How to update more then one database column - php

Question

I was following one guy's tutorial on how to update database with ajax but I had some other intentions, he wanted to make a new row each time he updates his form, where I wanted to update an existing row. I Successfully updated the code to my needs but I want to update more then one column in that same row.
My form has 2 values, Show Announcement and Announcement Content where In text field I update Show Announcement to either 0 or 1 (true, false) and in Announcement Content to some text I want.
Now, the problem is that when trying to add && isset($_POST['anncontent']) && $_POST['anncontent']!='' in if statement in line 19 (marked where it is) and adding another SET option in $sql (SET announcement=('".addslashes($_POST['anncontent'])."')), it gives me status code 500 and neither of these 2 content updates in a database.
.submit.php
<?php
$host = "localhost";
$database = "";
$username = "";
$password = "";
try
{
$conn = new PDO("mysql:host=$host;dbname=$database", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $e)
{
echo "Connection failed: " . $e->getMessage();
}
$response = array('success' => false);
LINE 19 ---> if(isset($_POST['name']) && $_POST['name']!='' && isset($_POST['anncontent']) && $_POST['anncontent']!='' )
{
$sql = "UPDATE settings SET ann=('".addslashes($_POST['name'])."') AND SET announcement=('".addslashes($_POST['anncontent'])."')";
//$sql = "UPDATE settings SET announcement=('".addslashes($_POST['anncontent'])."')";
if($conn->query($sql))
{
$response['success'] = true;
}
}
echo json_encode($response);
?>
index.php
<form action="" method="post">
<div> Show Announcement <input type="text" name="name" value="" /></div>
<div> Announcement Content<input type="text" name="anncontent" value="" /></div>
<div><button type="button" onclick="submitForm();" name="save_announcement" value="Save"/>Update</button></div>
</form>
</body>
<script type="text/javascript">
function submitForm()
{
var name = $('input[name=name]').val();
var anncontent = $('input[name=anncontent]').val();
if(name != '')
{
var formData = {name: name, anncontent: anncontent};
$('#message').html('<span style="color: red">Updating...</span>');
$.ajax({url: "https://localhost/admin/api/submit.php", type: 'POST', data: formData, success: function(response)
{
var res = JSON.parse(response);
console.log(res);
if(res.success == true)
$('#message').html('<span style="color: green">Successfuly updated.</span>');
else
$('#message').html('<span style="color: red">Error while updating.</span>')
}
});
}
else
{
$('#message').html('<span style="color: red">Please fill all the fields</span>');
}
}
</script>
Maybe the problem is in my sql call? I am not sure if that's the right way to update 2 columns in the same line.
I tried adding additional $sql call with only SET announcement but that didn't work. Same error code.
When I try to write something only in Show Announcement text field and press Update, I get #Error While updating# message (The one I set for if success = false) but when I try to set some content in another text field as well, I get a message "Updating..." and I get stuck on that.
https://prnt.sc/_MexIxx6dSdJ
Please, let me know if I need to provide more information for this case for you to understand the problem.

Answer 1

I would advice using !empty() "not empty", which does both checks for you.
Except that, you can bind 2 parameters doing something like:
if (!empty($_POST['name']) && !empty($_POST['announcement'])) {
$stmt= $pdo->prepare("UPDATE settings SET name = :name, announcement = :announcement");
$stmt->execute([
'name' => $_POST['name'],
'announcement' => $_POST['announcement']
]);}
Here is more about PDO