So I'm using a checkbox to insert data into MySql database.
When check it stores "finish"
When unchecked if stores "pending"
Now for an edit feature, I have to fetch and display the data from the database. I need the checkbox to be checked or unchecked if it is stored as finish or pending. Appreciate your help, thank you.
The code to fetch the data is shown below:
<?php
$query = ("SELECT * FROM ebook WHERE Eid='" . $Eid . "'");
$result = mysqli_query($con, $query);
$rows = mysqli_fetch_assoc($result);
?>
Displaying data and checkbox:
<html>
<input type="text" name="title" value="<?php echo $rows["Title"]; ?>">
<input class="tgl tgl-flip" id="chk" type="checkbox" name="chk" />
</html>
Put a condition echo inside the input.
<input class="tgl tgl-flip" id="chk" type="checkbox" name="chk" <?php if ($rows['status'] == 'finish') { echo "checked"; } ?>/>
Related
I have a table in the database, I can edit a column of particular row at a time. but, i want to edit multiple columns of a single row at a time with an option of edit and then save it to the database ,we can do it from back-end by editing in the database itself. But, i want to do it from front-end .Now i am able to display the data in the table. I am new to coding , so can anyone help me where to start for this particular task of editing multiple columns at the same time.
Here is the code for displaying the data..
<?php
include('db.php');
include 'header.php';
include 'gobacktomenu.php';
$TND_ID = $_GET['TND_ID'];
$sql = "SELECT * FROM new_tnds WHERE TND_ID = ('".$TND_ID."')";
$result = $link->query($sql);
echo "<div style='overflow-x:auto;'><table border = '1'><font size = '2' face='verdana'>
<th>TND ID</th><th>Site name S1</th><th>Site name S2</th><th>Call sign S1</th><th>Idea ID S1</th><th>Call sign S2</th><th>Idea ID S2</th><th>Site to integrate</th><th>True azimuth (°) S1</th><th>True azimuth (°) S2</th><th>Pathlength (km)</th><th>TR Antenna diameter (m)</th><th>TR Antenna height (m) S1</th><th>TR Antenna height (m) S2</th><th>Channel ID S1</th><th>Channel ID S2</th><th>Design frequency S1</th><th>Design frequency S2</th><th>Polarization</th><th>Radio model</th><th>TX power (dBm)</th><th>Receive signal (dBm)</th><th>Planning Remarks</th><th>Projects Remarks Uploaded by</th><th>O & M Remarks Uploaded by</th><th>Planning Remarks Uploaded by</th><th>TXN NOC Remarks Uploaded by</th></tr>";
if ($result->num_rows > 0) {
// output data of each row
$row = $result->fetch_assoc();
echo "<tr><td>".$row["TND_ID"]."</td><td>".$row["Site_name_S1"]."</td><td>".$row["Site_name_S2"]."</td><td>".$row["Call_sign_S1"]."</td><td>".$row["Idea_ID_S1"]."</td><td>".$row["Call_sign_S2"]."</td><td>".$row["Idea_ID_S2"]."</td><td>".$row["Site_to_integrate"]."</td><td>".$row["True_azimuth_S1"]."</td><td>".$row["True_azimuth_S2"]."</td><td>".$row["Path_length_(km)"]."</td><td>".$row["TR_Antenna_diameter_(m)_S1"]."</td><td>".$row["TR_Antenna_height_(m)_S1"]."</td><td>".$row["TR_Antenna_height_(m)_S2"]."</td><td>".$row["#1_Channel_ID_S1"]."</td><td>".$row["#1_Channel_ID_S2"]."</td><td>".$row["#1_Design_frequency_S1"]."</td><td>".$row["#1_Design_frequency_S2"]."</td><td>".$row["Polarization"]."</td><td>".$row["Radio_model_S1"]."</td><td>".$row["TX_power_(dBm)_S1"]."</td><td>".$row["Receive_signal_(dBm)_S1"]."</td><td>".$row["Planning_Remarks"]."</td><td>".$row["Projects_remarksupdated_user_name"]."</td><td>".$row["O_M_remarksupdated_user_name"]."</td><td>".$row["Planning_remarksupdated_user_name"]."</td><td>".$row["txn_noc_remarksupdated_user_name"]."</td></tr>";
}
echo "</table></div>";
$link->close();
?>
you can use this structure ,this can be used for editing 2 tables and multiple columns table a has columns (aid,a1,a2) table b has columns (bid,b1,b2) i know code looks little rough but just wrote it in 5 min to give you an idea
<?php
//this only executes when button is clicked
if (isset($_POST["submit"] && $_POST["submit"]!=""){
$counta=$_POST["aid"];
//loops through the posts inside here do your query with the set command
//like "update a set a1='$a1',a2='$a2" where aid ='$_POST["aid'][$i]"
