How to get webhook response data using tradingview and php - php

I'm trying to get Tradingview signals to my remote php script using webhook and trading view alerts. I can't succeed . I'm following this way
In my trading view strategy I have this
strategy.entry("Long", strategy.long, alert_message = "entry_long")
strategy.exit("Exit Long", "Long", limit=LONG_take_profit, stop=LONG_stop_loss, alert_message = "exit_long")
then I set the alert as follow
Then I set a PHP script as follow to receive the POST curl JSON data from Trading view
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
// fetch RAW input
$json = file_get_contents('php://input');
// decode json
$object = json_decode($json);
// expecting valid json
if (json_last_error() !== JSON_ERROR_NONE) {
die(header('HTTP/1.0 415 Unsupported Media Type'));
}
$servdate2 = time();
$servdate=date('d-M-Y H:i:s',$servdate2);
file_put_contents("/home/user/public_html/data.txt", "$servdate :".print_r($object, true),FILE_APPEND);
}
I receive the alert via email correctly but I do not receive data in /home/user/public_html/data.txt . What am I doing wrong ? How to send the Tradingview JSON data to my remote PHP script ?

I'm not familiar with PHP, but you've asked:
How to send the Tradingview JSON data to my remote PHP script ?
Your alert message as it is currently written in the alert_message argument, is not valid JSON and therefore it is sent as a txt/plain content type. If you want the alert to be sent as application/json you will need to have it in a valid JSON.
Webhooks allow you to send a POST request to a certain URL every time the alert is triggered. This feature can be enabled when you create or edit an alert. Add the correct URL for your app and we will send a POST request as soon as the alert is triggered, with the alert message in the body of the request. If the alert message is valid JSON, we will send a request with an "application/json" content-type header. Otherwise, we will send "text/plain" as a content-type header.
You can read more about it here.
EDIT:
You can make minor adjustments to your code, and it will be sent as JSON:
strategy.entry("Long", strategy.long, alert_message = '{"message": "entry_long"}')
strategy.exit("Exit Long", "Long", limit=LONG_take_profit, stop=LONG_stop_loss, alert_message = '{"message": "exit_long"}')

Replace the script with:
<?php
file_put_contents("/home/user/public_html/data.txt", print_r([$_GET, $_POST, $_SERVER], true));
to better understand the incoming data.
Maybe the data are present in $_POST variable, if not, post the whole result here (via pastebin).
(also make sure the PHP script starts with <?php)

Related

Wordpress receiving a payload via a response url from third party API

I am sending & receiving JSON responses from a third party API, in one instance though they need to send a response to a url on my site ie: https://my-wordpress-site/api/confirm?transaction=T0efewgfweg78105 Can someone point me in the right direction on how to receive the payload from this response? The payload will be a JSON response like: “Status”: "Success" What script will I run on https://my-wordpress-site/api/confirm.php
If I understand the situation correctly
You can fetch this data with this snippet:
if(isset($_REQUEST['transaction']) && !empty($_REQUEST['transaction']))
{
$response_body = file_get_contents('php://input');
$data = json_decode($response_body);
}
php://input is a read-only stream that allows you to read raw data from the request body

Get and Send file with PHP and RESTful API

One of my partners has an API service which should send an HTTP POST request whenever a new file is published. This requires me to have an api file which will get the POST this way:
http://myip:port/api/ReciveFile
and requesting that the JSON format request should be:
{
"FILE ":"filename.zip",
"FILE_ID":"123",
"FILE_DESC":"PRUPOUS_FILE",
"EXTRAVAR":"",
"EXTRAVAR2":"",
"USERID":" xxxxxxxxxxxx",
"PASSWORD":"yyyyyyyyyyy"
}
Meanwhile it should issue a response, in JSON format if it got the file or not
{"RESULT_CODE":0,"RESULT_DESCR":""}
{"RESULT_CODE":1001,"RESULT_DESCR":"Bad request"}
And after, when I am finished elaborating the file, I should send back the modified file same way.
The question is, now basically from what I understand he will send me the variables witch I have to read, download the file, and send a response back.
I am not really sure how to do this any sample code would be welcomed!
I'm not sure exactly what the question is, but if you mean creating a success response in JSON for if an action occurred while adding data to it which is what can be understood from the question, just create an array with the values you wish to send back to the provider and do json_encode on the array which should create json and just print it back as a response.
About receiving the information; all you have to do is use the integrated curl functions or use a wrapper (Guzzle, etc) to output the raw JSON or json_decode data into a variable and do whatever you please with it.
From what I read in the question, you wish to modify the contents of it. This can be achieved by just decoding the json and changing the variables in the array, then printing the modified JSON back as a response.
Example (this uses GuzzleHTTP as an example):
$res = $client->request('GET', 'url');
$json = $res->getBody();
$array = json_decode($json, 1); // decode the json
// Start modifying the values or adding
$array['value_to_modify'] = $whatever;
$filename = $array['filename']; // get filename
// make a new request
$res = $client->request('GET', 'url/'.$filename);
// get the body of specified filename
$body = $res->getBody();
// Return the array.
echo json_encode($body);
References:
http://docs.guzzlephp.org/en/latest/

