How to return TRUE when an account was created more than 30 days ago?
I have the following date:
$udata['joined']; - record date in time():
I tried like this
If($udata['joined'] = strtotime ("+30 days", time())){
return true;
}
Any idea why it's not working correctly?
Return empty.
I guess you want
If timestamp is smaller than (or exactly) 30 days ago
if ($udata['joined'] <= strtotime("-30 days", time()) {
return TRUE;
}
(you need to substract 30 days from now and remove all syntax errors)
You are assigning a value instead of using an operator, i.e. you are using = instead of ==. Try this:
If($udata['joined'] == strtotime ("+30 days", time())){
return true;
}
Edit
As others pointed out, checking for equality will most likely always return false anyway, because you'd be very luck to hit the exact same timestamp!
What you are looking for is the <= (less than or equal) operator to check if $udata['joined'] is a timestamp before 30 days ago. In other words :
// true if the provided date is before 30 days ago
return strtotime($udata['joined']) < strtotime("-30 days", time());
Related
I have following
$var = "2010-01-21 00:00:00.0"
I'd like to compare this date against today's date (i.e. I'd like to know if this $var is before today or equals today or not)
What function would I need to use?
strtotime($var);
Turns it into a time value
time() - strtotime($var);
Gives you the seconds since $var
if((time()-(60*60*24)) < strtotime($var))
Will check if $var has been within the last day.
That format is perfectly appropriate for a standard string comparison e.g.
if ($date1 > $date2){
//Action
}
To get today's date in that format, simply use: date("Y-m-d H:i:s").
So:
$today = date("Y-m-d H:i:s");
$date = "2010-01-21 00:00:00";
if ($date < $today) {}
That's the beauty of that format: it orders nicely. Of course, that may be less efficient, depending on your exact circumstances, but it might also be a whole lot more convenient and lead to more maintainable code - we'd need to know more to truly make that judgement call.
For the correct timezone, you can use, for example,
date_default_timezone_set('America/New_York');
Click here to refer to the available PHP Timezones.
Here you go:
function isToday($time) // midnight second
{
return (strtotime($time) === strtotime('today'));
}
isToday('2010-01-22 00:00:00.0'); // true
Also, some more helper functions:
function isPast($time)
{
return (strtotime($time) < time());
}
function isFuture($time)
{
return (strtotime($time) > time());
}
You can use the DateTime class:
$past = new DateTime("2010-01-01 00:00:00");
$now = new DateTime();
$future = new DateTime("2021-01-01 00:00:00");
Comparison operators work*:
var_dump($past < $now); // bool(true)
var_dump($future < $now); // bool(false)
var_dump($now == $past); // bool(false)
var_dump($now == new DateTime()); // bool(true)
var_dump($now == $future); // bool(false)
var_dump($past > $now); // bool(false)
var_dump($future > $now); // bool(true)
It is also possible to grab the timestamp values from DateTime objects and compare them:
var_dump($past ->getTimestamp()); // int(1262286000)
var_dump($now ->getTimestamp()); // int(1431686228)
var_dump($future->getTimestamp()); // int(1577818800)
var_dump($past ->getTimestamp() < $now->getTimestamp()); // bool(true)
var_dump($future->getTimestamp() > $now->getTimestamp()); // bool(true)
* Note that === returns false when comparing two different DateTime objects even when they represent the same date.
To complete BoBby Jack, the use of DateTime OBject, if you have php 5.2.2+ :
if(new DateTime() > new DateTime($var)){
// $var is before today so use it
}
$toBeComparedDate = '2014-08-12';
$today = (new DateTime())->format('Y-m-d'); //use format whatever you are using
$expiry = (new DateTime($toBeComparedDate))->format('Y-m-d');
var_dump(strtotime($today) > strtotime($expiry)); //false or true
One caution based on my experience, if your purpose only involves date then be careful to include the timestamp. For example, say today is "2016-11-09". Comparison involving timestamp will nullify the logic here. Example,
// input
$var = "2016-11-09 00:00:00.0";
// check if date is today or in the future
if ( time() <= strtotime($var) )
{
// This seems right, but if it's ONLY date you are after
// then the code might treat $var as past depending on
// the time.
}
The code above seems right, but if it's ONLY the date you want to compare, then, the above code is not the right logic. Why? Because, time() and strtotime() will provide include timestamp. That is, even though both dates fall on the same day, but difference in time will matter. Consider the example below:
// plain date string
$input = "2016-11-09";
Because the input is plain date string, using strtotime() on $input will assume that it's the midnight of 2016-11-09. So, running time() anytime after midnight will always treat $input as past, even though they are on the same day.
