Increase year after every 3 iterations while looping - php

Question

I have an array contain n number of elements can be 6 or 8, like that:
$langs = ["PHP", "JAVA", "Ruby", "C", "C++", "Perl"];
I would like to add one year evenly next to the elements
Desired output in case of 6 elements:
PHP - 2022
JAVA - 2022
Ruby - 2022
C - 2023
C++ - 2023
Perl - 2023
Desired output in case of 9 elements:
PHP - 2022
JAVA - 2022
Ruby - 2022
C - 2023
C++ - 2023
Perl - 2023
Python - 2024
Javascript - 2024
Mysql - 2024
My try :
$date = Carbon::now();
foreach($langs as $key => $lang){
if(count($langs) % $key == 0){
echo $lang .' - '. $date->addYear();
}
}

Answer 1

Bump the year every time $key is not zero and $key / 3 has no remainder.
Code: (Demo)
$langs = ["PHP", "JAVA", "Ruby", "C", "C++", "Perl", "Perl", "Python", "Javascript", "Mysql"];
$date = Carbon::now();
foreach ($langs as $key => $lang){
if ($key && $key % 3 === 0) {
$date->addYear();
}
echo $lang .' - '. $date->year . PHP_EOL;
}
To be perfectly honest, I don't see any benefit is calling a datetime wrapper for this very basic task. You can easily replace all usage of Carbon with PHP's native date() function. (Demo)
$langs = ["PHP", "JAVA", "Ruby", "C", "C++", "Perl", "Perl", "Python", "Javascript", "Mysql"];
$year = date('Y');
foreach ($langs as $key => $lang){
if ($key && $key % 3 === 0) {
++$year;
}
echo $lang .' - '. $year . PHP_EOL;
}

Answer 2

I'd use %3 as suggested by #mickmackusa but I would avoid incrementing the year of a date object as here you just need to get the year number and increment it (the month/day/hour/etc. is not an info you need to keep):
$langs = ["PHP", "JAVA", "Ruby", "C", "C++", "Perl", 'foo', 'bar', 'bam'];
$year = Carbon::now()->year;
foreach ($langs as $key => $lang){
if ($key && $key % 3 === 0) {
$year++;
}
echo $lang .' - '. $year . PHP_EOL;
}