Adding PHP variable in JSON - php

I have this code to send whatsapp API
<?php
require_once('vendor/autoload.php');
$client = new \GuzzleHttp\Client();
$product="shadow";
$response = $client->request('POST', 'https://live-server-10100.wati.io/api/v1/sendTemplateMessage?whatsappNumber=96655642XXXXX',
[
'body' => '{"parameters":
[{"name":"name1","value":"hosam"},
{"name":"discount_code","value":"gh5"},
{"name":"shop_name","value":$product}],
"template_name":"aband_cart4",
"broadcast_name":"test01"}',
'headers' => [
'Authorization' => 'Bearer eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJqdGkiOiI0OTFmOGNkOS1mOWNOTM5Yy04MTEzMzhmMzc1ZjEiLCJ1bmlxdWVfbmFtZSI6ImFkbWluQGdoYW5hdHkuY29tIiwibmFtZWlkIjoiYWRtaW5AZ2hhbmF0eS5jb20iLCJlbWFpbCI6ImFkbWluQGdoYW5hdHkuY29tIiwiYXV0aF90aW1lIjoiMDIvMDUvMjAyMyAwNDo1NzozOCIsImRiX25hbWUiOiIxMDE3MDAiLCJodHRwOi8vc2NoZW1hcy5taWNyb3NvZnQuY29tL3dzLzIwMDgvMDYvaWRlbnRpdHkvY2xhaW1zL3JvbGUiOiJBRE1JTklTVFJBVE9SIiwiZXhwIjoyNTM0MDIzMDA4MDAsImlzcyI6IkNsYXJlX0FJIiwiYXVkIjoiQ2xhcmVfQUkifQ.3scVLBYDnzxPWlGQ_UfUgR_ecFQgnahQCnRQkAuzjoY',
'content-type' => 'text/json',
],
]);
echo $response->getBody();
?>
I tried to send post code with user value, and get error:
"{"result":false,"info":"Parameters is incorrect""
So what is the way to add PHP value $product to JSON?

Related

Using guzzle to post to Facebook Conversions API [duplicate]

