Hi Guys I have a question. I am still learning and am trying to get some date out. Beneath is the table. It has hundreds of lines, but for example:
FormNR
Datum
XX1
XX2
XX3
0001
2022-09-08
4
23
7
0002
2022-09-10
8
5
0
The table name is 'forms'. Now what I need to do is to count XX1+XX2+XX3 (for a year rapport). Then I have a 'date from and to' selection box on my page. So the question would be:
What instanties have been used between a certain date in total but so that you can see a a total per Instantie (each number is a different instantie).
So for example...Between the 1st of January and the 1st of June a list of all XX numbers ( there are 36 ) with there total behind it
What I have is the following. Is works great and shows all XX's in a nice table but for the entire table, not per date. As soon as i want to add the 'between $date_from AND $date_to' it fails.
<?php
$sql_rg_total="SELECT forms.Datum, x.f1,Count(x.f1)
FROM
(SELECT XX1 As F1 FROM forms
UNION ALL
SELECT XX2 As F1 FROM forms
UNION ALL
SELECT XX3 As F1 FROM forms) x
WHERE x.f1 = '$subcat_id'
GROUP BY x.f1";
$resultvv=mysqli_query($conn, $sql_rg_total);
if (mysqli_num_rows($resultvv) > 0) {
while ($rowvv = mysqli_fetch_assoc($resultvv)) {
$subnr = $rowvv['Count(x.f1)'];
echo $subnr;
}
}
?>
By the way $subcat_id is from another table which connects the number to a name.
I have tried to write it as clear as I could. I know it's a bit thought haha. Thanks anyway for any input. Really stuck.
This query should do it:
SELECT SUM(x.c) AS c
FROM (
SELECT ((XX1 = '$subcat_id') + (XX2 = '$subcat_id') + (XX3 = '$subcat_id')) AS c
FROM forms
WHERE Datum BETWEEN '$date_from' AND '$date_to'
) x
The value of a boolean condition is 1 when it's true, 0 when it's false. So XX1 = '$subcat_id' + XX2 = '$subcat_id' + XX3 = '$subcat_id' adds up the number of columns that match in a row, then SUM(c) totals them in the entire table.
You don't need GROUP BY, since it's the same column that you're filtering in the WHERE condition (and now in the SELECT expression). And this moves the date condition into the subquery.
Related
I am trying to search two tables, match the results and then concatenate the answer... Only finding results >= today's date. This will then give the user the option to delete the selected from the DB. So...
Table 1 called Prog_name
id prog_name
1 Breakfast
2 Mid Morning
3 Afternoon
Table 2 called talk_ups
id date_tx prog_name (prog_name value = prog_name.id)
1 2017-06-30 2
2 2017-07-03 1
3 2017-07-01 3
The result I am after is something like: "01-07-2017, Afternoon". But I do also need the talk_ups.id to ensure it only deletes the correct record.
I managed to figure out how to get the name to match the talk_ups.prog_name value:
'$sql. = "SELECT talk_ups.prog_name, prog_name.id as progID, prog_name.prog_name as theName FROM prog_name, talk_ups WHERE talk_ups.prog_name = prog_name.id";'
But I can't figure out how to do the two searches and end up with the right result and how to separate out the results to then concatenate them.
You can use JOIN with WHERE condition, e.g.:
SELECT pn.id, pn.prog_name, tu.date_tx
FROM prog_name pn JOIN talk_ups tu ON pn.id = tu.prog_name
WHERE tu.date_tx > NOW();
The following mySQL query gets data from 2 tables, alerts_data and alerts_list. The first table has the data of an alert, and the second has the description of the alert. So in the alerts_data there are multiple rows with the same alerts_data_id that is the same with the alerts_id of alerts_list.
What i want to achieve, is to display something like this
alert number 51, 5 clicked , 2 closed
alert number 57, 13 clicked, 3 closed, 8 waiting
using mySQL or PHP (i do not know if i can get this through plain mySQL)
So for now with my knowledge I can not display the data of alert 51 in one row, but because of the different alerts_data_status i have to show 3 rows for each.
How can I do it as above?
