This question already has answers here:
PHP Strtotime without current time?
(2 answers)
Closed 4 months ago.
I have an Unix timestamp like this 1660293621 (2022-08-12 8:40). I want to get next 2 days not counting current date. I expect the result to be 2022-08-15 00:00.
I tried
strtotime("+3 Days", $current_date)
but it returns 2022-08-15 8:40, not 00:00
How can I get that in PHP? Thank you~
$Today=date('y:m:d');
// add 3 days to date
$NewDate=Date('y:m:d', strtotime('+3 days'));
Reference:
Increase days to php current Date()
I figured it out, just add 0:00 will help
$next2days = strtotime("+3 days 0:00", $current_date);
Related
This question already has answers here:
Return current date plus 7 days
(10 answers)
Closed 2 years ago.
So I have the below property where I'm passing in a time()-86000 value, but what would be the best call to generate a timestamp from the time the class method executes and then adds 7 days to that.
Here is what I got:
$profile->set_picture_expiration(time()-86000)
Would using time()-86000 be the right call? I'd like to write it to the DB in timestamp format from the current time + 7 days.
First of all, if you need +7 days, why are you using minus?
Next, 7 days are 7*24*60*60 = 604800 seconds, not 86000.
Finally, the easiest way to get the timestamp for such relative dates is using the strtotime function. In your specific case it would be strtotime('+7 days').
$profile->set_picture_expiration(strtotime('+7 days'));
This question already has answers here:
PHP Adding 15 minutes to Time value
(9 answers)
Closed 4 years ago.
I want to add a specific period like 2 hours to only time.
BUT only TIME. There will be no date related issue.
Like my time is 02:00:00
And I want to add 1 hour to this time.
So, the result will be 03:00:00
Is there any PHP built-in function like strtotime()?
I don't want explode related function for this like explode(":", $time)
Is it possible? Please help someone.
Try
$new_time = date("H:i:s", strtotime("+ 1 hours"))
or if you would just like the timestamp:
strtotime("+ 1 hours")
This question already has answers here:
Subtract one second from a given time
(2 answers)
Closed 8 years ago.
I writing a code for subtract seconds from a time using php. i have date which assigned to variable , i need to subtract seconds from that date.
$date="2014-03-16 17:40:27";
echo date("Y-m-d H:i:s", strtotime($date) - strtotime("-600 seconds"));
but this gives me dates on 1970S, i search everhere and didn't found a answer which matched for my question. can anyone help me to fix this little code
strtotime() gives you a timestamp in seconds. Don't make another timestamp to subtract from it, just take 600 from it:
echo date("Y-m-d H:i:s", strtotime($date) - 600);
//2014-03-16 17:30:27
This question already has answers here:
Get first day of week in PHP?
(39 answers)
Closed 9 years ago.
Any way to take a date like this 2013-05-29 in PHP and get the date (in the same format) of that weeks monday? So the output would be like this: 2013-05-27
date('Y-m-d', strtotime('last sunday +1 day', strtotime('2013-05-29')));
last sunday +1 day because last monday would return the Monday of the previous week if $timestamp actually was a Monday already.
And parsing of the original date value 2013-05-29 in a second step because all together as one argument does not work well (mixing of absolute and relative date values is something strtotime does not like very much).
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
PHP:find day difference between two date(“YmdHis”) reture
What I want to do is to get day from database, current date. And check if difference between them > 1 day:
$curdate= date("Y-m-d H:i:s");
$dbdate is value stored in datetime format in db.
$dif=$curdate-dbdate;
How to check if $dif>1 day ??
Assuming the stored date is expressed in the same time zone as the server, you can convert it to a timestamp using strtotime, and compare it to strtotime("-1 day"):
if (strtotime($dbdate) < strtotime("-1 day"))
frobnicate();
You can get just the day from each date.
$day = intval($curdate= date("d"));
This will get the day as an in. Do the same for the time of the data base and you get two integer representing the day. Using that you can calculate how many days have pass.
Beware that the last line should look like this:
$dif = abs($curdate-$dbdate);