i have an Array with this string value.
[VALIDUNTIL] => 28.08.23
Now i need to compare it with the todays date and check if the VALIDUNTIL date is in the same month and year as the today´s date
i looked for a while now but i cant find any solution.
while ($row = oci_fetch_assoc($dbResult))
{
$data[] = $row;
}
foreach($data as $ar) {
if ($ar['VALIDUNTIL'] && $ar['VALIDUNTIL'] != null) {
if(strtotime($ar['VALIDUNTIL']) >= strtotime($date)) {
}
}
When i try to do it with timestamps it cant read the VALIDUNTIL date and gives me the 1970 timestamp
strtotime seems not to work too.
tnx 4 help.
while ($row = oci_fetch_assoc($dbResult))
{
if(!empty($row['VALIDUNTIL']) && !is_null($row['VALIDUNTIL'])){
$valid_date = date('d-m-Y', strtotime($row['VALIDUNTIL']));
$current_date = date('d-m-Y');
if($valid_date >= $current_date ) {
echo "True";
}
}
}
Here are the PHP string conversions for time ref. https://www.w3schools.com/php/php_ref_date.asp
echo(strtotime("now") . "<br>");
echo(strtotime("3 October 2005") . "<br>");
echo(strtotime("+5 hours") . "<br>");
echo(strtotime("+1 week") . "<br>");
echo(strtotime("+1 week 3 days 7 hours 5 seconds") . "<br>");
echo(strtotime("next Monday") . "");
echo(strtotime("last Sunday"));
You'd need to have both dates in the same format. The above is from : https://www.w3schools.com/php/func_date_strtotime.asp#:~:text=The%20strtotime()%20function%20parses,are%20mapped%20to%201970%2D2000.
if you echo (strtotime($ar['VALIDUNTIL']) and strtotime($date)) back to the screen then you can visually compare and check to see the format which you are using is the same for both dates and adjust accordingly.
Related
I'm trying to compare if a date is today, or in the past. As far as i can tell i should be able to do date1 <= today but it shows as true even if the date is in the future
I'm getting the date from the database and adding 30 days to it using
echo "End Date: " . $rowTicket['endDate'] . "<br/>";
$disableDate = ($rowTicket['endDate'] != '0000-00-00') ? date('d-m-Y', strtotime('+30 days', strtotime($rowTicket['endDate']))) : '';
And then doing the check using
echo "Is " . $disableDate . " before today's date? (" . date("d-m-Y") . ")";
if($disableDate <= date("d-m-Y")) {
//$colourTR = $red;
echo " - Yes<br/><br/>";
} else {
echo " - No<br/><br/>";
}
The output i get from the echo's is
End Date: 2021-09-01
Is 01-10-2021 before today's date? (26-10-2021) - Yes
End Date: 2021-10-15
Is 14-11-2021 before today's date? (26-10-2021) - Yes
Because you compare strings, while should compare timestamps
echo "End Date: " . $rowTicket['endDate'] . "<br/>";
$disableDate = $rowTicket['endDate'] != '0000-00-00'
? strtotime('+30 days', strtotime($rowTicket['endDate']))
: '';
$today = strtotime('today midnight');
echo "Is {$disableDate} before today's date? (" . date("d-m-Y", $today) . ")";
if($disableDate <= $today) {
//$colourTR = $red;
echo " - Yes<br/><br/>";
} else {
echo " - No<br/><br/>";
}
You are formatting your dates as strings. PHP has no way of knowing that the string '26-10-2021' should be "less than" the string '14-11-2021'.
If you format them year-first ('Y-m-d'), it will work, but better to compare the integer timestamps (output of strtotime), or DateTimeImmutable objects.