Does anybody know the correct way to post JSON using Guzzle?
$request = $this->client->post(self::URL_REGISTER,array(
'content-type' => 'application/json'
),array(json_encode($_POST)));
I get an internal server error response from the server. It works using Chrome Postman.
For Guzzle 5, 6 and 7 you do it like this:
use GuzzleHttp\Client;
$client = new Client();
$response = $client->post('url', [
GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar'] // or 'json' => [...]
]);
Docs
The simple and basic way (guzzle6):
$client = new Client([
'headers' => [ 'Content-Type' => 'application/json' ]
]);
$response = $client->post('http://api.com/CheckItOutNow',
['body' => json_encode(
[
'hello' => 'World'
]
)]
);
To get the response status code and the content of the body I did this:
echo '<pre>' . var_export($response->getStatusCode(), true) . '</pre>';
echo '<pre>' . var_export($response->getBody()->getContents(), true) . '</pre>';
For Guzzle <= 4:
It's a raw post request so putting the JSON in the body solved the problem
$request = $this->client->post(
$url,
[
'content-type' => 'application/json'
],
);
$request->setBody($data); #set body!
$response = $request->send();
This worked for me (using Guzzle 6)
$client = new Client();
$result = $client->post('http://api.example.com', [
'json' => [
'value_1' => 'number1',
'Value_group' =>
array("value_2" => "number2",
"value_3" => "number3")
]
]);
echo($result->getBody()->getContents());
$client = new \GuzzleHttp\Client();
$body['grant_type'] = "client_credentials";
$body['client_id'] = $this->client_id;
$body['client_secret'] = $this->client_secret;
$res = $client->post($url, [ 'body' => json_encode($body) ]);
$code = $res->getStatusCode();
$result = $res->json();
You can either using hardcoded json attribute as key, or you can conveniently using GuzzleHttp\RequestOptions::JSON constant.
Here is the example of using hardcoded json string.
use GuzzleHttp\Client;
$client = new Client();
$response = $client->post('url', [
'json' => ['foo' => 'bar']
]);
See Docs.
$client = new \GuzzleHttp\Client(['base_uri' => 'http://example.com/api']);
$response = $client->post('/save', [
'json' => [
'name' => 'John Doe'
]
]);
return $response->getBody();
This works for me with Guzzle 6.2 :
$gClient = new \GuzzleHttp\Client(['base_uri' => 'www.foo.bar']);
$res = $gClient->post('ws/endpoint',
array(
'headers'=>array('Content-Type'=>'application/json'),
'json'=>array('someData'=>'xxxxx','moreData'=>'zzzzzzz')
)
);
According to the documentation guzzle do the json_encode
Solution for $client->request('POST',...
For those who are using $client->request this is how you create a JSON request:
$client = new Client();
$res = $client->request('POST', "https://some-url.com/api", [
'json' => [
'paramaterName' => "parameterValue",
'paramaterName2' => "parameterValue2",
]
'headers' => [
'Content-Type' => 'application/json',
]
]);
Guzzle JSON Request Reference
Php Version: 5.6
Symfony version: 2.3
Guzzle: 5.0
I had an experience recently about sending json with Guzzle. I use Symfony 2.3 so my guzzle version can be a little older.
I will also show how to use debug mode and you can see the request before sending it,
When i made the request as shown below got the successfull response;
use GuzzleHttp\Client;
$headers = [
'Authorization' => 'Bearer ' . $token,
'Accept' => 'application/json',
"Content-Type" => "application/json"
];
$body = json_encode($requestBody);
$client = new Client();
$client->setDefaultOption('headers', $headers);
$client->setDefaultOption('verify', false);
$client->setDefaultOption('debug', true);
$response = $client->post($endPoint, array('body'=> $body));
dump($response->getBody()->getContents());
#user3379466 is correct, but here I rewrite in full:
-package that you need:
"require": {
"php" : ">=5.3.9",
"guzzlehttp/guzzle": "^3.8"
},
-php code (Digest is a type so pick different type if you need to, i have to include api server for authentication in this paragraph, some does not need to authenticate. If you use json you will need to replace any text 'xml' with 'json' and the data below should be a json string too):
$client = new Client('https://api.yourbaseapiserver.com/incidents.xml', array('version' => 'v1.3', 'request.options' => array('headers' => array('Accept' => 'application/vnd.yourbaseapiserver.v1.1+xml', 'Content-Type' => 'text/xml'), 'auth' => array('username#gmail.com', 'password', 'Digest'),)));
$url = "https://api.yourbaseapiserver.com/incidents.xml";
$data = '<incident>
<name>Incident Title2a</name>
<priority>Medium</priority>
<requester><email>dsss#mail.ca</email></requester>
<description>description2a</description>
</incident>';
$request = $client->post($url, array('content-type' => 'application/xml',));
$request->setBody($data); #set body! this is body of request object and not a body field in the header section so don't be confused.
$response = $request->send(); #you must do send() method!
echo $response->getBody(); #you should see the response body from the server on success
die;
--- Solution for * Guzzle 6 * ---
-package that you need:
"require": {
"php" : ">=5.5.0",
"guzzlehttp/guzzle": "~6.0"
},
$client = new Client([
// Base URI is used with relative requests
'base_uri' => 'https://api.compay.com/',
// You can set any number of default request options.
'timeout' => 3.0,
'auth' => array('you#gmail.ca', 'dsfddfdfpassword', 'Digest'),
'headers' => array('Accept' => 'application/vnd.comay.v1.1+xml',
'Content-Type' => 'text/xml'),
]);
$url = "https://api.compay.com/cases.xml";
$data string variable is defined same as above.
// Provide the body as a string.
$r = $client->request('POST', $url, [
'body' => $data
]);
echo $r->getBody();
die;
Simply use this it will work
$auth = base64_encode('user:'.config('mailchimp.api_key'));
//API URL
$urll = "https://".config('mailchimp.data_center').".api.mailchimp.com/3.0/batches";
//API authentication Header
$headers = array(
'Accept' => 'application/json',
'Authorization' => 'Basic '.$auth
);
$client = new Client();
$req_Memeber = new Request('POST', $urll, $headers, $userlist);
// promise
$promise = $client->sendAsync($req_Memeber)->then(function ($res){
echo "Synched";
});
$promise->wait();
I use the following code that works very reliably.
The JSON data is passed in the parameter $request, and the specific request type passed in the variable $searchType.
The code includes a trap to detect and report an unsuccessful or invalid call which will then return false.
If the call is sucessful then json_decode ($result->getBody(), $return=true) returns an array of the results.
public function callAPI($request, $searchType) {
$guzzleClient = new GuzzleHttp\Client(["base_uri" => "https://example.com"]);
try {
$result = $guzzleClient->post( $searchType, ["json" => $request]);
} catch (Exception $e) {
$error = $e->getMessage();
$error .= '<pre>'.print_r($request, $return=true).'</pre>';
$error .= 'No returnable data';
Event::logError(__LINE__, __FILE__, $error);
return false;
}
return json_decode($result->getBody(), $return=true);
}
The answer from #user3379466 can be made to work by setting $data as follows:
$data = "{'some_key' : 'some_value'}";
What our project needed was to insert a variable into an array inside the json string, which I did as follows (in case this helps anyone):
$data = "{\"collection\" : [$existing_variable]}";
So with $existing_variable being, say, 90210, you get:
echo $data;
//{"collection" : [90210]}
Also worth noting is that you might want to also set the 'Accept' => 'application/json' as well in case the endpoint you're hitting cares about that kind of thing.
Above answers did not worked for me somehow. But this works fine for me.
$client = new Client('' . $appUrl['scheme'] . '://' . $appUrl['host'] . '' . $appUrl['path']);
$request = $client->post($base_url, array('content-type' => 'application/json'), json_encode($appUrl['query']));

