result = mysqli_query($con,"SELECT * FROM course");
echo "<table border='1'>
<tr>
<th>blablabla</th>
<th>blabla</th>
<th>blablabla</th>
<th>bla</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['blablabla'] . "</td>";
echo "<td>" . $row['blabla'] . "</td>";
echo "<td>" . $row['blablabla'] . "</td>";
echo "<td>" . $row['bla'] . "</td>";
echo "</tr>";
}
echo "</table>";
In this example I can show it since I know the name of table is course and it has 4 attributes.But I want to be able to show the result regardless of the name the user entered.So if user wants to view the contents of instructors there should be two columns instead of 4.How can I accomplish this.I get the table name with html.
Table:<input type="text" name="table">
Edit:Denis's answer and GrumpyCroutons' answer are both correct.You can also ask me if you didnt understand something in their solution.
Quickly wrote this up, commented it (This way you can easily learn what's going on, you see), and tested it for you.
<form method="GET">
<input type="text" name="table">
</form>
<?php
//can be done elsewhere, I used this for testing. vv
$config = array(
'SQL-Host' => '',
'SQL-User' => '',
'SQL-Pass' => '',
'SQL-Database' => ''
);
$con = mysqli_connect($config['SQL-Host'], $config['SQL-User'], $config['SQL-Pass'], $config['SQL-Database']) or die("Error " . mysqli_error($con));
//can be done elsewhere, I used this for testing. ^^
if(!isSet($_GET['table'])) { //check if table choser form was submitted.
//In my case, do nothing, but you could display a message saying something like no db chosen etc.
} else {
$table = mysqli_real_escape_string($con, $_GET['table']); //escape it because it's an input, helps prevent sqlinjection.
$sql = "SELECT * FROM " . $table; // SELECT * returns a list of ALL column data
$sql2 = "SHOW COLUMNS FROM " . $table; // SHOW COLUMNS FROM returns a list of columns
$result = mysqli_query($con, $sql);
$Headers = mysqli_query($con, $sql2);
//you could do more checks here to see if anything was returned, and display an error if not or whatever.
echo "<table border='1'>";
echo "<tr>"; //all in one row
$headersList = array(); //create an empty array
while($row = mysqli_fetch_array($Headers)) { //loop through table columns
echo "<td>" . $row['Field'] . "</td>"; // list columns in TD's or TH's.
array_push($headersList, $row['Field']); //Fill array with fields
} //$row = mysqli_fetch_array($Headers)
echo "</tr>";
$amt = count($headersList); // How many headers are there?
while($row = mysqli_fetch_array($result)) {
echo "<tr>"; //each row gets its own tr
for($x = 1; $x <= $amt; $x++) { //nested for loop, based on the $amt variable above, so you don't leave any columns out - should have been <= and not <, my bad
echo "<td>" . $row[$headersList[$x]] . "</td>"; //Fill td's or th's with column data
} //$x = 1; $x < $amt; $x++
echo "</tr>";
} //$row = mysqli_fetch_array($result)
echo "</table>";
}
?>
$tablename = $_POST['table'];
$result = mysqli_query($con,"SELECT * FROM $tablename");
$first = true;
while($row = mysqli_fetch_assoc($result))
{
if ($first)
{
$columns = array_keys($row);
echo "<table border='1'>
<tr>";
foreach ($columns as $c)
{
echo "<th>$c</th>";
}
echo "</tr>";
$first = false;
}
echo "<tr>";
foreach ($row as $v)
{
echo "<td>$v</td>";
}
echo "</tr>";
}
echo "</table>";
<?php
$table_name = do_not_inject($_REQUEST['table_name']);
$result = mysqli_query($con,'SELECT COLUMN_NAME FROM information_schema.COLUMNS WHERE TABLE_NAME='. $table_name);
?>
<table>
<?php
$columns = array();
while ($row = mysql_fetch_assoc($result)){
$columns[]=$row['COLUMN_NAME'];
?>
<tr><th><?php echo $row['COLUMN_NAME']; ?></th></tr>
<?php
}
$result = mysqli_query($con,'SELECT * FROM course'. $table_name);
while($row = mysqli_fetch_assoc($result)){
echo '<tr>';
foreach ($columns as $column){
?>
<td><?php echo $row[$column]; ?></td>
<?php
}
echo '</tr>';
}
?>
</table>

Retrieve data from sql database and display in tables - Display certain data according to checkboxes checked