To fix this, you can simply code, like this:
if (date("Y-m-d") <= $input)
{
echo "Input date is equal to or greater than today.";
}
Few years later, I second Bobby Jack's observation that last 24 hrs is not today!!! And I am surprised that the answer was so much upvoted...
To compare if a certain date is less, equal or greater than another, first you need to turn them "down" to beginning of the day. In other words, make sure that you're talking about same 00:00:00 time in both dates.
This can be simply and elegantly done as:
strtotime("today") <=> strtotime($var)
if $var has the time part on 00:00:00 like the OP specified.
Replace <=> with whatever you need (or keep it like this in php 7)
Also, obviously, we're talking about same timezone for both.
For list of supported TimeZones
$date1=date_create("2014-07-02");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
(the w3schools example, it works perfect)
Expanding on Josua's answer from w3schools:
//create objects for the dates to compare
$date1=date_create($someDate);
$date2=date_create(date("Y-m-d"));
$diff=date_diff($date1,$date2);
//now convert the $diff object to type integer
$intDiff = $diff->format("%R%a");
$intDiff = intval($intDiff);
//now compare the two dates
if ($intDiff > 0) {echo '$date1 is in the past';}
else {echo 'date1 is today or in the future';}
I hope this helps. My first post on stackoverflow!
Some given answers don't have in consideration the current day!
Here it is my proposal.
$var = "2010-01-21 00:00:00.0"
$given_date = new \DateTime($var);
if ($given_date == new \DateTime('today')) {
//today
}
if ($given_date < new \DateTime('today')) {
//past
}
if ($given_date > new \DateTime('today')) {
//future
}
Compare date time objects:
(I picked 10 days - Anything older than 10 days is "OLD", else "NEW")
$now = new DateTime();
$yourdate = new DateTime("2021-08-24");
$diff=date_diff($yourdate,$now);
$diff_days = $diff->format("%a");
if($diff_days > 10){
echo "OLD! " . $yourdate->format('m/d/Y');
}else{
echo "NEW! " . $yourdate->format('m/d/Y');
}
If you do things with time and dates Carbon is you best friend;
Install the package then:
$theDay = Carbon::make("2010-01-21 00:00:00.0");
$theDay->isToday();
$theDay->isPast();
$theDay->isFuture();
if($theDay->lt(Carbon::today()) || $theDay->gt(Carbon::today()))
lt = less than,
gt = greater than
As in the question:
$theDay->gt(Carbon::today()) ? true : false;
and much more;
Try this:
if (date("Y-m-d",strtotime($funding_dt)) >= date("Y-m-d",strtotime('31-01-2007')))
{
echo "ok";
} else {
echo "not";
}
this code keeps telling me that $lasUpdate is always greater than $yesterday no matter the change i make to $yesterday result is (12/31/14 is greater than 01/19/15 no update needed). i feel like i'm missing something simple thank you in advance it is greatly appreciated.
$result['MAX(Date)']='12/31/14';
$lastUpdate = date('m/d/y', strtotime($result['MAX(Date)']));
$yesterday = date('m/d/y', strtotime('-1 day'));
if($lastUpdate<$yesterday){echo $lastUpdate.'is less '.$yesterday.'<br>'.'update needed';}
if($lastUpdate>=$yesterday){echo $lastUpdate.'is greater than '.$yesterday.'<br>'.'no update needed';
You have fallen victim to PHP type juggling with strings. A date function has a return value of a string. You cannot compare dates in their string format since PHP will juggle strings into integers in the context of a comparison. The only exception is if the string is a valid number. In essence, you are doing:
if ('12/31/14' < '01/19/15') { ... }
if ('12/31/14' >= '01/19/15') { ... }
Which PHP type juggles to:
if (12 < 1) { ... }
if (12 >= 1) { ... }
And returns false on the first instance, and true on the second instance.
Your solution is to not wrap date around the strtotime functions, and just use the returned timestamps from the strtotime functions themselves to compare UNIX timestamps directly:
$lastUpdate = strtotime($result['MAX(Date)']);
$yesterday = strtotime('-1 day');
You will however want to use date when you do the echo back to the user so they have a meaningful date string to work with.
Try something like this:
$lastUpdate = strtotime($result['MAX(Date)']);
$yesterday = strtotime('-1 day');
if ($lastUpdate < $yesterday) { /* do Something */ }
12/31/14 is greater than 01/19/15
Because 1 is greater than 0. If you want to compare dates that way you will need to store them in a different format (from most to least significant digit), for example Ymd.