Retrieve POST data sent with Guzzle (6.3) from Laravel

I am posting some data from my laravel app to another plain PHP page I have on my local server. The status code returned by Guzzle says it was successful but I am unable to access it. How can I do this?
I've tried using the Post method to retrieve value but no luck
Guzzle Function:
$client = new Client();
$response = $client->request('POST', 'http://localhost/testApp/guzTest.php',
[
'form_params' => [
'amnt' => 75
],
'allow_redirects' => true
]);
echo $response->getStatusCode();
Page Receiving POST DATA:
<?php
if (!empty($_POST['amnt'])) {
echo $_POST['amnt'];
}else
echo 'not found';
?>
I expect to be able to access the amount posted via post method but nothing is yielded.
Try somthing like that .
$client = new Client();
$response = $client->request('POST', 'http://localhost/testApp/guzTest.php',
[
'form_params' => [
'amnt' => 75
],
'allow_redirects' => true
]);
$contents = $response->getBody()->getContents();
$contents = json_decode($contents,true);
return ($contents);
On page Receiving POST DATA:
Response should be like this
return response()->json([
'status' => 'SUCCESS',
'code' => '200',
], 200);

Microsoft Graph API - Uploaded file can not be opened

I am trying to upload a file using the Microsoft Graph API. It seems to upload OK, but when trying to open the file I am told that it can not be opened.
Here's the relavent part of my PHP code. I've using Guzzle to make the requests.
$data = file_get_contents($_FILES['foo']['tmp_name']);
$guzzle = new GuzzleHttp\Client();
$sent_options = [
'headers' => [
'Authorization' => 'Bearer ' . $accessToken,
'Content-Type' => 'text/plain'
],
'form_params' => [
base64_encode($data)
]
];
$guzzle->put($url, $sent_options);
OK, so I've worked it out... for anyone else with the same problem, here's the solution.
$data = file_get_contents($_FILES['foo']['tmp_name']);
$guzzle = new GuzzleHttp\Client();
$sent_options = [
'headers' => [
'Authorization' => 'Bearer ' . $accessToken,
'Content-Type' => 'text/plain'
],
'body' => $data
];
$guzzle->put($url, $sent_options);

Can you include raw JSON in Guzzle POST Body?

This should be soo simple but I have spent hours searching for the answer and am truly stuck. I am building a basic Laravel application and am using Guzzle to replace the CURL request I am making at the moment. All the CURL functions utilise raw JSON variables in the body.
I am trying to create a working Guzzle client but the server is respsonding with 'invalid request' and I am just wondering if something fishy is going on with the JSON I am posting. I am starting to wonder if you can not use raw JSON in the Guzzle POST request body? I know the headers are working as I am receiving a valid response from the server and I know the JSON is valid as it is currently working in a CURL request. So I am stuck :-(
Any help would be sooo greatly appreciated.
$headers = array(
'NETOAPI_KEY' => env('NETO_API_KEY'),
'Content-Type' => 'application/json',
'Accept' => 'application/json',
'NETOAPI_ACTION' => 'GetOrder'
);
// JSON Data for API post
$GetOrder = '{
"Filter": {
"OrderID": "N10139",
"OutputSelector": [
"OrderStatus"
]
}
}';
$client = new client();
$res = $client->post(env('NETO_API_URL'), [ 'headers' => $headers ], [ 'body' => $GetOrder ]);
return $res->getBody();
You can send a regular array as JSON via the 'json' request option; this will also automatically set the right headers:
$headers = [
'NETOAPI_KEY' => env('NETO_API_KEY'),
'Accept' => 'application/json',
'NETOAPI_ACTION' => 'GetOrder'
];
$GetOrder = [
'Filter' => [
'OrderID' => 'N10139',
'OutputSelector' => ['OrderStatus'],
],
];
$client = new client();
$res = $client->post(env('NETO_API_URL'), [
'headers' => $headers,
'json' => $GetOrder,
]);
Note that Guzzle applies json_encode() without any options behind the scenes; if you need any customisation, you're advised to do some of the work yourself
$res = $client->post(env('NETO_API_URL'), [
'headers' => $headers + ['Content-Type' => 'application/json'],
'body' => json_encode($getOrders, ...),
]);
Guzzle 7 Here
The below worked for me with raw json input
$data = array(
'customer' => '89090',
'username' => 'app',
'password' => 'pwd'
);
$url = "http://someendpoint/API/Login";
$client = new \GuzzleHttp\Client();
$response = $client->post($url, [
'headers' => ['Content-Type' => 'application/json', 'Accept' => 'application/json'],
'body' => json_encode($data)
]);
print_r(json_decode($response->getBody(), true));
For some reasons until I used the json_decode on the response, the output wasn't formatted.
You probably need to set the body mime type. This can be done easily using the setBody() method.
$request = $client->post(env('NETO_API_URL'), ['headers' => $headers]);
$request->setBody($GetOrder, 'application/json');

