I am looking for a way to populate an option value.
<?php for ($i = 1; $i <= 300; $i++) : ?>
<option value="<?php echo $i; ?>">1.<?php print $i; ?> AVAX</option>
<?php endfor; ?>
I want for the above code to work something like this. 1.00 - 1.99 after reaching 1.99 I want it to navigate to 2.00 - 2.99 and so forth and onward until the numbers run out. How can I achieve that? The above result returns only 1.300
You can set the increment to whatever you want
<?php for ($i = 1; $i <= 300; $i+=0.01) : ?>
<option value="<?php echo number_format($i, 2, '.', ''); ?>"><?php echo number_format($i, 2, '.', ''); ?> AVAX</option>
<?php endfor; ?>
demo
What do you mean by until numbers run out?
You do realize that numbers are infinite.
Therefore, I can only assume that you want the options to have the series:
1.01, 1.02.... 1.99, 2.00, 2.01, 2.02, .... until 10.00.
If 10 is not the highest number you want to reach, then you can change the end limit of $i in the following code:
<?php
for ($i = 1; $i <= 10; $i++) {
for ($j = 0; $j <= 99; $j++) {
$num = "$i." . sprintf('%02d',$j); // 1.01, 1.02, ...
echo '<option value="' . $num . '">AVAX</option>';
}
}
?>
Related
I am working with some legacy PHP code so re-writing this isn't an option at this point but I have a dropdown for number of years and months of employment and currently they go from 0 - 11, 0 - 65. Can a PHP loop array numbers starting at NULL, which adds -Select- as the default forcing user to make a selection, but also have 0 as the starting number?
I've tried:
for ($i = NULL; $i <= 11; $i++) {
echo $i;
}
But 0 is no loner an option
This is what I have currently:
for ($i = 0; $i <= 11; $i++) {
echo $i;
}
I need it to display as:
-Select-
0
1
2
3
4
etc
Echo the text before echoing the numbers using a loop.
<?php
echo '-Select-';
for($i = 0; $i <= 11; ++$i) {
echo $i;
}
NULL++ would not increase the value of NULL, which is essentially nothing. Why not start at -1, and if ($i == -1) then echo select?
It would look like this:
for ($i = -1; $i <= 11; $i++) {
if ($i == -1) {
echo '-Select-';
} else {
echo $i;
}
}
What I want is the first loop iterating from 1 to 4 and the second loop from 5 to 6.
Here is my code:
<?php
for ($i = 1 ; $i <= 4 ; $i++)
{
echo $i . "<br>";
}
?>
<hr>
<?php
for ($i = 1 ; $i <= 2 ; $i++)
{
echo $i . "<br>";
}
?>
The loops you've given are:
1st loop: from 1 to 4
2nd loop: from 1 to 2
First loop is ok, but seconds needs to be modified. Use $i<=6 and don't initialize $i variable.
This will give you:
1st loop: from 1 to 4
2nd loop: from (value that 1st loop have ended)+1 to 6, so (4+1) to 6, 5 to 6
<?php
$i = 0; // be sure 'i' is visible in both loops
for ($i=1; $i<=4; $i++) // form 1 to 4
{
echo $i . "<br>";
}
?>
<hr>
<?php
$i++; // start from 5, not 4
for (; $i<=6; $i++) // from the previous value to 6
{
echo $i . "<br>";
}
?>
Your problem
The second for loop resets your $i variable to 1:
for ($i = 1 ; $i <= 2 ; $i++)
Solution
You can use a while loop instead of your second for loop:
<?php
for ($i = 1; $i <= 4; $i++)
{
echo $i . "<br>";
}
?>
<hr>
<?php
while ($i <= 6) // `<= 6` instead of `<= 2`, since we keep $1's value
{
echo $i . "<br>";
$i++;
}
?>
Rather than using two loops for this, why not just output the <hr> tag at the appropriate point within the same one? If you carry on with adding extra loops, first of all you'll run into confusing problems like this about (re-)initialising variables, and you'll also quickly end up with a lot of unnecessary duplicated code.
You can use the PHP modulo operator (%) to output the <hr> tag after every fourth element, which will both reduce the complexity and be a lot more extensible if you later add more elements:
for ($i=1; $i<=6; $i++) {
echo $i . "<br>";
if ($i % 4 === 0) {
echo "<hr>";
}
}
See https://eval.in/976102
Here is my php code given below when I run it in my browser its display 1 continuously. My question is why its show like this? After execution its displays a fatal error : maximum execution time is exceeded. what is that?
<?php
for ($i=1; $i<=5; $i+1) {
echo $i." ";
}
?>
Give me proper answer. Make me sure that what is the execution time of php code?