for($i=0;$i<$count;$i++){
$a1[$i]=$_POST["a1"][$i];
$a2[$i]=$_POST["a2"][$i];
//your query here
}
$countb=$_POST["bid"];
//loops through the posts inside here do your query with the set command
//like "update b set b1='$b1',b2='$b2" where aid ='$_POST["bid'][$i]"
for($i=0;$i<$count;$i++){
$a1[$i]=$_POST["a1"][$i];
$a2[$i]=$_POST["a2"][$i];
}
//now the part before the button gets clicked
//do your query to select data from database
?>
<html>
<body>
//creating loop inside html
<?php
$a=0;
while($rowa = mysql_fetch_assoc($resulta){
?>
//getting the input data
<input type="checkbox" name="aid[]" value="<?php echo $row["aid"]; ?>>
<label>a1</label>
<input type="text" name="a1[]" value="<?php echo $row["a1"]; ?>>
<label>a2</label>
<input type="text" name="a2[]" value="<?php echo $row["a2"]; ?>>
//ending the loop
<?php
$a++;
}
//b works the same as a
$b=0;
while($rowb = mysql_fetch_assoc($resultb){
?>
<input type="checkbox" name="bid[]" value="<?php echo $row["bid"]; ?>>
<label>b1</label>
<input type="text" name="b1[]" value="<?php echo $row["b1"]; ?>>
<label>b2</label>
<input type="text" name="b2[]" value="<?php echo $row["b2"]; ?>>
<?php
$b++;
}
?>
<input type="submit" name="submit" value="submit">
</body>
</html>
You need use form instead of table while editing and pass the fetched values on input of form and write update query on form submit.
if ($result->num_rows > 0) {
// output data of each row
$row = $result->fetch_assoc();
}
if(isset($_POST['submit']))
{
$query = "update details set Site_name_S1='$_POST['submit']',Site_name_S2='$_POST['Site_name_S2']',Call_sign_S1='$_POST['Call_sign_S1']',Idea_ID_S1='$_POST['Idea_ID_S1'] where TND_ID=$_POST['TND_ID']";
$res = mysql_query($query);
}
<form method="post">
<input type="text" name="id" value="<?php echo $row['TND_ID'] ;?>" >
<input type="text" name="Site_name_S1" value="<?php echo $row['Site_name_S1'] ;?>" >
<input type="text" name="Site_name_S2" value="<?php echo $row['Site_name_S2'] ;?>" >
<input type="text" name="Call_sign_S1" value="<?php echo $row['Call_sign_S1'] ;?>" >
<input type="text" name="Idea_ID_S1" value="<?php echo $row['Idea_ID_S1'] ;?>" >
<input type="submit" name="submit">
</form>
Just check the quotes while writing update query.
You can use Ajax
Just a fragment of code:
.............
<td><input type="text" row_id=".$some_row_num_from_table."
col-name=".$some_col_name_from_table." disabled class="some-val" value=".$some_from_base."></td>
.............
than little Ajax
$('.some-val').dblclick(function() {
$(this).attr('disabled', false);
});
$('.some-val').blur(function() {
$(this).attr('disabled', true);
var send_data = { 'row_id':$(this).attr('row_id'),
'col-name':$(this).attr('col-name'),
'myval':$(this).val()
};
$.ajax({
url:'your_url.php',
data:send_data,
method: 'post',
success: function(data){...}
});
});
your_url.php
if(isset($_POST['row_id'])){
$sql = "UPDATE mytablename SET `".$_POST['col-name']."` = ".$_POST['myval']." WHERE `row_id` = ".$_POST['row_id'];
$link->query($sql); // it s bad query without protect of sql injection JUST DEMO
}
There are many Subject in my database. I called them in a form in checkbox. When some checkbox checked, those value will go on my database in "select_subject" table in subject column. And when checked a radio button for course name, its value will go in "course" column. My mysql query and chackbox code was:
<?php
$result = mysql_query("SELECT * FROM vhsubject WHERE lid= 2");
while($row = mysql_fetch_array($result))
{
echo "<input type='checkbox' name='vhsubject[]' value=".$row['subject_name'].">" .$row['subject_name']."<br />";
}
?>
After checked and submit, my query was
<?php
if (isset($_POST['form'])) {
$query2 = "INSERT INTO select_subject (subject, course) VALUES ('$_POST[vhsubject]', '$_POST[course_radio]')";
$insert = mysql_query ($query2) or die(mysql_error());
if ($insert){
echo "Your registration is complete";
}
}
?>
But it doesn't work. Please help me;
Use Implode Function:
You can not store value in the form of an array in mysql, so first convert array into string by using implode function.
