I want to compare two values of the database. Is it possible to do so with the "where" method? For example, the "tnx_time" would be one DB value and the "value(duration)" the other one. But I cannot now access the DB values on the 3rd field of the "where" function.
Does anybody know how to fix that?
$trnxs = Transaction::where('tnx_time', '<', date("Y-m-d", strtotime( value(duration) )) )
You can use a callback in your "where" clause to create a subquery, would be something like this (might need some changing)
$trnxs = Transaction::where('tnx_time', '<', function ($query) {
$query->selectRaw('date("Y-m-d", strtotime(value(duration)))');
})->get();
Related
I am trying to select records from my MSSQL database, with below parameters:
Column 'first_etd' must be between two dates
Column 'car_id' must not be the same as the current $carId variable.
This is my code:
$carId = 47;
$from = Carbon::now()->subWeeks(2)->startOfWeek()->toDateString();
$to = Carbon::now()->addWeeks(4)->endOfWeek()->toDateString();
$consols = Consol::with(['car'])
->where('car_id', '!=', $carId)
->whereBetween('first_etd', [$from, $to])->get();
The above variable $consols returns no results.
If I remove the ->where('car_id', '!=', $carId) from the statement, I successfully get results.
All the records in my database currently have NULL in the car_id column:
I have also tried to change the != operator to <> without any luck.
So this is not a fix to the SQL statement itself, but more a fix to my problem.
As said in my OP, I can find the two records if I remove the where() method. I figured I could start by getting the records, that's between my two dates and then do the where() filtering on the result collection.
This works:
//Get the records from the database, that's between two dates.
$consols = Consol::with(['car'])->whereBetween('first_etd', [$from, $to])->get();
//Now $consols is a Laravel collection, so I can use the where() method here.
$consols = $this->consols->where('car_id', '!=', $carId);
Above successfully returns the two records.
I have some code like below, the thing I want to ask is with the exactly same // dd($example->count()) #10 why put dd() on each different line has different value ? What change my $example event I never reassign it ?
$example = $car->wheels()->whereBetween(
'created_at',
[
$starDay->format('Y-m-d h:i:s'),
$today->format('Y-m-d h:i:s')
]
)
$total = $example->count();
// dd($example->count()) #10
$totalSuccess = $example->where('status', 'good')->count();
// dd($example->count()) # 5
$colors = $example->select('color', DB::raw('count(*) as total'))
->groupBy('color')
->get()
->toArray();
// dd($example->count()) # []
The value changes because each time you are adding more and more different clauses (like where) to your query. Those calls actually change the query object itself and the changes persist.
At first you have query object in $example with only whereBetween clause. It returns you count of 10 rows in your database.
Then you add where('status', 'good') to the query and it narrows down the selection even more down to 5 rows.
Lastly you change your $example query with select(...) and groupBy() calls.
In Laravel query builder objects are mutated when you add query constructions to it. So when you call $example->where(...) your $example query builder object will now have that where clause.
I have a table called gk and I am currently running two queries. Please have a look at the queries:
Gk::groupBy(DB::raw("MONTH(created_at)"))
->groupBy(DB::raw("YEAR(created_at)"))
->selectRaw('id, user_id, sum(ton) as ton,pl, count(id) as total, sum(w) , created_at')
->with(array('user'=> function($q){
$q->select('id', 'userName', 'profilePic');
}))
->where('user_id', $userData[0]->id)
->get();
This query returns a little summary of every months. As you can I see I am grouping results by months and years. And I have another query which will return all the rows of any given months.
I am running second query like this
$m=Carbon::parse($request->date);
Gk::where('user_id',$request->user_id)->whereRaw(DB::raw("YEAR(created_at)=$m->year"))->whereRaw(DB::raw("MONTH(created_at)=$m->month"))
->orderBy('created_at','desc')
->get();
The second query returns all the rows of any month. I'm executing this query in a foreach loop for all of the months that are returned in the first query.
I am trying to combine this two query into one so that I can get a group of the results by months and years and also all the details of that month.
Any help, suggestions or idea would be extremely helpful.
[Note: For the date in second query, this date is created_at result from the first query.]
Thank you.
The way I read your question is as following: The second query is executed in a loop with results from the first one. Is that right? In my answer I have explained a way to execute the second query just one time instead of in a loop. You'd still have to execute the first query once.
So, I think that you are better of using the Php collection methods:
$results = Gk::where('user_id',$request->user_id)
->orderBy('created_at','desc')
->get()
->groupBy(function (Gk $item) {
return $item->created_at->format('Y-m');
});
The groupBy method has to return an attribute on which you want to group the elements. For this example I think that using a yyyy-mm format will do fine.
Reference: https://laravel.com/docs/5.5/collections#method-groupby
Edit: Maybe you can also get rid of the orderBy method call because you are grouping by afterwards:
$results = Gk::where('user_id',$request->user_id)
->get()
->groupBy(function (Gk $item) {
return $item->created_at->format('Y-m');
});
Edit 2: To combine the information of the two queries, you could do something like the following:
$results = Gk::where('user_id',$request->user_id)
->get()
->groupBy(function (Gk $item) {
return $item->created_at->format('Y-m');
})->map(function(Collection $rows) {
return [
'sum(ton)' => $rows->sum('ton'),
'total' => $rows->count(),
'sum(w)' => $rows->sum('w'),
'rows' => $rows
];
);
Note that I have omitted a few of the selected columns in your first query because they are not unique in the given group by. But feel free to add any logic in the map function. Because we use map() after groupBy, every call of map() will receive a collection of items for one month. You can that use that fabulous collection magic to calculate all values that you need and reduce the number of queries to just one.
