My current code in PHP:
$str = "https://app.abc.com/mlk//mlk/List_xyz?loginname=0&project=0&company=a&phase=0&type=0&kind=need_to_check"
$output = implode(',', array_unique(explode(',', $str)));
print $output
But it results in the wrong output.
My desired output is "https://app.abc.com/mlk/List_xyz?loginname=0&project=0&company=a&phase=0&type=0&kind=need_to_check"
How can I remove the duplicated text, for example /mlk/ in my above string?
Note: The duplicate is not always /mlk/. Sometimes it is /example/ or similar.
For example, /a/b/b/a/c/b/ must become /a/b/c/
The first argument of the functions explode() is the character on which you will split the string. As there isn't any comma in your URL, your explode(',', $str) doesn't have any effect: it returns an array of one element, the full URL.
You need to explode the string on the character /.
Then, same behavior for implode():
$str = "https://app.abc.com//a/b/b/a/c/b//List_xyz?loginname=0&project=0&company=a&phase=0&type=0&kind=need_to_check";
$output = implode('/', array_unique(explode('/', $str)));
print $output;
Output:
https://app.abc.com/a/b/c/List_xyz?loginname=0&project=0&company=a&phase=0&type=0&kind=need_to_check
Related
I have below URL in my code and i want to split it and get the number from it
For example from the below URL need to fetch 123456
https://review-test.com/#/c/123456/
I have tried this and it is not working
$completeURL = https://review-test.com/#/c/123456/ ;
list($url, $number) = explode('#c', preg_replace('/^.*\/+/', '', $completeURL));
Use parse_url
It's specifically made for this sort of thing.
You can do this without using regex also -
$completeURL = 'https://review-test.com/#/c/123456/' ;
list($url, $number) = explode('#c', str_replace('/', '', $completeURL));
echo $number;
If you wan to get the /c/123456/ params you will need to execute the following:
$url = 'https://review-test.com/#/c/123456/';
$url_fragment = parse_url($url, PHP_URL_FRAGMENT);
$fragments = explode('/', $url_fragment);
$fragments = array_filter(array_map('trim', $fragments));
$fragments = array_values($fragments);
The PHP_URL_FRAGMENT will return a component of the url after #
After parse_url you will end up with a string like this: '/c/123456/'
The explode('/', $url_fragment); function will return an array with empty indexes where '/' was extracted
In order to remove empty indexes array_filter($fragments); the
array_map with trim option will remove excess spaces. It does not
apply in this case but in real case scenario you better trim.
Now if you var_dump the result you can see that the array needs to
be reindexed array_values($fragments)
You should try this: basename
basename — Returns trailing name component of path
<?php
echo basename("https://review-test.com/#/c/123456/");
?>
Demo : http://codepad.org/9Ah83qaP
Subsequently you can directly take from pure regex to fetch numbers from string,
preg_match('!\d+!', "https://review-test.com/#/c/123456/", $matches);
print_r($matches);
Working demo
Simply:
$tmp = explode( '/', $completeUrl).end();
It will explode the string by '/' and take the last element
If you have no other option than regex, for your example data you could use preg_match to split your url instead of preg_replace.
An approach could be to
Capture the first part as a group (.+\/)
Then capture your number as a group (\d+)
Followed by a forward slash at the end of the line \/$/
This will take the last number from the url followed by a forward slash.
Then you could use list and skip the first item of the $matches array because that will contain the text that matched the full pattern.
$completeURL = "https://review-test.com/#/c/123456/";
preg_match('/(.+\/)(\d+)\/$/', $completeURL, $matches);
list(, $url, $number) = $matches;
How can I remove all the content in a string after the LAST occurance of a slash character / ?
For example, the string is:
http://localhost/new-123-rugby/competition.php?croncode=12345678
I want to remove all the content after the last / so that it just shows:
http://localhost/new-123-rugby/
But the content after the / could be of a variable length.
Please note, there could be any number of slashes in the URL. It needs to be able to remove content after the last slash. There could be more than shown in the example above.
you can try this
$url = "http://localhost/new-123-rugby/competition.php?croncode=12345678";
preg_match("/[^\/]+$/", $url, $matches);
$newUrl = str_replace($matches[0],'',$url);
echo $newUrl;
Solution #1, using substr() + strrpos():
$string = 'http://localhost/new-123-rugby/competition.php?croncode=12345678';
$pos = strrpos($string, '/');
if ($pos !== FALSE) {
echo(substr($string, 0, $pos + 1));
}
Function strrpos() finds the position of the last occurrence of / in the string, substr() extracts the required substring.
Drawback: if $string does not contain '/', strrpos() returns FALSE and substr() does not return what we want. Need to check the value returned by strrpos() first.
Solution #2, using explode() + implode():
$string = 'http://localhost/new-123-rugby/competition.php?croncode=12345678';
$array = explode('/', $string);
if (count($array) > 1) {
array_pop($array); // ignore the returned value, we don't need it
echo(implode('/', $array).'/'); // join the pieces back, add the last '/'
}
Alternatively, instead of array_pop($array) we can make the last component empty and there is no need to add an extra '/' at the end:
$string = 'http://localhost/new-123-rugby/competition.php?croncode=12345678';
$array = explode('/', $string);
if (count($array) > 1) {
$array[count($array) - 1] = ''; // empty the last component
echo(implode('/', $array)); // join the pieces back
}
Drawback (for both versions): if $string does not contain '/', explode() produces an array containing a single value and the rest of the code produces either '/' (the first piece of code) or an empty string (the second). Need to check the number of items in the array produced by explode().