here is the example:
<input name="q1[]" type="checkbox" value="a1">Used e-mail<br>
<input name="q1[]" type="checkbox" value="a2">Used instant messenger & chat room<br>
<input name="q1[]" type="checkbox" value="a3">Made a purchase for personal use<br>
<input name="q1[]" type="checkbox" value="a4">Downloaded/Played a video game<br>
<input name="q1[]" type="checkbox" value="a5">Obtained news/information/current events<br>
<input name="q1[]" type="checkbox" value="a6">Looked for employment (Used classified listings)<br>
<input name="q1[]" type="checkbox" value="a7">Looked for recipes<br>
<input name="q1[]" type="checkbox" value="a8">Downloaded a movie<br>
and now use implode function:
<?php
$q1=implode(',', $_POST['q1']);
?>
To give you an idea of what I am after. I have items that have "info" to them, well say if I check a box to show Model, I want to be able to go in at a later date and uncheck it.
Is there anyway that you can uncheck a checkbox and have it be stored as 0 in the database?
Here is my input ( I have 10 of these )
<input type="checkbox" name="showmodel" <?php if ($showmodel == '1') echo "checked='checked'"; ?> />
this is how I am trying to update it
$query = "UPDATE `new_equip` SET `featured`='1',`showmanu`='1',`showmodel`='1' "WHERE `id`='$id' LIMIT 1";
I passed trough the same issue and i solved like this:
<input type="hidden" name="permission[<?php echo $data->permission_id; ?>]" value="off">
<input type="checkbox" name="permission[<?php echo $data->permission_id; ?>]" <?php if($data->permission == 'on') { echo 'checked'; } ?> >
Using WordPress, so PHP, HTML, CSS, JavaScript what is the best method of populating the results of a form upon submission? I could have a form with ddl, radio buttons, etc.
<form>
<input type="radio" name="sex" value="male">Male<br>
<input type="radio" name="sex" value="female">Female
<input type="checkbox" name="vehicle" value="Bike">I have a bike<br>
<input type="checkbox" name="vehicle" value="Car">I have a car
<input type="submit" value="Submit">
</form>
What is the best way of populating the results i.e. "67% of users are Female" and "30% ride bikes" on the same page once the submit button is triggered?
Try something along these lines:
script.php
----------
<html>
<body>
<form method=post action=script.php>
your form here...
</form>
<? if($_SERVER["CONTENT_LENGTH"]>0) {
//form was submitted to script, so process form inputs here and display results...
}
?>
</body>
</html>
<form action="phpfile.php" method="Post">
...form here
</form>
phpfile.php:
<?php
if(isset($_POST['sex'])){
$sex = $_POST['sex'];
}//etc..
//To show the result, simply echo it:
echo $sex;
You'll need some sort of storage system to be able to calculate the amount of each.
So what you would need to do is write a simple query where the value of the field is male or female. Then you can easily calculate it.
What you will need to do is add the form results to the database, then find the total number of results for both categories, then calculate the percent female and the percent bike.