How can I use Guzzle to send a POST request in JSON?

Does anybody know the correct way to post JSON using Guzzle?
$request = $this->client->post(self::URL_REGISTER,array(
'content-type' => 'application/json'
),array(json_encode($_POST)));
I get an internal server error response from the server. It works using Chrome Postman.
For Guzzle 5, 6 and 7 you do it like this:
use GuzzleHttp\Client;
$client = new Client();
$response = $client->post('url', [
GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar'] // or 'json' => [...]
]);
Docs
The simple and basic way (guzzle6):
$client = new Client([
'headers' => [ 'Content-Type' => 'application/json' ]
]);
$response = $client->post('http://api.com/CheckItOutNow',
['body' => json_encode(
[
'hello' => 'World'
]
)]
);
To get the response status code and the content of the body I did this:
echo '<pre>' . var_export($response->getStatusCode(), true) . '</pre>';
echo '<pre>' . var_export($response->getBody()->getContents(), true) . '</pre>';
For Guzzle <= 4:
It's a raw post request so putting the JSON in the body solved the problem
$request = $this->client->post(
$url,
[
'content-type' => 'application/json'
],
);
$request->setBody($data); #set body!
$response = $request->send();
This worked for me (using Guzzle 6)
$client = new Client();
$result = $client->post('http://api.example.com', [
'json' => [
'value_1' => 'number1',
'Value_group' =>
array("value_2" => "number2",
"value_3" => "number3")
]
]);
echo($result->getBody()->getContents());
$client = new \GuzzleHttp\Client();
$body['grant_type'] = "client_credentials";
$body['client_id'] = $this->client_id;
$body['client_secret'] = $this->client_secret;
$res = $client->post($url, [ 'body' => json_encode($body) ]);
$code = $res->getStatusCode();
$result = $res->json();
You can either using hardcoded json attribute as key, or you can conveniently using GuzzleHttp\RequestOptions::JSON constant.
Here is the example of using hardcoded json string.
use GuzzleHttp\Client;
$client = new Client();
$response = $client->post('url', [
'json' => ['foo' => 'bar']
]);
See Docs.
$client = new \GuzzleHttp\Client(['base_uri' => 'http://example.com/api']);
$response = $client->post('/save', [
'json' => [
'name' => 'John Doe'
]
]);
return $response->getBody();
This works for me with Guzzle 6.2 :
$gClient = new \GuzzleHttp\Client(['base_uri' => 'www.foo.bar']);
$res = $gClient->post('ws/endpoint',
array(
'headers'=>array('Content-Type'=>'application/json'),
'json'=>array('someData'=>'xxxxx','moreData'=>'zzzzzzz')
)
);
According to the documentation guzzle do the json_encode
Solution for $client->request('POST',...
For those who are using $client->request this is how you create a JSON request:
$client = new Client();
$res = $client->request('POST', "https://some-url.com/api", [
'json' => [
'paramaterName' => "parameterValue",
'paramaterName2' => "parameterValue2",
]
'headers' => [
'Content-Type' => 'application/json',
]
]);
Guzzle JSON Request Reference
Php Version: 5.6
Symfony version: 2.3
Guzzle: 5.0
I had an experience recently about sending json with Guzzle. I use Symfony 2.3 so my guzzle version can be a little older.
I will also show how to use debug mode and you can see the request before sending it,
When i made the request as shown below got the successfull response;
use GuzzleHttp\Client;
$headers = [
'Authorization' => 'Bearer ' . $token,
'Accept' => 'application/json',
"Content-Type" => "application/json"
];
$body = json_encode($requestBody);
$client = new Client();
$client->setDefaultOption('headers', $headers);
$client->setDefaultOption('verify', false);
$client->setDefaultOption('debug', true);
$response = $client->post($endPoint, array('body'=> $body));
dump($response->getBody()->getContents());
#user3379466 is correct, but here I rewrite in full:
-package that you need:
"require": {
"php" : ">=5.3.9",
"guzzlehttp/guzzle": "^3.8"
},
