I have created a project which allows logged in users to created posts. The post table has a column called post_id. The post_id has the value user id fetched from Session::get('id').
Now I want to fetch all posts associated with a loggedin user by using Post::where('post_id','=',Session::get('id');
Code Below
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
//use App\Models\User;
use App\Models\Post;
use Session;
class PostController extends Controller
{
public function post(Request $request){
$posts = Post::where('post_id','=',Session::get('id'));
return view('dashboard',['posts' => $posts]);
}
}
in web.php
use App\Http\Controllers\PostController;
Route::get('/dashaboard',[PostController::class,'post']);
in dashboard view
#foreach ($posts as $post)
<tr>
<td>{{$post->post_title}}</td>
<td>{{$post->post_description}}</td>
</tr>
#endforeach
The error is
Undefined variable $posts
I tried to fetch logged in User's posts. I want to fetch all posts.
A bit correction to eloquent query that you are using.
$user_id = Session::get('id');
// change post_id into user_id
// and add ->get() to fetch all posts related to user_id
$posts = Post::where('user_id','=', $user_id)->get();
And if the user has way to many posts, for example more than 25.
You can use pagination
$perPage = 25;
$posts = Post::where('user_id','=', $user_id)->paginate($perPage);
https://laravel.com/docs/9.x/pagination#paginating-eloquent-results
Btw there are other way to get user id as long as this user is logged in
$user_id = auth()->user()->id;
$user_id = $request->user()->id;
$user_id = auth()->id();
So your setup is a little confusing. Let me break down how you should actually set this up.
In your User model, you should define a relationship for posts:
public function posts() {
return $this->hasMany(Post::class);
}
In your Post model, you should define a relation for the user:
public function user() {
return $this->belongsTo(User::class);
}
In your posts database table, you'll want a user_id integer column which will store the post user id.
Once you've done this setup, you'll be able to get all of the currently logged in users posts like this:
public function post(Request $request){
$posts = $request->user()->posts;
return view('dashboard',['posts' => $posts]);
}
For getting logged in user id
use Auth;
$user_id = Auth::user()->id;
Related
I have a Many To Many relationship between User & Wallet Models:
Wallet.php:
public function users()
{
return $this->belongsToMany(User::class,'user_wallet','wallet_id','user_id')->withPivot('balance');
}
User.php:
public function wallets()
{
return $this->belongsToMany(Wallet::class,'user_wallet','user_id','wallet_id')->withPivot('balance');
}
And the pivot table user_wallet goes like this:
Then at the Controller, I need to access the balance field:
public function chargeWallet(Request $request, $wallet, $user)
{
// $wallet is wallet_id (2) & $user is user_id (373)
$bal = Wallet::with("users")
->whereHas('users', function ($query) use ($user) {
$query->where('id',$user);
})->where('id', $wallet)->first();
dd($bal->balance);
}
But now I get null as the result of dd($bal->balance) !!
So what is wrong here? How can I properly get the balance ?
Since it is a Many to Many relationships, you have Users attached to many Wallets, and Wallets attach to many Users. For each relation between a single Wallet and a single User: you have a pivot value (pivot relation). From your query, you'll retrieve Wallet with Users, each user's having the pivot relation value attached. So to retrieve the pivot table data (for each relation) you have to use a loop (added a with callback to make sure that only Users with matching user_id are eager loaded with the Wallets):
$bal = Wallet::with(["users"=>function ($query) use ($user) {
$query->where('user_id',$user);
}])
->whereHas('users', function ($query) use ($user) {
$query->where('user_id',$user);
})->find($wallet);
To avoid repeating same callback (where user_id =) you can assign it to variable:
$callback = function ($query) use ($user) {
$query->where('user_id',$user);
};
then use it in your query:
$bal = Wallet::with(['users' => $callback])
->whereHas('users', $callback)->find($wallet);
and then use a foreach loop:
foreach ($bal->users as $value){
dd($value->pivot->balance);
}
or
if you only want to return the pivot value for the first User of the first Wallet of your query, then:
$user = $bal->users->first();
dd($user->pivot->balance);
I have an user. User create many ads.I want to see users details with ads where ads shown by paginate. For this, i make two model(User & Ads)
public function user(){
return $this->hasOne(User::class, 'id', 'user_id');
}
public function ads(){
return $this->hasMany(Ads::class, 'user_id', 'id');
}
In controller i call like this:
$users = Ads::with(['user'=> function ($q) use ($id){
$q->where('id',$id);
}])->paginate(2);
But here user's details are shown when forelse loop are called. But i don't want this.
So, How can i get user's details with ads's pagination?
I think you're overcomplicating.
You has two models.