SELECT COUNT( alerts_data_id ) AS total, alerts_data_id, alerts_data_status, alerts_list.alerts_title
FROM alerts_data
JOIN alerts_list ON
alerts_data.alerts_data_id = alerts_list.alerts_id
GROUP BY alerts_data_id, alerts_data_status
//output
total - alerts_data_id - alerts_data_status - alerts_title
5 - 51 - clicked - alert number 51
2 - 52 - closed - alert number 51
13 - 57 - clicked - alert number 57
3 - 57 - waiting - alert number 57
8 - 57 waiting - alert number 57
Note: the alerts number are just examples, it can be any number
// alert_data
id - alerts_data_id - alerts_data_status
// alerts_list
alerts_id - alerts_name - alerts_text
Here's a sqlfiddle: http://sqlfiddle.com/#!9/c70c2/1
This may be an application for GROUP_CONCAT().
You first want a summary of your alerts by alerts_data_id and alerts_data_status. This is a little complex, because your sqlfiddle has a whole bunch of empty alerts_data_status strings. Here, I'm replacing those empty strings with `?'. (http://sqlfiddle.com/#!9/c70c2/23/0)
SELECT COUNT(*) AS alerts_count,
alerts_data_id,
CASE WHEN LENGTH(alerts_data_status) = 0 THEN '?'
ELSE alerts_data_status END AS alerts_data_status
FROM alerts_data
GROUP BY alerts_data_id, alerts_data_status
You then want to roll that up inside another query
SELECT SUM(a.alerts_count) total,
a.alerts_data_id, b. alerts_name,
GROUP_CONCAT( CONCAT(a.alerts_count, ': ', a.alerts_data_status)
ORDER BY a.alerts_data_status
SEPARATOR "; " ) detail
FROM (
SELECT COUNT(*) AS alerts_count,
alerts_data_id,
CASE WHEN LENGTH(alerts_data_status) = 0 THEN '?'
ELSE alerts_data_status END AS alerts_data_status
FROM alerts_data
GROUP BY alerts_data_id, alerts_data_status
) a
JOIN alerts_list b ON a.alerts_data_id = b.alerts_id
GROUP BY a.alerts_data_id, b.alerts_name
This will give you one row for each distinct alerts_data_id. Each alert is identified by its count, its id, and its name. (http://sqlfiddle.com/#!9/c70c2/26/0)
Then the row will contain a semicolon-separated list of the counts of the different alert status.
If i understand you well i think here is what you need;
SELECT
COUNT( alerts_data.id ) AS total,
ad.id,
(SELECT count(*) from alert_list al where al.alerts_id=ad.id and alerts_data_status='clicked') as clicked,
(SELECT count(*) from alert_list al where al.alerts_id=ad.id and alerts_data_status='closed') as closed,
(SELECT count(*) from alert_list al where al.alerts_id=ad.id and alerts_data_status='waiting') as waiting,
FROM alerts_data ad
GROUP BY ad.id
Was checking other answers and your SQLFIDDLE and thought this might be a nicer approach:
SELECT alerts_list.alerts_title,
SUM(CASE WHEN alerts_data_status = 'clicked' THEN 1 ELSE 0 END) AS clicked,
SUM(CASE WHEN alerts_data_status = 'closed' THEN 1 ELSE 0 END) AS closed,
SUM(CASE WHEN alerts_data_status = 'waiting' THEN 1 ELSE 0 END) AS waiting
FROM alerts_data
JOIN alerts_list ON alerts_data.alerts_data_id = alerts_list.alerts_id
GROUP BY alerts_list.alerts_title
Here's my database (free rooms in a hotel, simplified)
rooms_available:
id date_available room_id
================================
1 2013-12-19 2
2 2013-12-20 2
3 2013-12-21 2
4 2013-12-22 2
5 2013-12-23 2
6 2013-12-25 3
rooms:
id name minimal_range
================================
2 Apartment A 5
3 Apartment B 1
I want to query all rooms which are available between 2013-12-20 and 2013-12-22
My query is like:
select *
from rooms_available
where (date='2013-12-20' OR date='2013-12-21' OR date='2013-12-22')
My questions:
is there a more comfortable way? when the date range will be like 2 weeks, the query will also be very long (which will take much longer for querying)
would it be possible to consider minimum ranges - for example: room_id 2 is only available for at least 5 nights (see table "rooms") -> so above query should return no records
Thanks
date >= '2013-12-20' and date <= '2013-12-22'
SELECT * FROM rooms_available WHERE `date_available` BETWEEN "2013-12-20 " AND "2012-03-31"
I didn't test this but it should point you in the right direction especially for the second part of your question about minimal range.