// holiday array
$holy = [
'2020-12-23',
'2020-12-24',
'2020-12-25',
'2020-12-28',
'2020-12-29',
];
$inputDate = '2020-12-23'; // input
$outputDate = get_date($inputDate);
echo "Winning Day: " . $outputDate . "<br />";
echo "<br />";
function get_date($chkDate)
{
global $holy;
$chkDateYoil = date("w", strtotime($chkDate)); // sat(6), sun(0)
if ($chkDateYoil == 6) {
// Saturday when + 2
$timestamp = strtotime($chkDate . " +2 days");
$chkDate = date("Y-m-d", $timestamp);
} else if ($chkDateYoil == 0) {
// Sunday when + 1
$timestamp = strtotime($chkDate . " +1 days");
$chkDate = date("Y-m-d", $timestamp);
}
// If it's a weekday, compare it array
foreach ($holy as $key => $holyday) {
if ($chkDate == $holyday) {
// holiday when + 1
$day_plus = 8 - $chkDateYoil;
$timestamp = strtotime($chkDate." +".$day_plus." days");
$chkDate = date("Y-m-d", $timestamp);
}
}
return $chkDate;
}
Hello, let me ask a question.
The following codes are:
Is the input value weekend?
Or are they included in the array?
in accordance with the judgment
Weekday extraction code.
But there is an error.
in my estimation
December 30th is supposed to come out.
By the way, January 2, 2021 is the result.
Why is that?
sorry
i don't write english very well
Thank you for reading.
The problem is in this line: $day_plus = 8 - $chkDateYoil;, which is calculating the date of the next Monday the first time it's executed.
You're then looping through the rest of the $holy array, and updating $chkDate if necessary, but you're not recalculating the value of $chkDateYoil, so the output depends on the day of the week you run this. Today (23rd December) it stops on 2nd January
Your code can be simplified by just incrementing the date by 1 day and performing the checks again, continuing until you get a result. I've also used the PHP function in_array() to simplify the search of the $holy array, and incorporated it into the same test as Saturday and Sunday.
// holiday array
$holy = [
'2020-12-23',
'2020-12-24',
'2020-12-25',
'2020-12-28',
'2020-12-29',
];
$inputDate = '2020-12-23'; // input
$outputDate = get_date($inputDate);
echo "Winning Day: " . $outputDate . "<br />";
echo "<br />";
function get_date($chkDate)
{
global $holy;
do {
$chkDateYoil = date("w", strtotime($chkDate)); // sat(6), sun(0)
if (($chkDateYoil == 0) || ($chkDateYoil == 6) || (in_array($chkDate, $holy))) {
$timestamp = strtotime($chkDate . " +1 days");
$chkDate = date("Y-m-d", $timestamp);
} else {
return $chkDate;
}
} while (true);
}
I have a DATE field on my MySQL table. Let's say the value is 2015-05-05.
I would like to check if the current time is before or after that.
This is my code:
foreach ($row as $row)
{
$ExpDate = strtotime($row['exp_date']);
$Today = strtotime(date("Y-m-d"));
echo $Today . ' - ' . $ExpDate;
if ($Today > $ExpDate)
{
exit('<M>LicenseExpired<M>');
}
}
The problem is that it's not working. The value of exp without strtotime is 2015-05-05. It I add the strtotime, the value becomes an empty string.
How am I able to solve this problem or what would be a good way to compare dates in PHP?
When comparing dates in MySQL there is no reason to take the extra step and use string_to_time(). The below example should work just fine. The format of MySQL DATE is designed in such a way that comparisons of this nature work naturally without any extra steps needed.
foreach ($row as $row)
{
$ExpDate = $row['exp_date'];
$Today = date("Y-m-d");
echo $Today . ' - ' . $ExpDate;
if ($Today > $ExpDate)
{
exit('<M>LicenseExpired<M>');
}
}
try this
foreach ($row as $row)
{
$ExpDate = new DateTime($row['exp_date']);
$Today = new DateTime(date("Y-m-d"));
$interval = $ExpDate->diff($Today);
//echo $interval->format('%R%a days'); <--- to diffenernce by days.
if ($interval > 0)
{
exit('<M>LicenseExpired<M>');
}
}
I have a table called schedule and a column called Date where the column type is date. In that column I have a range of dates, which is currently from 2012-11-01 to 2012-11-30. I have a small form where the user can enter a range of dates (input names from and to) and I want to be able to compare the range of dates with the dates currently in the database.