Or store the timestamps you are making in the different variables and compare them.
i am struggling for a long time to set a specific date but i am not getting correct out put.
i want to get date from user and compare that date with the date 15 days older then today. if it is older than 15 days then convert to today else print what it is.
$todaydate= $_GET['date'];// getting date as 201013 ddmmyy submitted by user
$todaydate=preg_replace("/[^0-9,.]/", "", $todaydate);
$today =date("dmy"); //today ddmmyy
$older= date("dmy",strtotime("-15 day")); // before 15 days 051013
if ($todaydate <= $older){
$todaydate= $today;}
problem is, it is taking date as number and giving wrong result.
Comparing date strings is a bit hacky and prone to failure. Try comparing actual date objects
$userDate = DateTime::createFromFormat('dmy', $_GET['date']);
if ($userDate === false) {
throw new InvalidArgumentException('Invalid date string');
}
$cmp = new DateTime('15 days ago');
if ($userDate <= $cmp) {
$userDate = new DateTime();
}
Also, strtotime has some severe limitations (see http://php.net/manual/function.strtotime.php#refsect1-function.strtotime-notesand) and is not useful in non-US locales. The DateTime class is much more flexible and up-to-date.
try this one:
<?php
$todaydate = date(d-m-Y,strtotime($_GET['date']));
$today = date("d-m-Y");
$older= date("d-m-Y",strtotime("-15 day"));
if (strtotime($todaydate) <= strtotime($older))
{
$todaydate= $today;
}
?>
$previousDate = "2012-09-30";
if (strtotime($previousDate) <= strtotime("-15 days")) {
//the date in $previousDate is earlier or is equal to the date 15 days before from today
}
I need to check a date in PHP if it is bigger than the 00:00 hours of the next day.
At the first sight I tried to use
if($date_variable<strtotime('+1day')){
return true;
}else{
return false
}
But what it's doing is in fact adding to time() (24*60*60)
Is there any solution to that?
P.S.: Im trying to avoid the use of date on +1day and backwards to UNIX without hours info
You can use:
if($date_variable<strtotime('midnight tomorrow')){
return true;
}else{
return false
}
Okay the accepted answer is now over three years old and since we got PHP5 and even now PHP7 we can do it much easier with the DateTime class. The DateTime class is a native PHP class. No further library is in need.
$oDateNow = new DateTime(); // Date now
$oDateTomorrow = new DateTime('tomorrow midnight'); // Date tomorrow midnight
$bResult = $oDateNow < $oDateTomorrow ? true : false;
The DateTime class accepts all parameters the strtotime() function also accepts.
You can try using mktime() like this :
if($date_variable<mktime(0,0,0, date('m'), date('d')+1, date('Y')){
return true;
}else{
return false
}
I have following
$var = "2010-01-21 00:00:00.0"
I'd like to compare this date against today's date (i.e. I'd like to know if this $var is before today or equals today or not)
What function would I need to use?
strtotime($var);
Turns it into a time value
time() - strtotime($var);
Gives you the seconds since $var
if((time()-(60*60*24)) < strtotime($var))
Will check if $var has been within the last day.
That format is perfectly appropriate for a standard string comparison e.g.
if ($date1 > $date2){
//Action
}
To get today's date in that format, simply use: date("Y-m-d H:i:s").
So:
$today = date("Y-m-d H:i:s");
$date = "2010-01-21 00:00:00";
if ($date < $today) {}
That's the beauty of that format: it orders nicely. Of course, that may be less efficient, depending on your exact circumstances, but it might also be a whole lot more convenient and lead to more maintainable code - we'd need to know more to truly make that judgement call.
For the correct timezone, you can use, for example,
date_default_timezone_set('America/New_York');
Click here to refer to the available PHP Timezones.
Here you go:
function isToday($time) // midnight second
{
return (strtotime($time) === strtotime('today'));
}
isToday('2010-01-22 00:00:00.0'); // true
Also, some more helper functions:
function isPast($time)
{
return (strtotime($time) < time());
}
function isFuture($time)
{
return (strtotime($time) > time());
}
You can use the DateTime class:
$past = new DateTime("2010-01-01 00:00:00");
$now = new DateTime();
$future = new DateTime("2021-01-01 00:00:00");
Comparison operators work*:
var_dump($past < $now); // bool(true)
var_dump($future < $now); // bool(false)
var_dump($now == $past); // bool(false)
var_dump($now == new DateTime()); // bool(true)
var_dump($now == $future); // bool(false)
var_dump($past > $now); // bool(false)
var_dump($future > $now); // bool(true)
It is also possible to grab the timestamp values from DateTime objects and compare them:
var_dump($past ->getTimestamp()); // int(1262286000)
var_dump($now ->getTimestamp()); // int(1431686228)
var_dump($future->getTimestamp()); // int(1577818800)
var_dump($past ->getTimestamp() < $now->getTimestamp()); // bool(true)
var_dump($future->getTimestamp() > $now->getTimestamp()); // bool(true)
* Note that === returns false when comparing two different DateTime objects even when they represent the same date.