Solution #3, using preg_replace():
$string = 'http://localhost/new-123-rugby/competition.php?croncode=12345678';
echo(preg_replace('#/[^/]*$#', '/', $string));
Drawbacks: none. It works well when both when $string contains '/' and it does not contain '/' (it does not modify $string in this case).
NOTA:
The question was edited so that the original answer (below the edit), doesn't match the requirements from OP. It wasn't marked as an edit from OP.
EDIT:
Updated my answer so it now matches the requirements of OP:
(Now it works with as many slashes as you want)
Will also work using
http://localhost/new-123-rugby////////competition.php?croncode=12345678
<?php
$url = "http://localhost/new-123-rugby/competition.php?croncode=12345678";
echo dirname($url) . "/";
?>
Output:
http://localhost/new-123-rugby/
Original answer:
This should work for you:
<?php
$string = "http://localhost/new-123-rugby/competition.php?croncode=12345678";
echo $string = substr($string, 0, strpos(strrev($string), "/")-2);
?>
Output:
http://localhost/new-123-rugby/
Demo: http://ideone.com/0R9QUG
hi all i am trying to parse a big string and want to obtain only the value of id(id=dfsdfdsfdsfsaddfdfdfd) . My current code output extra data beyon the id value. could any one help me fix this problem.Thanks
preg_match_all("#live3.me.somesite.com([^<]+)\"#", $html, $foo);
print_r($foo[0]);
sample input string:
$html=".............."url":"rtmp:\/\/live3.me.somesite.com\/live\/?id=dfsdfdsfdsfsaddfdfdfd","name":"8.low.stream".........";
Is this an issue where you are set on using preg_match?
Or would something like 'parse_url' be acceptable?
http://php.net/manual/en/function.parse-url.php
Once parsed, getting specific query string parameters out should be easy
Just for the fun of answering an 8 month old question, here is my go at it :-)
We have got this to work with:
$html='".............."url":"rtmp:\/\/live3.me.somesite.com\/live\/?id=dfsdfdsfdsfsaddfdfdfd","name":"8.low.stream"........."';
That string sure looks a bit JSONish to me, so why not ...
// 1. Get rid of leading and trailing quotes and dots
$clean = trim($html, '"');
$clean = trim($clean, '.');
// 2. Add squiggly brackets to form a JSON string
$json = '{' . $clean . '}';
// 3. Decode the JSON into an array
$array = json_decode($json, true);
// 4. Parse URL value from the array and grab the query part
$query = parse_url($array['url'], PHP_URL_QUERY);
// 5. Get parameter values from the query
parse_str($query, $params);
// 6. Ta-da!
echo "Readable : ", $params['id'], PHP_EOL;
And of course ...
// The one-liner!
parse_str(parse_url(json_decode('{'.trim(trim($html,'"'),'.').'}', true)['url'], PHP_URL_QUERY), $params2);
echo "One-liner: ", $params2['id'], PHP_EOL;
Output:
Readable : dfsdfdsfdsfsaddfdfdfd
One-liner: dfsdfdsfdsfsaddfdfdfd
If I have a string such as this "Hello | I'm Ben" and I want to edit the second section, I can use PHP explode like this
$newstring = explode("|","Hello | I'm Ben");
Once that data has been edited to something new, for example:
$newstring[1] = "I'm john";
How can I implode the string to once again be "Hello | I'm John"?
PHP's implode function returns Hello I'm John however it does not put the delimiters back in.
So, is there a way to implode this string and put the | between the two exploded sections of the string?
From the documentation for implode():
string implode ( string $glue , array $pieces )
Where:
glue - Defaults to an empty string.
pieces - The array of strings to implode.
If you don't specify the glue parameter in your implode() call, an empty string will be used. In this case, you need to glue the parts with |, so you need the following:
$newstring = implode('| ', $newstring);
echo $newstring; // => Hello | I'm john
However, I don't recommend editing values like this. Perhaps use an array instead?
You should be able to use a glue piece. simply by doing :
$foo = implode("|",$newstring);
The php implode function can be used with or without this glue piece.
php implode function
Edit values using implode or explode isn't a good idea, but you can achieve by this way
$newstring = implode('| ', $newstring);
You can pass a "glue" argument to implode(). (See the docs.)
$newstring = explode("|","Hello | I'm Ben");
$newstring[1] = "I'm john";
$newstring = implode("|", $newstring);
I have an array which I get from an exploded url (using $_GET).
The elements in the url are separated by commas but when I COUNT the elements the result includes the final comma. Eg: '?list=jonny,sally,bob,' returns '4' when '?list=jonny,sally,bob' returns '3'. I can't avoid the final comma as they are genrated with them automatically but I need to return 3 on both examples. Any ideas please?? Thanks
$list = explode(",", $_GET['list']);
$listCount = count($list);
//$listCount =(int)$listCount -1;
//$list[$listCount]=str_replace($list[$listCount],',','');
echo $listCount;
NB: the commented out lines are a failed attempt to remove the comma. But $list[$listCount] ,ie the final array element doesn't seem to exist even though it is counted
If you want to trim any extra commas at the start or end of the string, use trim(). If you want it at the end of the string, you can use rtrim().
$list = explode(",", $_GET['list']);
to
$list = explode(",", trim($_GET['list'], ','));
Trim any commas first:
$strList = rtrim($_GET['list'], ",")
$arrList = explode(",", $strList);
Array_filter will remove any empty values from your array, so in case you have two commas in a row, it will remove empty values caused by that also.
$list = array_filter(explode(",", $_GET['lists']));