POST data not received on server side

I use Postman (the Chrome app) to send POST data to a URL but the POST data are never received by the PHP file, no matter how I change the content-type before sending. Is there a server setting on Apache that stops post data from external sources?
This is the URL:
http://friendesque.com/arranged/handler.php
And this is the content of the handler.php file:
<?php
echo("Inside file");
echo("JSON:");
$json = file_get_contents('php://input');
echo($json);
echo("POST:");
print_r($_POST);
echo("GET:");
print_r($_GET);
?>
In order for data to be available in $_POST array, the following conditions should be met:
Request must be sent with POST HTTP method
Content-Type header must be set to application/x-www-form-urlencoded
Request payload (body) must be in the form of URL-encoded parameters, e.g.
param1=a&param2=b
I sent to your URL a request that meets those 3 conditions and got my data available in $_POST array.
Use file name like /index.php . It will work !!

How to access a JSON request body of a POST request in Slim?

I'm just a newbie in the Slim framework. I've written one API using Slim framework.
A POST request is coming to this API from an iPhone app. This POST request is in JSON format.
But I'm not able to access the POST parameters that are sent in a request from iPhone. When I tried to print the POST parameters' values I got "null" for every parameter.
$allPostVars = $application->request->post(); //Always I get null
Then I tried to get the body of a coming request, convert the body into JSON format and sent it back as a response to the iPhone. Then I got the parameters' values but they are in very weird format as follows:
"{\"password\":\"admin123\",\"login\":\"admin#gmail.com\",\"device_type\":\"iphone\",\"device_token\":\"785903860i5y1243i5\"}"
So one thing for sure is POST request parameters are coming to this API file. Though they are not accessible in $application->request->post(), they are coming into request body.
My first issue is how should I access these POST parameters from request body and my second issue is why the request data is getting displayed into such a weird format as above after converting the request body into JSON format?
Following is the necessary code snippet:
<?php
require 'Slim/Slim.php';
\Slim\Slim::registerAutoloader();
//Instantiate Slim class in order to get a reference for the object.
$application = new \Slim\Slim();
$body = $application->request->getBody();
header("Content-Type: application/json");//setting header before sending the JSON response back to the iPhone
echo json_encode($new_body);// Converting the request body into JSON format and sending it as a response back to the iPhone. After execution of this step I'm getting the above weird format data as a response on iPhone.
die;
?>
Generally speaking, you can access the POST parameters individually in one of two ways:
$paramValue = $application->request->params('paramName');
or
$paramValue = $application->request->post('paramName');
More info is available in the documentation: http://docs.slimframework.com/#Request-Variables
When JSON is sent in a POST, you have to access the information from the request body, for example:
$app->post('/some/path', function () use ($app) {
$json = $app->request->getBody();
$data = json_decode($json, true); // parse the JSON into an assoc. array
// do other tasks
});
"Slim can parse JSON, XML, and URL-encoded data out of the box" - http://www.slimframework.com/docs/objects/request.html under "The Request Body".
Easiest way to handle a request in any body form is via the "getParsedBody()". This will do guillermoandrae example but on 1 line instead of 2.
Example:
$allPostVars = $application->request->getParsedBody();
Then you can access any parameters by their key in the array given.
$someVariable = $allPostVars['someVariable'];
Slim will json_decode the post body for you using this middleware
https://www.slimframework.com/docs/v4/middleware/body-parsing.html

Receive JSON object from HTTP Get in PHP

I am trying to implement a php client that sends an HTTP GET to the server which sends back a JSON object with the return information. I know how to decode the JSON once my php script has received it, but how would I go about actually getting it?
EDIT: Note - I send the server an HTTP GET, and it generates and sends back a JSON file. It is not a file sitting on the server.
Check out file_get_contents
$json = file_get_contents('http://somesite.com/getjson.php');
Browsers act differently based on what the server responds. It does not matter what type of request you make to the server (be it GET, POST, etc), but to return JSON as a response you have to set the header in the script you make the request to:
header('Content-Type: application/json;charset=utf-8;');
And then echo the JSON string, for example:
//...populating your result data array here...//
// Print out the JSON formatted data
echo json_encode($myData);
User agent will then get the JSON string. If AJAX made the request then you can simply parse that result into a JavaScript object that you can handle, like this:
//...AJAX request here...//
// Parse result to JavaScript object
var myData=JSON.parse(XMLHttp.responseText);
The header itself is not -really- necessary, but is sort-of good practice. JSON.parse() can parse the response regardless.

Categories