-php code (Digest is a type so pick different type if you need to, i have to include api server for authentication in this paragraph, some does not need to authenticate. If you use json you will need to replace any text 'xml' with 'json' and the data below should be a json string too):
$client = new Client('https://api.yourbaseapiserver.com/incidents.xml', array('version' => 'v1.3', 'request.options' => array('headers' => array('Accept' => 'application/vnd.yourbaseapiserver.v1.1+xml', 'Content-Type' => 'text/xml'), 'auth' => array('username#gmail.com', 'password', 'Digest'),)));
$url = "https://api.yourbaseapiserver.com/incidents.xml";
$data = '<incident>
<name>Incident Title2a</name>
<priority>Medium</priority>
<requester><email>dsss#mail.ca</email></requester>
<description>description2a</description>
</incident>';
$request = $client->post($url, array('content-type' => 'application/xml',));
$request->setBody($data); #set body! this is body of request object and not a body field in the header section so don't be confused.
$response = $request->send(); #you must do send() method!
echo $response->getBody(); #you should see the response body from the server on success
die;
--- Solution for * Guzzle 6 * ---
-package that you need:
"require": {
"php" : ">=5.5.0",
"guzzlehttp/guzzle": "~6.0"
},
$client = new Client([
// Base URI is used with relative requests
'base_uri' => 'https://api.compay.com/',
// You can set any number of default request options.
'timeout' => 3.0,
'auth' => array('you#gmail.ca', 'dsfddfdfpassword', 'Digest'),
'headers' => array('Accept' => 'application/vnd.comay.v1.1+xml',
'Content-Type' => 'text/xml'),
]);
$url = "https://api.compay.com/cases.xml";
$data string variable is defined same as above.
// Provide the body as a string.
$r = $client->request('POST', $url, [
'body' => $data
]);
echo $r->getBody();
die;
Simply use this it will work
$auth = base64_encode('user:'.config('mailchimp.api_key'));
//API URL
$urll = "https://".config('mailchimp.data_center').".api.mailchimp.com/3.0/batches";
//API authentication Header
$headers = array(
'Accept' => 'application/json',
'Authorization' => 'Basic '.$auth
);
$client = new Client();
$req_Memeber = new Request('POST', $urll, $headers, $userlist);
// promise
$promise = $client->sendAsync($req_Memeber)->then(function ($res){
echo "Synched";
});
$promise->wait();
I use the following code that works very reliably.
The JSON data is passed in the parameter $request, and the specific request type passed in the variable $searchType.
The code includes a trap to detect and report an unsuccessful or invalid call which will then return false.
If the call is sucessful then json_decode ($result->getBody(), $return=true) returns an array of the results.
public function callAPI($request, $searchType) {
$guzzleClient = new GuzzleHttp\Client(["base_uri" => "https://example.com"]);
try {
$result = $guzzleClient->post( $searchType, ["json" => $request]);
} catch (Exception $e) {
$error = $e->getMessage();
$error .= '<pre>'.print_r($request, $return=true).'</pre>';
$error .= 'No returnable data';
Event::logError(__LINE__, __FILE__, $error);
return false;
}
return json_decode($result->getBody(), $return=true);
}
The answer from #user3379466 can be made to work by setting $data as follows:
$data = "{'some_key' : 'some_value'}";
What our project needed was to insert a variable into an array inside the json string, which I did as follows (in case this helps anyone):
$data = "{\"collection\" : [$existing_variable]}";
So with $existing_variable being, say, 90210, you get:
echo $data;
//{"collection" : [90210]}
Also worth noting is that you might want to also set the 'Accept' => 'application/json' as well in case the endpoint you're hitting cares about that kind of thing.
Above answers did not worked for me somehow. But this works fine for me.
$client = new Client('' . $appUrl['scheme'] . '://' . $appUrl['host'] . '' . $appUrl['path']);
$request = $client->post($base_url, array('content-type' => 'application/json'), json_encode($appUrl['query']));

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