How to get the ages that are greater than 50 in php - php

Question

Need to get all the age keys and count the number of them greater than 50. Given data
$data = '{"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47"}';
Output should be 2 as there are 2 ages greater than 50
This is what I am trying
$array = json_decode($data, true);
$strArray = explode(',', $array['data']);
$temp1 = array();
for($i=0; $i < count($strArray); $i++){
$key_value = explode('=', $strArray[$i]);
$temp1[$i][$key_value[0]] = $key_value[1];
}
print "<pre>";
print_r($temp1);
print "</pre>";
Output is coming as
Array
(
[0] => Array
(
[key] => IAfpK
)
[1] => Array
(
[ age] => 58
)
[2] => Array
(
[ key] => WNVdi
)
[3] => Array
(
[ age] => 64
)
[4] => Array
(
[ key] => jp9zt
)
[5] => Array
(
[ age] => 47
)
)
Need to get all the ages in an array to compare.

Answer 1

If your data is truly semi-structured like that and isn’t too massive, and you want to keep the keys, I think this is a good case for array_shift to reduce the array until it is exhausted:
$data = '{"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47"}';
$array = json_decode($data, true);
$strArray = explode(',', $array['data']);
$clean = [];
while(count($strArray) >= 2){
$key = explode('=', array_shift($strArray))[1];
$age = explode('=', array_shift($strArray))[1];
$clean[$key] = (int)$age;
}
var_dump($clean);
Demo: https://3v4l.org/RIF2q
You should hopefully be able to add whatever logic you need to test ages then.

Answer 2

Short and simple. Hope this will work for you,
$output = [];
$data = '{"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47"}';
$array = json_decode($data, true);
foreach (explode(',',$array['data']) as $key => $value)
{
if(str_contains($value,'age'))
{
$age = explode('=',$value);
if($age[1] > 50)
{
array_push($output, $age[1]);
}
}
}
print_r($output);

Answer 3

An effective way to achieve this since your data is strangely formatted would be to use regex. For some reason, the ?: non capturing group is still being captured so all of the ages will be in the second capture group of the match array - you can play to optimise that.
Once you have all your ages in an array, a simple array_filter for ages larger than 50 is more than enough. You can see a live working example on 3v4l.org.
$data = '{"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47"}';
preg_match_all('/(?:age=)([0-9]+)/', json_decode($data)->data, $matches, PREG_PATTERN_ORDER);
// Only continue if we found any ages in the string
if (array_key_exists(1, $matches))
{
// 58, 64
$greaterThan50 = array_filter($matches[1], fn($age) => intval($age) > 50);
}
Ofc, if you then need the corresponding key, you will need to do more magic.
If you're using less than PHP 7.4, arrow functions are not supported. You can instead replace $greaterThan50 assignment to:
$greaterThan50 = array_filter($matches[1], function($age) {
return intval($age) > 50;
});
See it working live on 34vl.org

Answer 4

Based on your logic, You can do it as follows :
<?php
$data = '{"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47"}';
$array = json_decode($data, true);
$strArray = explode(',', $array['data']);
$keys = array();
$ages = array();
for($i=0; $i < count($strArray); $i++){
$key_value = explode('=', $strArray[$i]);
if ((int)$key_value[1] > 0 ) {
array_push($ages, $key_value[1]);
} else {
array_push($keys, $key_value[1]);
}
}
$result = array_combine($keys, $ages);
$result = array_filter($result, function($age) {
return intval($age) > 50;
});
print "<pre>";
print_r($result);
print "</pre>";