Merge returns empty - php

Question

There was a problem with the request. Any ideas?
The situation is as follows, there is a request
MERGE ore as T_Base USING ( SELECT
date
,sec
,shift
,id_ore
FROM ore
WHERE date = '2022-9-20'
AND sec = '2'
AND shift = '1') AS T_Source
ON T_Base.date = T_Source.date
AND T_Base.sec = T_Source.sec
AND T_Base.shift = T_Source.shift
AND T_Base.id_ore = T_Source.id_ore
WHEN MATCHED
THEN UPDATE
SET date = T_Source.date
,sec = T_Source.sec
,shift = T_Source.shift
,id_ore = '1'
WHEN NOT MATCHED
THEN INSERT (date, sec, shift, id_ore)
VALUES (T_Source.date, T_Source.sec, T_Source.shift, '1');
But for some reason it returns "0 rows affected".
Table structure:
[id] [int] IDENTITY(1,1) NOT NULL,
[date] [datetime] NULL,
[sec] [int] NULL,
[shift] [int] NULL,
[id_ore] [int] NULL
Values in the table:
id date sec shift id_ore
11637 2022-09-10 00:00:00.000 1 1 13
11636 2022-09-09 00:00:00.000 1 2 13
etc
Expected Result
When updated, no change
id date sec shift id_ore
11637 2022-09-10 00:00:00.000 1 1 13
1.1) When update, with changes (shift and id_ore updated )
id date sec shift id_ore
11637 2022-09-10 00:00:00.000 1 2(change) 27(change)
When new values are inserted:
id date sec shift id_ore
11638 2022-09-20 00:00:00.000 1 1 1

Answer 1

Sorry for this post. I misunderstood the MERGE construction. If there is no data in any of the tables, the operation will not be performed, since there will be nothing to match
If suddenly, someone encountered a similar, came to the following solution:
IF EXISTS (SELECT
date
,sec
,shift
FROM ore
WHERE date = '" . $y . "-" . $m . "-" . $d . "'
AND sec = '" . $sec . "'
AND shift = '" . $shift. "')
UPDATE ore
SET id_ore = '" . $nam_ryd . "'
WHERE date = '" . $y . "-" . $m . "-" . $d . "'
AND sec = '" . $sec . "'
AND shift = '" . $shift. "'
ELSE
INSERT ore (date, sec, shift, id_ore)
VALUES ('" . $y . "-" . $m . "-" . $d . "', '" . $sec . "', '" . $shift. "', '" . $nam_ryd . "')