This is what I have:
////////////////////////////////////////////////////////
//////First set the date range that we want to use//////
////////////////////////////////////////////////////////
if(isset($_POST['from']) && ($_POST['from'] != NULL))
{
$startDate = $_POST['from'];
}
else
{
//Default date is Today
$startDate = date("Y-m-d");
}
if(isset($_POST['to']) && ($_POST['to'] != NULL))
{
$endDate = $_POST['to'];
}
else
{
//Default day is one month from today
$endDate = date("Y-m-d", strtotime("+1 month"));
}
//////////////////////////////////////////////////////////////////////////////////////
//////Next calculate the total amount of days selected above to use as a limiter//////
//////////////////////////////////////////////////////////////////////////////////////
$dayStart = strtotime($startDate);
$dayEnd = strtotime($endDate);
$total_days = abs($dayEnd - $dayStart) / 86400 +1;
echo "Start Date: " . $startDate . "<br>End Date: " . $endDate . "<br>";
echo "Day Start: " . $dayStart . "<br>Day End: " . $dayEnd . "<br>";
echo "Total Days: " . $total_days . "<br>";
////////////////////////////////////////////////////////////////////////////////////
//////Then we're going to see if the dates selected are in the schedule table//////
////////////////////////////////////////////////////////////////////////////////////
//Select all of the dates currently in the schedule table between the range selected.
$sql = ("SELECT Date FROM schedule WHERE Date BETWEEN '$startDate' AND '$endDate' LIMIT $total_days");
//Run a check on the query to make sure it worked. If it failed then print the error.
if(!$result_date_query = $mysqli->query($sql))
{
die('There was an error getting the dates from the schedule table [' . $mysqli->error . ']');
}
//Set the dates to an array for future use.
// $current_dates = $result_date_query->fetch_assoc();
//Loop through the results while a result is being returned.
while($row = $result_date_query->fetch_assoc())
{
echo "Row: " . $row['Date'] . "<br>";
echo "Start day: " . date('Y-m-d', $dayStart) . "<br>";
//Set this loop to add 1 day to the Start Date until it reaches the End Date
for($i = $dayStart; $i <= $dayEnd; $i = strtotime('+1 day', $i))
{
$date = date('Y-m-d',$i);
echo "Loop Start day: " . date('Y-m-d', $dayStart) . "<br>";
//Run a check to see if any of the dates selected are in the schedule table.
if($row['Date'] != $date)
{
echo "Current Date: " . $row['Date'] . "<br>";
echo "Date: " . $date . "<br>";
echo "It appears as though you've selected some dates that are not in the schedule database.<br>Please correct the issue and try again.";
return;
}
}
}
//Free the result so something else can use it.
$result_date_query->free();
As you can see I've added in some echo statements so I can see what is being produced. From what I can see it looks like my $row['Date'] is not incrementing and staying at the same date. I originally had it set to a variable (currently commented out) but I thought that could be causing problems.
I have created the table with dates ranging from 2012-11-01 to 2012-11-15 for testing and entered all of this php code onto phpfiddle.org but I can't get the username provided to connect.
Here is the link: PHP Fiddle
I'll be reading through the documentation to try and figure out the user connection problem in the meantime, I would really appreciate any direction or advice you can give me.
I have a series of weekly events in a database along with the day they happen on (in full form, so: 'Monday', 'Tuesday' etc). I've successfully printed the events in a while loop ordered by today, tomorrow, etc, but I'd like to put the date in brackets next to each one.
I thought it might be a case of (mock code):
$today = date("l");
$todays_date = date("j M");
if (day == $today) {
$date = $todays_date;
}
else if (day == $today + 1) {
$date = $todays_date + 1;
}
else if (day == $today + 2) {
$date = $todays_date + 2;
}
etc...
But I'm not so sure. It'd be ideal if I could just have the date in the database, but this seems to go against the grain of what MySQL is about.
Also, I'd like to ideally format the date as: 11 Jun.
EDIT
Presumably it's also got to fit into my while loop somehow:
if($result && mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_array($result)) {
$items[] = array($row[0]);
echo "<option>" . $row[0] . "</option>";
}
}
You can use strtotime?
echo "Today: ".date("j M");
echo "Tomorrow: ".date("j M", strotime("+1 day"));
You can use strtotime:
echo strtotime("+1 day");