In User, you can put this relationship:
public function ads(){
return $this->hasMany(App\Ad, 'user_id', 'id');
}
In Ads model, you put this relationship:
public function user(){
return $this->belongsTo(App\User, 'id', 'user_id');
}
In your controller, you simple call like this:
//If you want a list of User's Ads
$user = User::find(1);
$userAds = $user->ads()->paginate(2); //you paginate because can be many
//If you want the details from a user who made the Ad #1
$ad = Ad::find(1);
$user = $ad->user; //Don't need paginate because is only one.
In my application, I have setup a User model that can have subscribers and subscriptions through a pivot table called subscriptions.
public function subscribers()
{
return $this->belongsToMany('Forum\User', 'subscriptions', 'subscription_id', 'subscriber_id');
}
public function subscriptions()
{
return $this->belongsToMany('Forum\User', 'subscriptions', 'subscriber_id', 'subscription_id');
}
My question is, what relationship should I use to get a list of paginated Post models (belong to a User) from the User's subscriptions?
You can use the whereHas method to filter based on relationships. Assuming your Post model has a user relationship defined, your code would look something like:
// target user
$user = \App\User::first();
$userId = $user->id;
// get all of the posts that belong to users that have your target user as a subscriber
\App\Post::whereHas('user.subscribers', function ($query) use ($userId) {
return $query->where('id', $userId);
})->paginate(10);
You can read more about querying relationship existence in the documentation.
You can do something like this
\App\Post::with(['subscriptions' => function ($query) {
$query->where('date', 'like', '%date%');
}])->paginate(15);
Or without any conditions
\App\Post::with('subscriptions')->paginate(15);
I would like to display the posts of everyone the current user follows, ordered by date desc.
I have a many to many relationship supplying all the people the user is following.
$users = User::find(Auth::user()->id)->follow()->get();
I have a one to many relationship displaying the posts for any user.
$updates = App\User::find(?????)->updates()->orderBy('created_at', 'desc')->get();
The question mark's shows where the followers ID's need to be placed.
I can put the above query inside the for each loop but that obviously works its way through each follower rather than all posts in date order.
I suspect I may need to set a new relationship and work from the beginning. Can anyone advise.
User Model
public function updates()
{
return $this->hasMany('App\update');
}
/**
* User following relationship
*/
// Get all users we are following
public function follow()
{
return $this->belongsToMany('App\User', 'user_follows', 'user_id', 'follow_id')->withTimestamps()->withPivot('id');;;
}
// This function allows us to get a list of users following us
public function followers()
{
return $this->belongsToMany('App\User', 'user_follows', 'follow_id', 'user_id')->withTimestamps();;
}
}
Update Model
public function user_update()
{
return $this->belongsTo('App\User');
}
Thank you.
Since you want the posts, it is probably going to be easier starting a query on the Post model, and then filter the posts based on their relationships.
Assuming your Post model has an author relationship to the User that created the post, and the User has a follower relationship to all the Users that are following it, you could do:
$userId = Auth::user()->id;
$posts = \App\Post::whereHas('author.follower', function ($q) use ($userId) {
return $q->where('id', $userId);
})
->latest() // built in helper method for orderBy('created_at', 'desc')
->get();
Now, $posts will be a collection of your Post models that were authored by a user that is being followed by your authenticated user.
In the documentation of Eloquent it is said that I can pass the keys of a desired relationship to hasManyThrough.
Lets say I have Models named Country, User, Post. A Country model might have many Posts through a Users model. That said I simply could call:
$this->hasManyThrough('Post', 'User', 'country_id', 'user_id');
This is fine so far! But how can I get these posts only for the user with the id of 3 ?
Can anybody help here?
So here it goes:
models: Country has many User has many Post
This allows us to use hasManyThrough like in your question:
// Country model
public function posts()
{
return $this->hasManyThrough('Post', 'User', 'country_id', 'user_id');
}
You want to get posts of a given user for this relation, so:
$country = Country::first();
$country->load(['posts' => function ($q) {
$q->where('user_id', '=', 3);
}]);
// or
$country->load(['posts' => function ($q) {
$q->has('user', function ($q) {
$q->where('users.id', '=', 3);
});
})
$country->posts; // collection of posts related to user with id 3
BUT it will be easier, more readable and more eloquent if you use this instead:
(since it has nothing to do with country when you are looking for the posts of user with id 3)
// User model
public function posts()
{
return $this->hasMany('Post');
}
// then
$user = User::find(3);
// lazy load
$user->load('posts');
// or use dynamic property
$user->posts; // it will load the posts automatically
// or eager load
$user = User::with('posts')->find(3);
$user->posts; // collection of posts for given user
To sum up: hasManyThrough is a way to get nested relation directly, ie. all the posts for given country, but rather not to search for specific through model.
$user_id = 3;
$country = Country::find($country_id);
$country->posts()->where('users.id', '=', $user_id)->get();
$this->hasManyThrough('Post', 'User', 'country_id', 'user_id')->where(column,x);
What happen here is you get the collection in return you can put any condition you want at the end.