PHP PDO REPLACE works in phpadmin but not in php - php

Question

Trying to update the record (timestamp) if it exists or insert a new record if it doesn't exist.
Table is:
id = int 12 primary key, auto increment
userid = int 12
viewerid = int 12
viewDateTime = TIMESTAMP
This sql works in phpmyadmin but not in php
SELECT #id := id FROM `profileViews` WHERE `userid` = 31 AND `viewerid` = 30 LIMIT 1;
REPLACE INTO `profileViews`(id, `userid`, `viewerid`, `viewDateTime`)
VALUES (#id, 31, 30, now());
Here is the php version:
$INSERTViewSQL = "SELECT #id := id FROM `profileViews` WHERE `userid` = ? AND `viewerid` = ? LIMIT 1;
REPLACE INTO `profileViews`(id, `userid`, `viewerid`, `viewDateTime`)
VALUES (#id, ?, ?, now());";
try{
$DBConnection->prepare($INSERTViewSQL)->execute([$profileid, $_SESSION["id"], $profileid, $_SESSION["id"]]);
} catch(PDOException $e) {
file_put_contents($ErrorLogFileForPDO, 'update view : ' .$e->getMessage()."\n", FILE_APPEND);
}
Here is the error message:
update view : SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'REPLACE INTO profileViews(id, userid, viewerid, viewDateTime)
VALUES (#i' at line 2
Thanks‼️

Answer 1

MySQL document says:
SQL syntax for prepared statements does not support multi-statements (that is, multiple statements within a single string separated by ; characters).
So you need to fetch id value first, execute replace statement after that.
$stmt = $DBConnection
->prepare("SELECT id FROM ...");
$stmt->execute([$profileid, $_SESSION["id"]]);
$id = $stmt->fetchColumn();
$DBConnection
->prepare("REPLACE INTO ...");
->execute([$id, $profileid, $_SESSION["id"]]);