To complete BoBby Jack, the use of DateTime OBject, if you have php 5.2.2+ :
if(new DateTime() > new DateTime($var)){
// $var is before today so use it
}
$toBeComparedDate = '2014-08-12';
$today = (new DateTime())->format('Y-m-d'); //use format whatever you are using
$expiry = (new DateTime($toBeComparedDate))->format('Y-m-d');
var_dump(strtotime($today) > strtotime($expiry)); //false or true
One caution based on my experience, if your purpose only involves date then be careful to include the timestamp. For example, say today is "2016-11-09". Comparison involving timestamp will nullify the logic here. Example,
// input
$var = "2016-11-09 00:00:00.0";
// check if date is today or in the future
if ( time() <= strtotime($var) )
{
// This seems right, but if it's ONLY date you are after
// then the code might treat $var as past depending on
// the time.
}
The code above seems right, but if it's ONLY the date you want to compare, then, the above code is not the right logic. Why? Because, time() and strtotime() will provide include timestamp. That is, even though both dates fall on the same day, but difference in time will matter. Consider the example below:
// plain date string
$input = "2016-11-09";
Because the input is plain date string, using strtotime() on $input will assume that it's the midnight of 2016-11-09. So, running time() anytime after midnight will always treat $input as past, even though they are on the same day.
To fix this, you can simply code, like this:
if (date("Y-m-d") <= $input)
{
echo "Input date is equal to or greater than today.";
}
Few years later, I second Bobby Jack's observation that last 24 hrs is not today!!! And I am surprised that the answer was so much upvoted...
To compare if a certain date is less, equal or greater than another, first you need to turn them "down" to beginning of the day. In other words, make sure that you're talking about same 00:00:00 time in both dates.
This can be simply and elegantly done as:
strtotime("today") <=> strtotime($var)
if $var has the time part on 00:00:00 like the OP specified.
Replace <=> with whatever you need (or keep it like this in php 7)
Also, obviously, we're talking about same timezone for both.
For list of supported TimeZones
$date1=date_create("2014-07-02");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
(the w3schools example, it works perfect)
Expanding on Josua's answer from w3schools:
//create objects for the dates to compare
$date1=date_create($someDate);
$date2=date_create(date("Y-m-d"));
$diff=date_diff($date1,$date2);
//now convert the $diff object to type integer
$intDiff = $diff->format("%R%a");
$intDiff = intval($intDiff);
//now compare the two dates
if ($intDiff > 0) {echo '$date1 is in the past';}
else {echo 'date1 is today or in the future';}
I hope this helps. My first post on stackoverflow!
Some given answers don't have in consideration the current day!
Here it is my proposal.
$var = "2010-01-21 00:00:00.0"
$given_date = new \DateTime($var);
if ($given_date == new \DateTime('today')) {
//today
}
if ($given_date < new \DateTime('today')) {
//past
}
if ($given_date > new \DateTime('today')) {
//future
}
Compare date time objects:
(I picked 10 days - Anything older than 10 days is "OLD", else "NEW")
$now = new DateTime();
$yourdate = new DateTime("2021-08-24");
$diff=date_diff($yourdate,$now);
$diff_days = $diff->format("%a");
if($diff_days > 10){
echo "OLD! " . $yourdate->format('m/d/Y');
}else{
echo "NEW! " . $yourdate->format('m/d/Y');
}
If you do things with time and dates Carbon is you best friend;
Install the package then:
$theDay = Carbon::make("2010-01-21 00:00:00.0");
$theDay->isToday();
$theDay->isPast();
$theDay->isFuture();
if($theDay->lt(Carbon::today()) || $theDay->gt(Carbon::today()))
lt = less than,
gt = greater than
As in the question:
$theDay->gt(Carbon::today()) ? true : false;
and much more;
Try this:
if (date("Y-m-d",strtotime($funding_dt)) >= date("Y-m-d",strtotime('31-01-2007')))
{
echo "ok";
} else {
echo "not";
}