I have created an sql database(with phpmyadmin) filled with measurements from which I want to call data between two dates( the user selects the DATE by entering in the HTML forms the "FROM" and "TO" date) and display them in a table.
Additionally I have put, under my html forms, some checkboxes and by checking them you can restrict the amount of data displayed.
Each checkbox represent a column of my database; so along with the date and hour column, anything that is checked is displayed(if none is checked then everything is displayed).
So far I managed to write a php script that connects to the database, display everything when none of my checkboxes is checked and also managed to put in order one of my checkboxes.
Problem: The data that I call for are been displayed twice.
Question: I want to have four checkboxes.
Do I need to write an sql query for every possible combination or there is an easier way?
<?php
# FileName="Connection_php_mysql.htm"
# Type="MYSQL"
# HTTP="true"
$hostname_Database_Test = "localhost";
$database_Database_Test = "database_test";
$table_name = "solar_irradiance";
$username_Database_Test = "root";
$password_Database_Test = "";
$Database_Test = mysql_pconnect($hostname_Database_Test, $username_Database_Test, $password_Database_Test) or trigger_error(mysql_error(),E_USER_ERROR);
//HTML forms -> variables
$fromdate = $_POST['fyear'];
$todate = $_POST['toyear'];
//DNI CHECKBOX + ALL
$dna="SELECT DATE, Local_Time_Decimal, DNI FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$tmp ="SELECT * FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$entry=$_POST['dni'];
if (empty($entry))
{
$result = mysql_query($tmp);
echo
"<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>
<th>Solar_time_decimal</th>
<th>GHI</th>
<th>DiffuseHI</th>
<th>zenith_angle</th>
<th>DNI</th>
";
while( $row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal'] . "</td>";
echo "<td>" . $row['Solar_Time_Decimal'] . "</td>";
echo "<td>" . $row['GHI'] . "</td>";
echo "<td>" . $row['DiffuseHI'] . "</td>";
echo "<td>" . $row['Zenith_Angle'] . "</td>";
echo "<td>" . $row['DNI'] . "</td>";
echo "</tr>";
}
echo '</table>';}
else
{
$result= mysql_query($dna);
echo
"<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>
<th>DNI</th>
";
while($row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal']."</td>";
echo "<td>" . $row['DNI'] . "</td>";
echo "</tr>";
}
echo '</table>';
}
if($result){
echo "Successful";
}
else{
echo "Enter correct dates";
}
?>
<?php
mysql_close();
?>
Try to create your checkbox like below:
Solar_Time_Decimal<checkbox name='columns[]' value='1'>
GHI<checkbox name='columns[]' value='2'>
DiffuseHI<checkbox name='columns[]' value='3'>
Zenith_Angle<checkbox name='columns[]' value='4'>
DNI<checkbox name='columns[]' value='5'>
And try to hange your PHP code to this:
<?php
//HTML forms -> variables
$fromdate = isset($_POST['fyear']) ? $_POST['fyear'] : data("d/m/Y");
$todate = isset($_POST['toyear']) ? $_POST['toyear'] : data("d/m/Y");
$all = false;
$column_names = array('1' => 'Solar_Time_Decimal', '2'=>'GHI', '3'=>'DiffuseHI', '4'=>'Zenith_Angle','5'=>'DNI');
$column_entries = isset($_POST['columns']) ? $_POST['columns'] : array();
$sql_columns = array();
foreach($column_entries as $i) {
if(array_key_exists($i, $column_names)) {
$sql_columns[] = $column_names[$i];
}
}
if (empty($sql_columns)) {
$all = true;
$sql_columns[] = "*";
} else {
$sql_columns[] = "DATE,Local_Time_Decimal";
}
//DNI CHECKBOX + ALL
$tmp ="SELECT ".implode(",", $sql_columns)." FROM $database_Database_Test.$table_name where DATE>=\"$fromdate\" AND DATE<=\"$todate\"";
$result = mysql_query($tmp);
echo "<table border='1' style='width:300px'>
<tr>
<th>DATE</th>
<th>Local_Time_Decimal</th>";
foreach($column_names as $k => $v) {
if($all || (is_array($column_entries) && in_array($k, $column_entries)))
echo "<th>$v</th>";
}
echo "</tr>";
while( $row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>" . $row['DATE'] . "</td>";
echo "<td>" . $row['Local_Time_Decimal'] . "</td>";
foreach($column_names as $k => $v) {
if($all || (is_array($column_entries) && in_array($k, $column_entries))) {
echo "<th>".$row[$v]."</th>";
}
}
echo "</tr>";
}
echo '</table>';
if($result){
echo "Successful";
}
else{
echo "Enter correct dates";
}
?>
<?php
mysql_close();?>
This solution consider your particular table columns but if your wish a generic solution you can try to use this SQL too:
$sql_names = "SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = '$database_Database_Test' AND TABLE_NAME = '$table_name'";
and use the result to construct the $column_names array.
Solution for your problem : Change the mysql_fetch_assoc with mysql_fetch_array
If you have the same problem try to print your result with print_r
Answer : Use the bit datatype in mysql for store and read your checkboxes.
When you're receiving thr value from the database then you can use
in the parameter checked you can use the php code as exist :
$value = ...get the value from db ( 1 or 0 )
echo '<input type="checkbox" name="thename" value="thevalue" '.($value==1?'checked=checked'.'').'/>';

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