The form page:
<html>
<?php
if(isset($_GET['status']) && $_GET['status'] == "values") {
//connect to DB and select table
$male = count( mysql_query("SELECT gender FROM Table WHERE gender='male'"));
$female = count (mysql_query("SELECT gender FROM Table WHERE gender='female'"));
$car = count (mysql_query("SELECT vehicle FROM Table WEHRE vehicle='car'"));
$bike = count (mysql_query("SELECT vehicle FROM Table WEHRE vehicle='bike'"));
$totalResults = $male + $female;
$totalVehicles = $car + $bike;
$percentFemale = 100 * ($female / $totalResults);
$percentFemale = number_format($percentFemale, 0);
$percentBike = 100 * ($bike / $totalVehicals);
$percentBike = number_format($totalBike, 0);
echo "<p>" . $percentFemale . "% of users are female. </p>";
echo "<p>" . $percentBike . "% of users use bikes. </p>";
} else { ?>
<form action="formProcessor.php" method="POST"><!-- You could also use GET -->
<input type="radio" name="sex" value="male">Male<br>
<input type="radio" name="sex" value="female">Female
<input type="checkbox" name="vehicle" value="Bike">I have a bike<br>
<input type="checkbox" name="vehicle" value="Car">I have a car
<input type="submit" value="Submit">
</form>
<?php } ?>
</html>
The formProcessor.php Page:
<?php
if(isset($_POST["sex"]) && isset($_POST['vehicle'])) {
//Connect to MySQL DB and select table here
$sex = $_POST['sex'];
$vehicle = $_POST['vehicle'];
mysql_query("INSERT INTO Table(sex, vehicle) VALUES($sex, $vehicle)"); //You may also want to add an id column, but...
//Close mysql connection
header("Location: /form.php?status=values");
die();
} else {
die("There was an error in your submission.");
}
?>
I think this answers your question, you've got a way to find the percent of female users and users on bikes. If you need that to be dynamic and show only the greater amount (or show both or something) just add a comment. This also assumes you are not using PDO, if you are, I can adjust the code. I just wrote the code, so I don't know for sure if it works, but here you go!
As the title reveals I got an issue with how to update a checkbox that already has data in my SQL database.
My code looks like following:
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
Name <input type"text" name="inputName" value="<?php echo $hemsida['Namn']; ?>" /> </br>
Commentar <input type"text" name="inputComment" value="<?php echo $hemsida['Comment']; ?>" />
<br/>
</br><input type="checkbox" name="inputAll" value="checked" <?php echo $hemsida['All']; ?>/>Alla
<input type="hidden" name="id" value="<?php echo $_GET['id']; ?>" />
<input type="submit" name="submit" value="Redigera">
<?php
if(isset($_POST['submit'])) {
$u = "UPDATE hemsida SET `Namn`='$_POST[inputName]', `Comment`='$_POST[inputComment]', `ALL`='$_POST[inputALL]' WHERE ID = $_POST[id]";
mysql_query($u) or die(mysql_error());
echo "User has been modified";
header("Location: ..//sokh.php");
}
?>
The echo $hemsida['Namn'],['Comment'], and ['All'] just brings up and shows the old data thats in the database, but I do not understand what to do to update the checkbox. I have looked everywhere but I am stuck. Thank you in advance!
If I understand your question correctly, you are looking for a way to have a checkbox be either checked or not checked depending on database info. If so, I would try something like this. At the top of your code where you get your database info, put
if($conditionForCheck){
$inputAll = ' checked="checked"';
}
Then in your form
<input type="checkbox" name="inputAll"<?php echo $inputAll; ?> />
your question is not clear but i think you have a column in your database named "all" ? and perhaps this column can take only 1 value (true or false) !!
then you can test this value in your form, if the value is true : checkbox will be checked, else : checkbox will not be checked :
<input type="checkbox" name="inputAll" checked="<?php if($hemsida['All'] == true) echo checked; ?>" />Alla
dont use value="", use checked instead, then test value of $hemsida['All'] if it's true echo checked else anything to do
for your php code and server side of your application you can just test if checkbox is checked and then you have choice for what do you want to assign to your column in database, for example if checkbox is checked create a variable (for example $value_of_checkbox) and assign a value ("true" for exampel) to this variable, then include this variable in your sql code for update database column :
if (isset($_POST['inputALL'])) {
$value_of_checkbox = true;
}
else {
$value_of_checkbox = false;
}
if(isset($_POST['submit'])) {
$u = "UPDATE hemsida SET `Namn`='$_POST[inputName]', `Comment`='$_POST[inputComment]', `ALL`='$value_of_checkbox' WHERE ID = $_POST[id]";
mysql_query($u) or die(mysql_error());
echo "User has been modified";
header("Location: ..//sokh.php")
note : i change also sql code in this part : ALL='$value_of_checkbox'