SELECT t1.id as id, t1.date_available as date_available, t1.room_id
FROM rooms_availble as t1 JOIN rooms as t2 on t1.room_id = t2.id
WHERE t1.date_available BETWEEN DATE('2013-12-20') AND DATE('2012-03-31') AND
t2.minimal_range <= datediff('2013-12-22', '2012-12-20');
The mysql datediff function will return the number of days between two dates then you can just compare it with the minimal_range from the rooms join table. Also you might consider binding the start and end dates to variables so that you only have to write each date once.
I am recording a real time change of a given signal into my database table.
Then I draw line graph to visualize the change of the signal level.
I want to get (10n+1)th rows in the table to make a rough graph. 10 is also arbitrary. User may change it to another value.
Does someone know how to make this just using a MySQL Query
If no, I will go with PHP after selecting all the data.
Here my table structure is:
|id |signal1 |signal2 | signal 3 |
+----------+----------+----------+------------+
|1 |0.41452 | 1.32135 | 0.31231 |
...
If you have an auto_incrememt id column, you can select rows that are divisible by n
SELECT * FROM tableName1 WHERE MOD(id,10)=0;
// id divided by 10 with a remainder equal to 0 (exact)
or without sequential column id's
SELECT * FROM (
SELECT
#row := #row +1 AS rowNum, colName1
FROM (
SELECT #row :=0) r, tableName1
) ranked
WHERE rowNum % 10 = 1
If your table has auto increment id (intID), then you should try this code.There are only 26 records in my table.
select * from tablename where intId
in (select case (intId%10=0) when 1 then intId else 0 end as x from tablename )
Output :-
10 sdf KK201300010 123456 Regular
20 sdf KK201300020 123456 Regular
It will displaying each record in every 10 record.
Hope it will help you.
My Pastebin : http://pastebin.com/PmfDEdEw
Hi,
I am doing a bus search script and here is a table called "bus_notavailable" and it has fields as
nodate_id(PK)
bus_id(FK)
DD(INT 2)
MM(INT 2)
and YYYY(INT 4)
My Question is : Suppose Bus ID is 1 which is not available for these two dates are 15-08-2013 and 26-01-2013 so the record will filtered for this day...
The Nodates Table
Nodate_id bus_id DD MM YYYY
1 1 15 08 2013
2 1 26 01 2013
• so bus_notavailable.DD != '26' its showing me one record
• bus_notavailable.DD != '11' then its showing me 2 records
I know I did mistakes or don't know the solutions therefore want to find out the way to get rid of, and knew this is a issue of one to many relationship where the 'bus_notavailable' has two id of the same bus its showing me two records from 'bus' table.
So Do I need a sub-query to achieve this or is there any other methods?
Your condition here
LEFT JOIN bus_notavailable ON bus.bus_id = bus_notavailable.bus_id
.....
WHERE ......
bus_notavailable.bus_id IS NULL
AND bus_notavailable.DD != '$DD'
AND bus_notavailable.MM != '$MM'
AND bus_notavailable.YYYY != '$YYYY'
Is nonsensical because once bus_id IS NULL, there is no bus_notavailable record from which to compare the DD, MM or YYYY columns.
The condition you want is this (move the DD/MM/YYYY into the LEFT JOIN ON cluse):
LEFT JOIN bus_notavailable ON bus.bus_id = bus_notavailable.bus_id
AND bus_notavailable.DD = '$DD'
AND bus_notavailable.MM = '$MM'
AND bus_notavailable.YYYY = '$YYYY'
.....
WHERE ......
bus_notavailable.bus_id IS NULL
Man)))))) First of all you didn't say what you want to achieve. If you want to select buses that are available on day DD, then you are doing right.
The reason why second row returns 2 rows because as you say you select records where DD not equal to 11. And in this table, both records are suitable. That is why you get 2 rows.
If you want to select only one buss that is available for certain date in case there are many dates in this table you should use distinct keyword.
select distinct bus where dd!=11. You will get one row))
I mean only one row for each bus. So if you have 10 buses available on that date you will have 10 records. One record for each bus.