TIA
$i+1 does not increment the value of $i. It only adds 1 to what is in $i but it does not assign it back to $i. Your loop does this:
$i = 1
while ($i<=5) {
echo $i." ";
$i+1;
}
$i+1 on it's own doesn't do anything.
You need something like $i = $i + 1. Or for short $i += 1. Or even shorter and better: $i++.
for ($i=1; $i<=5; $i++) {
echo $i . " ";
}
It is because of $i+1 in for loop. This is basically an expression and it produces a result but you never assign this result to $i. Therefore you would rather do something like $i = $i + 1 or, in real life, use incrementation $i++. So the final code will looks like:
for ($i = 1; $i <= 5; $i++) {
echo $i." ";
}
use $i++ not $i+1, $i++ is $i=$i+1
Change your code to
<?php
for ($i=1; $i<=5; $i++) {
echo $i." ";
}
?>
because first you must set value for $i
You need to do
<?php
for( $i = 1; $i <= 5; $i++) {
echo $i." ";
}
?>
Now you just say 1 + 1 but you don't assign it to anything. You could use $i = $i + 1 but it's the same as $i++
<?php
for ($i=1; $i<=5; $i++) {
echo $i." ";
}
?>
in a for loop, every turn you need to increase value of $i. but you forgot to increase value of $i. You wrote $i +1 but it needs to be assigned with new value of $i.
In short, you should change $i +1 to $i = $i +1 or $i ++
the right code:
<?php
for ($i=1; $i<=5; $i = $i+1) {
echo $i." ";
}
?>
You are not changing the value of $i in the loop. Either $i =$i +1 or $i++ instead of $i + 1 will do.
You've problem in printing the line. It should look like
<?php
for ($i=1; $i<=5; $i++) {
echo $i;
}
?>
VERY basic question: I currently have the following (array?) for a select box within a form but I need to change the jump/step in numbers that appear in the drop down. At the moment it is in multiples of 100, from 300-1500 but I need multiples of 100 up to 1000 and then 1250 and 1500.
for($i = 300; $i <= 1500; $i += 100)
Have you tried using the function range() ?
You can configure start, end, and step.
http://php.net/manual/en/function.range.php
Just add the options from 100 to 1000 with a for loop and then add the other two options afterwards.
<select>
<?php
for($i = 100; $i <= 1000; $i+=100)
{
echo "<option>" . $i . "</option>";
}
?>
<option>1250</option>
<option>1500</option>
</select>
$step = 100;
for($i = 300; $i <= 1500; $i += $step){
if ($i >= 1000) {$step = 250}...
or
$inc = 100;
foreach (range(300, 1500, $inc) as $number)
{
echo "<Option>".$number."</Option>";
if ($number >= 1000){$inc = 250}
}
but i am not 100% sure if the second one works
I am trying to make a triangular-shaped set of lines of decreasing numbers like this :
5
45
345
2345
12345
I tried this :
for($i=1;$i<=5;$i++)
{
for($j=1;$j<=$i;$j++)
{
echo $j;
}
echo "<br>";
}
But it is printing the low number first and appending increasing numbers like this :
1
12
123
1234
12345
The inner loop needs to count down instead of up.
You can either subtract the outer loop's variable from the limit to get the starting point and count down:
for ($i = 0; $i < 5; $i++)
{
for ($j = 5 - $i; $j > 0; $j--)
{
echo $j;
}
echo "<br>";
}
or change the outer loop to count down from the limit as well.
for ($i = 5; $i >= 1; $i--)
{
for ($j = $i; $j >= 1; $j--)
{
echo $j;
}
echo "<br>";
}
This is pretty straightforward:
$max = 5;
echo "<pre>";
for($line=0; $line<$max; $line++) {
$min_this_line = $max-$line;
for($num = $min_this_line; $num <= $max; $num++) {
echo $num;
}
echo "\n";
}
echo "</pre>";
Output:
5
45
345
2345
12345
I think I would declare the $peak value, then use a for() loop to decrement the counter down to 1, and use implode() and range() to build the respective strings inside the loop.
This isn't going to outperform two for() loops, but for relatively small $peak values, no one is going to notice any performance hit.
Code: (Demo)
$peak = 5;
for ($i = $peak; $i; --$i) {
echo implode(range($i, $peak)) , "\n";
}
or with two loops: (Demo)
Decrement the outer loop and increment the inner loop.
$peak = 5;
for ($i = $peak; $i; --$i) {
for ($n = $i; $n <= $peak; ++$n) {
echo $n;
}
echo "\n";
}
Both output:
5
45
345
2345
12345