Calling static class outside of namespace - php

Inside a class "cl1" in the namespace "space1", there is the function "fctn1", and inside it I want to call the static method "fctn2" from the class "cl2". The class cl2 is not inside any namespaces.
<?php
namespace space1;
class cl1
{
public function fctn1()
{
cl2::fctn2();
}
}
<?php
class cl2
{
public static function fctn2()
{
// stuff here
}
}
How can I call fctn2 inside the fctn1 on PHP?
I tryied simply calling the method inside the class just like shown in the code on the question.

Honk der Hase gave a satisfactory answer in a comment:
Prepend a backslash to address the global namespace:
\cl2::fetch2();

Related

Can't extend abstract PHP class

I want a base class to be extended, but I have some errors coming out:
Fatal error: Class 'Api\Services\Base' not found in
/var/www/html/Api/Services/Example.php on line 7
I searched for typos, tried to use the fully qualified name, made the abstract class empty or just defined it as a simple class; none of these helped.
Using "require" instead of "use" worked, but still...
Any idea (the two files are in the same directory: /var/www/html/Api/Services)?
Thanks in advance...
<?php
// Base.php
namespace Api\Services;
use Api\Classes\ErrorHandler;
use Api\Classes\ErrorMessage;
abstract class Base
{
public $data = null;
public function getData()
{
return $this->data;
}
public function setData($data = null)
{
$this->data = $data;
}
}
?>
<?php
// Example.php
namespace Api\Services;
use Api\Services\Base;
class Example extends Base
{
public $request = array();
public function __construct($request = array())
{
$this->request = $request;
}
}
?>
use Base
instead of
use Api\Services\Base;
because you are already inside the namespace Api\Services
Actually, you don't even have to write the use statement, you are inside the namespace, you can just call the classes inside the same namespace without including them (use)

Overwrite namespace usage in extended class in PHP

Overwrite namespace usage in extended class
Is it possible to overwrite the used namespace of the parent class without rewriting the function in the extended class?
For clarification i write down an example:
i have two classes like this:
namespace one;
class hey
{
public static function say()
{
echo "hey";
}
}
and
namespace two;
class hey
{
public static function say()
{
echo "ho";
}
}
Now i use on of the namespaces in this class:
use one\hey;
class saysomething
{
public static function main()
{
hey::say();
}
}
Now i want to extend the last class:
class extended extends saysomething
{
}
extended::main();
In this class i want to use namespace "two\one" without overwriting the function, is it possible? *f it is, how?
Thank you for your time.
You must define extended::main() within extended class, like this:
use two\hey;
class extended extends saysomething
{
public static function main()
{
hey::say(); // will call two/hey::say method
}
}
Namespaces won't help here.

Call function from different class and namespace

I'm having some trouble to call a function from a namespaced class in a different namespaced class. In the dummy example below I would like to know how to use Class2 within Class1. I'm getting the error:
Trait 'name1\name2\Class2' not found in class1.php
The code:
#file index.php
require "class1.php";
require "class2.php";
$class1 = new name1\Class1();
$class1->sayHello();
#file class1.php
namespace name1{
class Class1{
use name2\Class2;
public function sayHello(){
echo Class2::staticFunction();
}
}
}
#file class2.php
namespace name2{
class Class2{
public static function staticFunction(){
return "hello!";
}
}
}
Thank you for any advice.
Ok, so you've got several errors which I have fixed.
Here's the working code you need:
# index.php
include "class1.php";
include "class2.php";
$class1 = new name1\Class1();
$class1->sayHello();
# class1.php
namespace name1;
use name2\Class2;
class Class1{
public function sayHello(){
echo Class2::staticFunction();
}
}
# class2.php
namespace name2;
class Class2{
public static function staticFunction(){
return "hello!";
}
}
Some explanations:
When in class definition the use is used for using traits and not namespace
In PHP namespace need not be enclosed in curly brackets
In PHP you include files with include, include_once, require, or require_once, and not import
Inside your first class, your trait is calling class2 as use name2\Class2 but, you are still within the name1{} namespace, so in reality you are calling it as: use name1\name2\Class2
So, you need to change
use name2\Class2; to use \name2\Class2
Try this.
namespace name1{
use \name2\Class2;
class Class1{
public function sayHello(){
echo Class2::staticFunction();
}
}
}
#file class2.php
namespace name2{
class Class2{
public static staticFunction(){
return "hello!";
}
}
}
Also, another tip: If you are separating your classes in separate files, you do not need to separate them as in they way you have done. Just call the namespace simple as:
// file1.php
namespace person;
class name{}
//file2.php
namespace address;
class name{}
Why not drop the static method and just inject the class? Seems like going through extra work for something so simple. That's what function arguments are made for.
namespace name1{
use \name2\Class2;
class Class1{
public function sayHello($Class2){
echo $Class2->someFunction();
}
}
}
namespace name2{
class Class2{
public function someFunction(){
return "hello!";
}
}
}
#index.php
include "class1.php";
include "class2.php";
$Class1 = new name1\Class1();
$Class2 = new name2\Class2();
$Class1->sayHello($Class2);
//hello!

Instantiate a class in another class code and get rid of include("class_name"), using namespace

so i have a class here that have a function who requires another class to create an object.
I use namespace in both files, my question is can i get rid of this line here: include("class.php"); and instantiate class using namespace?
here is the file from where i call the other class:
namespace namespaceName;
class classLoader{
public function __construct() {
//not used
}
public function executeFunctionOutsideTheNamespace() {
include("class.php");
new classExtended("badass");
}
}
and the class by itself:
namespace namespaceName;
class classExtended extends classBase
{
public function __construct($action) {
echo $action;
}
}
I ask again, using Namespace there is no possibility to get rid of include() or require(), require_once() functions? to call directly new classExtended("badass"); ?

Finding a class name after extending

I'm having troubles finding a class name after extending other classes. Here are the relevant classes:
class Home extends Controller {
public function test() {
Example::all();
}
}
Class Example extends Active {
//Variables
}
Class Active extends Database {
public function all() {
//This is where I need to store a variable containing the class name Example.
}
}
I'm trying to retrieve the name of the Class Example in Class Active from when it is called from class Home, however I've found it impossible to do this so far without adding an extra argument (which I don't want to do).
You are looking for
get_called_class — the "Late Static Binding" class name
Example (demo)
class Home {
public function test() {
Example::all();
}
}
Class Example extends Active {
//Variables
}
Class Active {
public static function all() {
var_dump( get_called_class() );
}
}
Note that I have changed the signature of Active::all to static because calling non-static methods statically will raise E_STRICT warnings. In general, you want to avoid static methods and Late Static Binding.
have you tried with ReflectionObject class from PHP ? Have a look to this method
Hope this helps

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