I have next query in Laravel Eloquent:
$buildings = Building::select('buildings.*')->join(
DB::raw('('.
(
IngameBuilding::select('buildings.building_id', 'buildings.level')
->join('buildings', 'buildings.id', '=', 'ingame_buildings.building_id')
->toSql()
).
') as `added_buildings`'), 'added_buildings.building_id', '=', 'buildings.building_id')
->where('buildings.level', '>', 'added_buildings.level')
->get();
This query returns all allowed rows from base, but one row more. When I added DB::raw() in where() return values is valid.
Good-working code:
$buildings = Building::select('buildings.*')->join(
DB::raw('('.
(
IngameBuilding::select('buildings.building_id', 'buildings.level')
->join('buildings', 'buildings.id', '=', 'ingame_buildings.building_id')
->toSql()
).
') as `added_buildings`'), 'added_buildings.building_id', '=', 'buildings.building_id')
->where('buildings.level', '>', DB::raw('`added_buildings`.`level`'))
->get();
Why first code workig, hmm.. Wrong?
I'm not a big fan of Laravel at all.
I've got only small experience with this framework but i'm almost sure that where function accepts only a 'constant' values to be checked against.
If you'll get an output of this query using toSQL method on the query object you will see that eloquent will convert it as something like:
(...) where buildings.level > 'added_buildings.level'
so the condition checks if the buildings.level (whatever the type is)
is greater than the given string and not the column value.
Using the DB::raw you're getting the proper sql as the eloquent won't parse/convert it.
You would need to use whereRaw method I suppose.
http://laravel.com/docs/4.2/queries#introduction
Of course I can use order_by with columns in my first table but not with columns on second table because results are partial.
If I use 'join' everything works perfect but I need to achieve this in eloquent. Am I doing something wrong?
This is an example:
//with join
$data = DB::table('odt')
->join('hdt', 'odt.id', '=', 'hdt.odt_id')
->order_by('hdt.servicio')
->get(array('odt.odt as odt','hdt.servicio as servicio'));
foreach($data as $v){
echo $v->odt.' - '.$v->servicio.'<br>';
}
echo '<br><br>';
//with eloquent
$data = Odt::get();
foreach($data as $odt){
foreach($odt->hdt()->order_by('servicio')->get() as $hdt){
echo $odt->odt.' - '.$hdt->servicio.'<br>';
}
}
In your model you will need to explicitly tell the relation to sort by that field.
So in your odt model add this:
public function hdt() {
return $this->has_many('hdt')->order_by('servicio', 'ASC');
}
This will allow the second table to be sorted when using this relation, and you wont need the order_by line in your Fluent join statement.
I would advise against including the order by in the relational method as codivist suggested. The method you had laid is functionally identical to codivist suggestion.
The difference between the two solutions is that in the first, you are ordering odt ( all results ) by hdt.servicio. In the second you are retrieving odt in it's natural order, then ordering each odt's contained hdt by servico.
The second solution is also much less efficient because you are making one query to pull all odt, then an additional query for each odt to pull it's hdts. Check the profiler. Considering your initial query and that you are only retrieving one column, would something like this work?
HDT::where( 'odt_id', '>', 0 )->order_by( 'servico' )->get('servico');
Now I see it was something simple! I have to do the query on the second table and get contents of the first table using the function odt() witch establish the relation "belongs_to"
//solution
$data = Hdt::order_by('servicio')->get();
foreach($data as $hdt){
echo $hdt->odt->odt.' - '.$hdt->servicio.'<br>';
}
The simple answer is:
$data = Odt::join('hdt', 'odt.id', '=', 'hdt.odt_id')
->order_by('hdt.servicio')
->get(array('odt.odt as odt','hdt.servicio as servicio'));
Anything you can do with Fluent you can also do with Eloquent. If your goal is to retrieve hdts with their odts tho, I would recommend the inverse query for improved readability:
$data = Hdt::join('odt', 'odt.id', '=', 'hdt.odt_id')
->order_by('hdt.servicio')
->get(array('hdt.servicio as servicio', 'odt.odt as odt'));
Both of these do exactly the same.
To explain why this works:
Whenever you call static methods like Posts::where(...), Eloquent will return a Fluent query for you, exactly the same as DB::table('posts')->where(...). This gives you flexibility to build whichever queries you like. Here's an example:
// Retrieves last 10 posts by Johnny within Laravel category
$posts = Posts::join('authors', 'authors.id', '=', 'posts.author_id')
->join('categories', 'categories.id', '=', 'posts.category_id')
->where('authors.username', '=', 'johnny')
->where('categories.name', '=', 'laravel')
->order_by('posts.created_at', 'DESC')
->take(10)
->get('posts.*');