Check every URL in string to remove links of certain sites - php

Question

I want to remove URLs of certain sites within a string
I used this:
<?php
$URLContent = '<p>Google</p><p>AnotherSite</p>';
$LinksToRemove = array('google.com', 'yahoo.com', 'msn.com');
$LinksToCheck = in_array('google.com' , $LinksToRemove);
if (strpos($URLContent, $LinksToCheck) !== 0) {
$URLContent = preg_replace('#<a.*?>([^>]*)</a>#i', '$1', $URLContent);
}
echo $URLContent;
?>
In this example, I want to remove URLs of google.com, yahoo.com and msn.com websites only if any of them found in string $URLContent, but keep any other links.
The result of the previous code is:
<p>Google</p><p>AnotherSite</p>
but I want it to be:
<p>Google</p><p>AnotherSite</p>

Answer 1

One solution would be to explode your $URLContent and compare for each value in $LinksToCheck.
It could be like this :
<?php
$URLContent = '<p>Google</p><p>AnotherSite</p>';
$urlList = explode('</p>', $URLContent);
$LinksToRemove = array('google.com', 'yahoo.com', 'msn.com');
$urlFormat = [];
foreach ($urlList as $url) {
foreach ($LinksToRemove as $link) {
if (str_contains($url, $link)) {
$url = '<p>' . ucfirst(str_replace('.com', '', $link)) . '</p>';
break;
}
}
$urlFormat[] = $url;
}
$result = implode('', $urlFormat);